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Colligative Properties Kausar Ahmad Kulliyyah of Pharmacy 1PHM1153 Physical Pharmacy 1 2010/11.

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Presentation on theme: "Colligative Properties Kausar Ahmad Kulliyyah of Pharmacy 1PHM1153 Physical Pharmacy 1 2010/11."— Presentation transcript:

1 Colligative Properties Kausar Ahmad Kulliyyah of Pharmacy 1PHM1153 Physical Pharmacy /11

2 Contents Effect of solute on vapour pressure Boiling point elevation Freezing point depression Osmotic pressure Lecture 1 Raoults law Deviation from Raoults law Lecture 2 Distillation Azeotropic mixtures Clausius-Clapeyron equation Lecture 3 PHM1153 Physical Pharmacy /112

3 Introduction Solutions have different properties than either the pure solvent or the solute. a solution of sugar in water is neither crystalline like sugar nor tasteless like water. Some of the properties unique to solutions depend only on the number of dissolved particles and not their identity. 3PHM1153 Physical Pharmacy /11

4 Definition Properties of a liquid that may be altered by the presence of a solute. Depend only on the amount of solute in a solution Does not depend on the identity of the solute Colligative properties Depend on the identity of the dissolved solute and the solvent Non-colligative properties 4PHM1153 Physical Pharmacy /11

5 Colligative vs Non-colligative 5 Compare 1.0 M aqueous sugar solution to a 0.5 M solution of salt (NaCl) in water. both solutions have the same number of dissolved particles any difference in the properties of those two solutions is due to a non-colligative property. Both have the same freezing point, boiling point, vapor pressure, and osmotic pressure PHM1153 Physical Pharmacy /11

6 Non-Colligative Properties Sugar solution is sweet and salt solution is salty. Therefore, the taste of the solution is not a colligative property. Another non-colligative property is the color of a solution. A 0.5 M solution of CuSO4 is bright blue in contrast to the colorless salt and sugar solutions. Other non-colligative properties include viscosity, surface tension, and solubility. 6PHM1153 Physical Pharmacy /11

7 Examples of Colligative Properties vapour pressure freezing point depression (melting) boiling point elevation osmotic pressure 7 All of these properties relate to the vapor pressure. PHM1153 Physical Pharmacy /11

8 Effect of Solute on Vapour Pressure When a nonvolatile solute is dissolved in a solvent, the vapor pressure of the resulting solution is lower than that of the pure solvent. The amount of the vapor pressure lowering is proportional to the amount of solute and not its identity. Therefore, vapor pressure lowering is a colligative property. 8PHM1153 Physical Pharmacy /11

9 Vapour pressure: Solution < pure solvent PHM1153 Physical Pharmacy /119

10 Boiling point Boiling point elevation is a colligative property related to vapor pressure lowering. The boiling point is defined as the temperature at which the vapor pressure of a liquid equals the atmospheric pressure. Due to vapor pressure lowering, a solution will require a higher temperature to reach its boiling point than the pure solvent. 10PHM1153 Physical Pharmacy /11

11 Freezing Point Every liquid has a freezing point - the temperature at which a liquid undergoes a phase change from liquid to solid. When solutes are added to a liquid, forming a solution, the solute molecules disrupt the formation of crystals of the solvent. That disruption in the freezing process results in a depression of the freezing point for the solution relative to the pure solvent. 11PHM1153 Physical Pharmacy /11

12 Osmotic Pressure When a solution is separated from a volume of pure solvent by a semi-permeable membrane that allows only the passage of solvent molecules, the height of the solution begins to rise. The value of the height difference between the two compartments reflects a property called the osmotic pressure of a solution. PHM1153 Physical Pharmacy /1112

13 PHM1153 Physical Pharmacy /1113 Phase Diagrams and the effect of solutes on freezing and boiling points

14 14PHM1153 Physical Pharmacy /11 end of lecture 1/3

15 Raoult's Law Raoult's law states that the vapor pressure of a solution, P 1, equals the mole fraction of the solvent, X 1, multiplied by the vapor pressure of the pure solvent, P o. P 1 = P o x X 1 15PHM1153 Physical Pharmacy /11

16 A Visual Demonstration of Raoult's Law Description: The intensity of color of bromine vapor is reduced (P) when a colorless volatile liquid is added (x). Source: Journal of Chemical Education - Vol. 67 Year : 1990 page: PHM1153 Physical Pharmacy /11

