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1.0Device for Current Measurement 1.1 Analog ammeter 1.2 Galvanometer 2.0Device for Voltage Measurement 2.1 Analog voltmeter 2.2 Oscilloscope 2.3 Potentiometer.

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Presentation on theme: "1.0Device for Current Measurement 1.1 Analog ammeter 1.2 Galvanometer 2.0Device for Voltage Measurement 2.1 Analog voltmeter 2.2 Oscilloscope 2.3 Potentiometer."— Presentation transcript:



3 1.0Device for Current Measurement 1.1 Analog ammeter 1.2 Galvanometer 2.0Device for Voltage Measurement 2.1 Analog voltmeter 2.2 Oscilloscope 2.3 Potentiometer 3.0Device for Resistance Measurement 3.1 Ohmmeter 3.2 Wheatstone bridge circuit 4.0 Digital Multimeter


5 A voltmeter is an instrument used for measuring the potential difference between two points in an electric circuit.

6 A voltmeter is placed in parallel with a circuit element to measure the voltage drop across it and must be designed to draw very little current from the circuit so that it does not appreciably change the circuit it is measuring. To accomplish this, a large resistor is placed in series with the galvanometer. Its value is chosen so that the design voltage placed across the meter will cause the meter to deflect to its full-scale reading. A galvanometer full-scale current is very small: on the order of milliamperes.

7 The moving coil galvanometer is one example of this type of voltmeter. It employs a small coil of fine wire suspended in a strong magnetic field. When an electrical current is applied, the galvanometer's indicator rotates and compresses a small spring. The angular rotation is proportional to the current that is flowing through the coil. For use as a voltmeter, a series resistance is added so that the angular rotation becomes proportional to the applied voltage.

8 8 The basic dÁrsonval meter movement can be converted to a dc voltmeter by connecting a multiplier R s in series with the meter movement The purpose of the multiplier: is to extend the voltage range of the meter to limit current through the dArsonval meter movement to a maximum full-scale deflection current. Fig 2-1 The basic dArsonval meter Movement Used In A DC Voltmeter

9 9 To find the value of the multiplier resistor, first determine the sensitivity, S, of the meter movement.

10 10 Calculate the value of the multiplier resistance on the 50V range of a dc voltmeter that used a 500 A meter movement with an internal resistance of 1k.

11 11 Sensitivity, Multiplier, R s = S X Range – internal Resistance = (2k X 50) – 1k = 99k

12 12 When a voltmeter is used to measure the voltage across a circuit component, the voltmeter circuit itself is in parallel with the circuit component. Since the parallel combination of two resistors is less than either resistor alone, the resistance seen by the source is less with the voltmeter connected than without. Therefore, the voltage across the component is less whenever the voltmeter is connected. The decrease in voltage may be negligible or it may be appreciable, depending on the sensitivity of the voltmeter being used. This effect is called voltmeter loading. The resulting error is called a loading error.

13 13 Two different voltmeters are used to measure the voltage across resistor R B in the circuit of Figure 2-2. The meters are as follows. Meter A: S = 1k /V, Rm = 0.2k, range = 10V Meter B: S = 20k /V, Rm = 1.5k, range=10V Calculate: (a) Voltage across R B without any meter connected across it. (b) Voltage across R B when meter A is used. (c) Voltage across R B when meter B is used (d) Error in voltmeter readings. Fig. 2.2

14 14 (a) The voltage across resistor R B without either meter connected is found Using the voltage divider equation:

15 15 (b) starting with meter A, the total resistance it presents to the circuit is The parallel combination of RB and meter A is Therefore, the voltage reading obtained with meter A, determined by the voltage divider equation, is

16 16 (c) The total resistance that meter B presents to the circuit is R TB = S x Range = 20k/V x 10 V = 200 k The parallel combination of R B and meter B is R e2 = (R B x R TB )/(R B + R TB ) = (5kx200k)/(5k+200k) = 4.88 k Therefore, the voltage reading obtained with meter B, determined by use of the voltage divider equation, is V RB = E(R e2 )/(R e2 +R A ) = 30 V x (4.88k)/(4.88k+25k) = 4.9 V

17 17 (d) Voltmeter A error = (5 V – 3.53 V)/5 V x (100% = 29.4% Voltmeter B error = (5 V – 4.9 V)/5 V x (100%) = 2 %

