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**Quadratic Word Problems WS 2 Solutions**

#1 10 inches #2 15 cm by 7 cm #3 a ft b sec c & 5.70 sec #4 72 units #5 96 cm #6 Height is 5.25 m or 5 m and 25 cm Distance is 3.79 meters or 3 m and 79 cm

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#1 2x + 15 2x + 20 ft x 12 in/ft About 10 inches

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**The dimensions of the rectangle are 15 cm by 7 cm**

#2 Perimeter = 44 cm Area = 105 sq. cm Width = W 2L + 2W = 44 L + W = 22 Length = L L = 22 - W The dimensions of the rectangle are 15 cm by 7 cm (L)(W) = 105 (22 - W)(W) = 105 22W – W2 = 105 W2 – 22W = 0 (W - 15)(W - 7) = 105

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#3a h = -16t t First find Axis of Symmetry Plug it in to get the vertex Solving for h will give the maximum point (or highest point)

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#3b h = -16t t Two ways to solve … Why does this work? Alternate solution 0 = -16t t 0 = -4t(4t – 25) t = 0 or 6.25

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#3c h = -16t t 50 = -16t t 16t t + 50 = 0 8t2 - 50t + 25 = 0

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#4 x x x + 6 x + 9

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**Width = w Length = 3w Volume = L x W x H 512 = (3w - 4)(w - 4)(2)**

Perimeter = 96 cm 256 = 3w2 – 16w + 16 0 = 3w2 – 16w - 240 0 = (w – 12)(3w + 20) Width = 12 cm

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**#6 Mr. Lomas (at least the way I remember me) ….**

Maximum height (at vertex) height when I hit the water? 3 meters Distance from board when entering water?

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Maximum height of 525 cm

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#7 Equation: y = x2 - 10x + 15 Direct: Up Width: Standard L of S: x = 5 Vertex: (5, -10) y-int: (0, 15) Roots:

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#8 Equation: y = -2x2 + 8 Direct: Down Width: Narrow L of S: x = 0 Vertex: (0, 8) y-int: (0, 8) Roots: 2 or -2

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#9 Equation: y = (1/4)x2 - 2x - 5 Direct: Up Width: Wide L of S: x = 4 Vertex: (4, -9) y-int: (0, -5) Roots: 10 or -2

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Applications Involving Rational Equations Sec. 2.8b.

Applications Involving Rational Equations Sec. 2.8b.

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