17 Total Vapour Pressure P = p1 +p2 In an ideal solution made up of two volatile components: P = p1 In an ideal solution made up of one volatile component: 17PHM1153 Physical Pharmacy /11

18 Ideal & Non-Ideal/Real Solutions Solutions that obey Raoult's law are called ideal solutions because they behave exactly as we would predict. Solutions that show a deviation from Raoult's law are called non-ideal solutions or real solutions because they deviate from the expected behavior. 18PHM1153 Physical Pharmacy /11

19 Deviations from Raoult's law the "law" is approximately obeyed by most solutions, some show deviations from the expected behavior. Deviations from Raoult's law can either be positive or negative. – A positive deviation means that there is a higher than expected vapor pressure above the solution: P 1 > P 1 o x X 1 – A negative deviation means that we find a lower than expected vapor pressure for the solution: P 1 < P 1 o x X 1 19PHM1153 Physical Pharmacy /11

20 Reason for the deviation In vapor pressure lowering we assumed that the solute did not interact with the solvent at all. If the solute is strongly held by the solvent, the solution will show a negative deviation from Raoult's law, because the solvent will find it more difficult to escape from solution. If the solute and solvent are not as tightly bound to each other as they are to themselves, then the solution will show a positive deviation from Raoult's law because the solvent molecules will find it easier to escape from solution into the gas phase. 20PHM1153 Physical Pharmacy /11

21 21 Deviation from Raoults Law PHM1153 Physical Pharmacy /11

22 Vapor Pressure of a Mixture: Raoult's Law The measurement of pressure exerted by a vapour is demonstrated using barometers. Vapor pressure varies with the strength of the intermolecular forces in the liquid. We can calculate the vapor pressure of a mixture using Raoult's law. PHM1153 Physical Pharmacy /1122 Source: Harrison/Manometer/Manometer.html Harrison/Manometer/Manometer.html

23 23 Example: Consider a solution that contains 0.6 mole fraction of decane and 0.4 mole fraction of diethyl ether. We can calculate the vapor pressure of a mixture using Raoult's law: P = P 1 o x X 1 + P 2 o x X 2 = (5 x 0.6) + (460 x 0.4) = 187 PHM1153 Physical Pharmacy /11

24 Factors that affect the magnitude of the changes in melting point and boiling point. ConcentrationEffect of ionic compounds 24PHM1153 Physical Pharmacy /11

25 Effect of ionic compounds 0.1 mole of an ionic compound such as NaCl,, has an effect on the melting and boiling points that is almost twice what we would observe for 0.1 mole sugar. – salt ionizes into Na + and Cl - ions in water – these ions act as independent particles on the vapor pressure of water. – Thus NaCl, NaNO 3, and CaCO 3 would have multipliers of 2, while Na 2 SO 4, and CaCl 2 would have multipliers of 3. 25PHM1153 Physical Pharmacy /11

26 Vant Hoff factor In dilute solutions, ionic compounds have simple multiple effects, but as the solution concentration increases the multiplier effect diminishes. This phenomenon was first discovered by van't Hoff and is generally called the van't Hoff factor. As concentration increases, some of the ions floating in solution find one another and form ion pairs, in which two oppositely charged ions briefly stick together and act as a single particle. the higher the concentration, the more likely it is that two ions will find one another. 26PHM1153 Physical Pharmacy /11

27 27PHM1153 Physical Pharmacy /11

28 Change in Boiling Point One consequence of Raoult's law is that the boiling point of a solution made of a liquid solvent with a nonvolatile solute is greater than the boiling point of the pure solvent. For a solution, the vapor pressure of the solvent is lower at any given temperature. Therefore, a higher temperature is required to boil the solution than the pure solvent. The change in boiling point is ΔT b = iK b m 28PHM1153 Physical Pharmacy /11

29 because molality is temperature independent. m is molality that depends on the particular solvent used. Kb is a boiling point elevation constant number of dissociated moles of particles per mole of solute. i=1 for all non-electrolyte solutes and equals the total number of ions released for electrolytes. Na 2 SO 4 is 3 because that salt releases three moles of ions per mole of the salt. i is the van't Hoff factor 29PHM1153 Physical Pharmacy /11 ΔT b = iK b m