18 18 Five principal meter movements used in ac instrument 1. Electrodynamometer 2. Iron Vane 3. Electrostatic 4. Thermocouple 5. DArsonval with rectifier

19 19 Meter Movement DC UseAC UseApplications ElectrodynamometerYES Standards meter, wattmeter, frequency meter Indicator applications such as in automobiles Iron VaneYES Indicator applications such as in automobiles ElectrostaticYES Measurement of high voltage when very little current can be supplied by the circuit being measured ThermocoupleYES Measurement of radio frequency ac signal DArsonvalYESYES with rectifier Most widely used meter movement for measuring direct current or voltage and resistance

20 20 The PMMC instrument is polarized (terminals +ve & - ve) - it must be connected correctly for positive (on scale) deflection to occur. When an AC with a very low frequency is passed through a PMMC, the pointer tends to follow the instantaneous level of the AC As the current grows positively, the pointer deflection increases to a maximum at the peak of the AC As the instantaneous current level falls, the pointer deflection decreases toward zero. When the AC goes negative, the pointer deflected (off scale) to the left of zero This kind of pointer movement can occur only with AC having a frequency of perhaps 0.1Hz or lower

21 21 At 50Hz or higher supply frequencies - the damping mechanism of the instrument and the inertia of the meter movement prevent the pointer from following the changing instantaneous levels. The average value of purely sinusoidal AC is zero. Therefore, a PMMC instrument connected directly to measure 50Hz AC indicates zero average value. It is important to note that although a PMMC instrument connected to an ac supply may indicating zero, there can actually be very large rms current flowing in its coils

22 22 1. Half wave rectification 2. Full wave rectification Two types of PMMC meter used in AC measurement :

23 23 To convert alternating current (AC) to unidirectional current flow, which produces positive deflection when passed through a PMMC, the diode rectifier is used. Several types of rectifiers are selected such as a copper oxide rectifier, a vacuum diode, or semiconductor or crystal diode.

24 24 For example, if the output voltage from a half wave rectifier is 10V rms so the dc voltmeter will provide an indication of approximately 4.5V dc Therefore, the pointer deflected full scale when 10V dc signal is applied. When we apply a 10Vrms sinusoidal AC waveform, the pointer will deflect to 4.5V This means that the AC voltmeter is not as sensitive as DC voltmeter. In fact, an AC voltmeter using half wave rectification is only approximately 45% as sensitive as a dc voltmeter. Cont…

25 25 Actually, the circuit would probably be designed for full- scale deflection with a 10V rms AC applied, which means the multiplier resistor would be only 45% of the value of the multiplier resistor for 10V dc voltmeter. Since we have seen that the equivalent dc voltage is equal to 45% of the rms value of the ac voltage. Cont… S ac = 0.45S dc

26 26 Commercially produced ac voltmeters that use half wave rectification also has an additional diode and a shunt as shown in Figure below: Cont..

27 27 The additional diode D2 is reverse biased on the positive half cycle and has virtually no effect on the behavior of the circuit. In the negative half cycle, D2 is forward biased and provides an alternate path for reverse biased leakage current that would normally through the meter movement and diode D1. The purpose of the shunt resistor R sh is to increase the current flow through D1 during positive half cycle so that the diode is operating in a more linear portion of its characteristic curve. Although this shunt resistor improves the linearity of the meter on its low voltage ac ranges, it also further reduces the AC sensitivity. Cont…

28 28 Compute the value of the multiplier resistor for a 15Vrms ac range on the voltmeter shown in Fig. 1. Fig. 1: AC voltmeter using half wave rectification RSRS E in = 15V rms I fs = 1mA R m = 300Ω

29 29 Method 1 The sensitivity of the meter movement, R s = S dc × Range dc – R m = 1k × - R m = 1k × 0.45(10) – 300 = 4.2k

30 30 Method 2 The AC sensitivity for half wave rectifier, S ac = 0.45S dc = 0.45(1k) = 450 /V R s = S ac × Range ac – R m = 450 × 10 –300 = 4.2k

31 31 Rs=Rs= = 4.2k = Method 3

32 32 Calculate the ac and dc sensitivity and the value of the multiplier resistor required to limit the full scale deflection current in the circuit shown in Fig above.

33 33 DArsonval meter movement used with full wave rectification Fig. 2: Full bridge rectifier used in an ac voltmeter circuit During the positive half cycle, currents flows through diode D2, through the meter movement from positive to negative, and through diode D3. The polarities in circles on the transformer secondary are for the positive half cycle. Since current flows through the meter movement on both half cycles, we can expect the deflection of the pointer to be greater than with the half wave cycle, which allows current to flow only on every other half cycle; if the deflection remains the same, the instrument using full wave rectification will have a greater sensitivity.

34 34 Fig. 1-2: AC voltmeter using full wave rectification

35 35 When the 10Vrms of AC signal is applied to the circuit above, where the peak value of the AC input signal is And the average full wave output signal is Therefore, we can see that a 10Vrms voltage is equivalent to 9Vdc for full-scale deflection.

36 36 S ac = 0.9 S dc Or This means an ac voltmeter using full wave rectification has a sensitivity equal to 90% of the dc sensitivity

37 37 Compute the value of the multiplier resistor for a 10V rms ac range on the voltmeter in Figure 1-2. Fig. 1-2: AC voltmeter circuit using full wave rectification

38 38 The dc sensitivity is The ac sensitivity is S ac = 0.9S dc = 0.9 (1k) = 900 /V

39 39 Therefore the multiplier resistor is R s = S ac x Range – R m = 900 x 10V rms – 500 = 8.5k

40 40 Note: Voltmeters using half wave and full wave rectification are suitable for measuring only sinusoidal ac voltages.

41 An oscilloscope is a piece of electronic test equipment that allows signal voltages to be viewed, usually as a two- dimensional graph of one or more electrical potential differences (vertical axis) plotted as a function of time or of some other voltage (horizontal axis electronic test equipmentpotential differences Perform some computations using data taken from the voltage waveform that is displayed such as: * Rms value * Average Amplitude * Peak-to-peak Amplitude * Frequency

42 An oscilloscope is easily the most useful instrument available for testing circuits because it allows you to see the signals at different points in the circuit. Using for signal/wave display – Winamp Music Player, Electrocardiogram,

43 A potentiometer is a variable resistor that functions as a voltage divider It is a simple electro-mechanical transducer It converts rotary or linear motion from the operator into a change of resistance, and this change is (or can be) used to control any volume.

44 Schematic symbol for a potentiometer. The arrow represents the moving terminal, called the wiper. Usually, this is a three-terminal resistor with a sliding contact in the center (the wiper) - user-adjustable resistanceresistance If all three terminals are used, it can act as a variable voltage divider voltage divider If only two terminals are used (one side and the wiper), it acts as a variable resistor

45 Any current flow through the Galvanometer, G, wpuld be a result of an imbalance in the measured voltage, V m and the voltage imposed across points A to B, V AB. If V m is not equal to V AB, a current will flow through the galvanometer, G. Galvanometer detects current flow due to imbalance in voltage V m and V AB. When V m = V AB, there is a balance and no current, means no displacement in Galvanometer.

46 In modern usage, a potentiometer is a potential divider, a three terminal resistor where the position of the sliding connection is user adjustable via a knob or slider. For instance, when attached to a volume control, the knob can also function as an on/off switch at the lowest volumepotential dividerresistor Potentiometers are frequently used to adjust the level of analog signals (e.g. volume controls on audio equipment) and as control inputs for electronic circuits (e.g. a typical domestic light dimmer).volumeaudio equipment


48 The purpose of an ohmmeter, is to measure the resistance placed between its leads. This resistance reading is indicated through a mechanical meter movement which operates on electric current. The ohmmeter must then have an internal source of voltage to create the necessary current to operate the movement, and also have appropriate ranging resistors to allow just the right amount of current through the movement at any given resistance.

49 The original design of an ohmmeter provided a small battery to apply a voltage to a resistance. It used a galvanometer to measure the electric current through the resistance.voltage galvanometercurrent The scale of the galvanometer was marked in ohms, because the fixed voltage from the battery assured that as resistance decreased, the current through the meter would increase. A more accurate type of ohmmeter has an electronic circuit that passes a constant current I through the resistance, and another circuit that measures the voltage V across the resistance.