30 Change in Freezing Point In order for a liquid to freeze it must achieve a very ordered state that results in the formation of a crystal. If there are impurities in the liquid, i.e. solutes, the liquid is inherently less ordered. Therefore, a solution is more difficult to freeze than the pure solvent so a lower temperature is required to freeze the liquid. The change in freezing point is ΔT f = -iK f m – Note that the sign of the change in freezing point is negative because the freezing point of the solution is less than that of the pure solvent. 30PHM1153 Physical Pharmacy /11

31 31 Molal Boiling Point Elevation and Freezing Point Depression Constants at 1 Atm pressure Compound Normal bp K b ( o C/m) Normal fp K f ( o C/m) Water, H 2 O Benzene, C 6 H Ethanol, C 2 H 5 OH Carbon tetrachloride, CCl Chloroform, CHCl Thus the boiling point of water would increase 0.52 o C for a one molal solution, while the freezing point of this solution would decrease by 1.86 o C. PHM1153 Physical Pharmacy /11

32 Osmotic pressure Solvent molecules flow into solutionVolume of the solution rise Net flow through the membrane ceases due to the extra pressure exerted by the excess height of the solution chamber. Converting the difference in height into pressure gives the osmotic pressure P = ρgh PHM1153 Physical Pharmacy /1132

33 Effect of concentration on osmotic pressure PV = inRT Since n / V gives the concentration of the solute in units of molarity, M P = iMRT 33 End of lecture 2/3 PHM1153 Physical Pharmacy /11

34 Application of Raoults Law Distillation 34PHM1153 Physical Pharmacy /11

35 DISTILLATION 35 Distillation is the process of boiling & condensing the vapour back to liquid A simple distillation: To change from liquid to vapour by boiling To change from vapour to liquid by condensing PHM1153 Physical Pharmacy /11

36 Distillation of Binary Mixture Ideal Solution When a liquid and its vapour are in equilibrium, vapour is richer in the more volatile component compared to liquid mixture At equilibrium, liquid and vapour phase can be separated and analysed 36PHM1153 Physical Pharmacy /11

37 Binary Mixtures Obeying Raoults Law Ideal Solution Attractive forces between molecules of different component equal those of the same component. A-B = A-A = B-B – Without a maximum or minimum at intermediate compositions. No change in properties of components (except dilution to form solution). Vapour pressure, refractive index, surface tension and viscosity of solution are averages of properties of pure individual constituents. No heat evolved or absorbed during mixing process. No change in solution temperature. No shrinkage or expansion. Final properties of solution are additive properties of individual constituents. E.g. methyl alcohol-water, benzene-toluene, methanol-ethanol. 37PHM1153 Physical Pharmacy /11

38 Definition - Azeotropic Mixture Describes a mixture of miscible liquids which boils at a constant composition and thus the composition cannot be changed by simple distillation Composition of vapour similar to that of liquid The composition as well as the boiling point of an azeotropic mixture changes with pressure If a liquid mixture represented by a composition X1 is distilled, the vapour has composition X2 and condenses to form a liquid of that composition. Distillation starting at composition X1 produces an azeotropic mixture Z as the distillate, and the residue tends towards pure B Similarly, a mixture of composition Y1, yields an azeotropic mixture as distillate, and pure A as a residue 38PHM1153 Physical Pharmacy /11

39 Positive Deviation from Raoults Law Vapour pressure greater than expected from Raoults law.The two components differ in properties e.g. polarityAttractive forces: A-B < A-A or B-B Escaping tendency higher A max is found in vapour pressure-composition curvePresence of azeotropic mixtures lead to min boiling point Examples: 1. ethyl, isopropyl, n-propyl alcohol - water, 2. volatile drug (methyl amphetamine) chloroform - ethanol 39PHM1153 Physical Pharmacy /11

40 Positively deviated solution mixture with a minimum boiling point The mixture shows positive deviation from Raoults law A minimum boiling point is obtained The solution has an azeotropic mixture whose vapour pressure is the highest and boiling point is the lowest example of a positive azeotrope is 95.6% ethanol and 4.4% water (by weight). Ethanol boils at 78.4°C, water boils at 100°C, but the azeotrope boils at 78.1°Cethanol 40PHM1153 Physical Pharmacy /11

41 Distillation of positive azeotrope 95.6% ethanol and 4.4% waterethanol distillation of any mixture will result in the distillate being closer in composition to the azeotrope than the starting mixture.distillate E.g. if a 50/50 mixture of ethanol and water is distilled once, the distillate will be 80% ethanol and 20% water i.e. closer to the azeotropic mixture than the original. Distilling the 80/20% mixture produces a distillate that is 87% ethanol and 13% water. Further repeated distillations will produce mixtures that are progressively closer to the azeotropic ratio of 95.5/4.5%. increasing distillations will not give distillate that exceeds the azeotropic ratio. 41PHM1153 Physical Pharmacy /11

42 Negative Deviation from Raoults Law Vapour pressure of solution less than that expected from Raoults lawAttractive forces: A-B > A-A or B-B Escaping tendency lower A min is found in vapour pressure – composition curvePresence of azeotropic mixtures lead to max boiling point E.g. pyridine-acetic acid, chloroform-acetone (formation of loose compounds from hydrogen bonding), formation of hydrates, nitric acid-water, sulfuric acid-water. 42PHM1153 Physical Pharmacy /11

43 Negatively deviated solution with maximum boiling point Mixtures showing negative deviation from Raoults law A maximum boiling point is obtained The solution has an azeotropic mixture whose vapour pressure is the lowest and the boiling point is the highest example of a negative azeotrope is 20.2% hydrogen chloride and 79.8% water (by weight). Hydrogen chloride boils at –84°C and water at 100°C, but the azeotrope boils at 110°Chydrogen chloride 43PHM1153 Physical Pharmacy /11

44 Distillation of negative azeotrope 20.2% hydrogen chloride and 79.8% waterhydrogen chloride distillation of any mixture of those constituents will result in the residue being closer in composition to the azeotrope than the original mixture. residue E.g. hydrochloric acid solution contains less than 20.2% hydrogen chloride,hydrochloric acidhydrogen chloride boiling the mixture will give a solution that is richer in hydrogen chloride than the original. If the solution initially contains more than 20.2% hydrogen chloride, boiling will give a solution that is poorer in hydrogen chloride than the original. Boiling of any hydrochloric acid solution long enough will cause the solution left behind to approach the azeotropic ratio. 44PHM1153 Physical Pharmacy /11

45 Application of Raoults Law in Aerosol Formulation As pressure increases, spray rate increases -> fine spray, propellant gas vapourises fast As pressure decreases, spray rate decreases -> coarse spray, propellant gas vapourises slowly -> wet Vapour pressure of propellant control the spray Examples of components: HFA-125: pentafluoroethane CHCF 5 HFC-134a: tetrafluoroethane CHCHF 4 HFA-152: difluoroethane CH 3 CHF 2 HFA-227: heptafluoropropane CHFCF 3 CF 3 Thus, improvise by using appropriate mixture of propellant 45PHM1153 Physical Pharmacy /11

46 Exercise: Application of Raoults Law in Aerosol Formulation The vapour pressure of pure propellant 11 (MW 137.4) at 21 o C is P 11 0 = 13.4 psi The vapour pressure of pure propellant 12 (MW 120.9) at 21 o C is P 12 0 = 84.9 psi A total of 100 g propellants consisting of 50:50 mixture by gram weight was used. What is the total vapour pressure? 46PHM1153 Physical Pharmacy /11

47 Variation of Vapour Pressure with Temperature 47 As T, energy of molecules More escape into vapour phase increase in vapour pressure Clausius- Clapeyron Equation PHM1153 Physical Pharmacy /11

48 Clausius-Clapeyron Equation The variation of vapour pressure with temperature in terms of molar enthalpy of the liquid, H vap V is the difference in molar volume of the two phases Since molar volume of vapour is very much greater than the molar volume of liquid, V approaches volume of vapour, Vv 48 Assuming that the vapour obeys ideal gas behaviour, PV = RT V = RT/P Thus, Vv = RT/P The equation becomes Assuming H vap to be constant: PHM1153 Physical Pharmacy /11

49 Application of Clausius-Clapeyron Equation To estimate vapour pressure at any temperature. To calculate enthalpy of vaporisation based on the slope of plot To study phase transition – important to determine the extent of weight loss during processing or testing. End lecture 3/3 49PHM1153 Physical Pharmacy /11

50 References The required texts you shall seek, The recommended ones you may flirt, Revise! Revise! Youd better be quick! When you get your grades you wont be hurt! 50PHM1153 Physical Pharmacy /11

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