50 The standard way to measure resistance in ohms is to supply a constant voltage to the resistance and measure the current through it. That current is of course inversely proportional to the resistance according to Ohm's law, so that you have a non- linear scale.Ohm's law The current registered by the current sensing element is proportional to 1/R, so that a large current implies a small resistance.

51 51 The ohmmeter consists of battery, resistor and PMMC. Fig. 2-7 Basic ohmmeter circuit function of R z and R m are to limit the current through the meter The full-scale deflection current,

52 52 To determine the value of unknown resistor, R x, The R x is connected to terminal X and Y. Fig 2-8 shows the basic ohmmeter circuit with unknown resistor, R x connected between probes. Fig. 2-8 Basic ohmmeter circuit with unknown resistor,R x connected between probes. R z = variable resistor

53 53 The circuit current, The ratio of the current, I to the full-scale deflection current, I fs is

54 A Wheatstone bridge is a measuring instrument invented by Samuel Hunter Christie (British scientist & mathematician) in 1833 and improved and popularized by Sir Charles Wheatstone in 1843. It is used to measure an unknown electrical resistance by balancing two legs of a bridge circuit, one leg of which includes the unknown component. Its operation is similar to the original potentiometer except that in potentiometer circuits the meter used is a sensitive galvanometer. Sir Charles Wheatstone (1802 – 1875) Accurately measures resistance and detect small changes in resistance.

55 Basic dc bridge used for accurate measurement of resistance: Fig. 5.1: Wheatstone bridge circuit Definition: Basic circuit configuration consists of two parallel resistance branches with each branch containing two series elements (resistors). To measure instruments or control instruments

56 The dc source, E is connected across the resistance network to provide a source of current through the resistance network. The sensitive current indicating meter or null detector usually a galvanometer is connected between the parallel branches to detect a condition of balance. When there is no current through the meter, the galvanometer pointer rests at 0 (midscale). Current in one direction causes the pointer to deflect on one side and current in the opposite direction to otherwise. The bridge is balanced when there is no current through the galvanometer or the potential across the galvanometer is zero.

57 At balance condition; (1) Voltage drop across R3 and R4 is equal I 3 R 3 = I 4 R 4 (2) No current flows through galvanometer G when the bridge is balance, therefore: I 1 = I 3 and I 2 =I 4 (3) voltage across R1 and R2 also equal, therefore

58 Cont. Substitute (3) in Eq (2), I 1 R 3 = I 2 R 4 (4) Eq (4) devide Eq (1) R 1 /R 3 = R 2 /R 4 Then rewritten as R 1 R 4 = R 2 R 3 (5)

59 Figure 5.2 consists of the following, R 1 = 12k, R 2 = 15 k, R 3 = 32 k. Find the unknown resistance R x. Assume a null exists(current through the galvanometer is zero). Fig. 5-2: Circuit For example 5-1

60 R x R 1 = R 2 R 3 R x = R 2 R 3 /R 1 = (15 x 32)/12 k, R x = 40 k

61 When the bridge is in unbalanced condition, current flows through the galvanometer, causing a deflection of its pointer. The amount of deflection is a function of the sensitivity of the galvanometer.

62 Deflection may be expressed in linear or angular units of measure, and sensitivity can be expressed: Total deflection,

63 V th = E ab R th = R 1 //R 3 + R 2 //R 4 = R 1 R 3 /(R 1 + R 3 ) + R 2 R 4 (R 2 +R 4 ) Fig. 5-3: Unbalanced Wheatstone BridgeFig. 5-4: Thevenins resistance

64 An analytical tool used to extensively analyze an unbalance bridge. Thévenin's theorem for electrical networks states that any combination of voltage sources and resistors with two terminals is electrically equivalent to a single voltage source V and a single series resistor R. For single frequency AC systems the theorem can also be applied to general impedances, not just resistors. The theorem was first discovered by German physicist Hermann von Helmholtz in 1853, but was then rediscovered in 1883 by French telegraph engineer Léon Charles Thévenin (1857-1926). Hermann von Helmholtz (1821 – 1894) Léon Charles Thévenin (1857-1926) German Physicist French Engineer

65 If a galvanometer is connected to terminal a and b, the deflection current in the galvanometer is where R g = the internal resistance in the galvanometer

66 R 2 = 1.5 kΩ R 1 = 1.5 kΩ R3 = 3 kΩ R4 = 7.8 kΩ R g = 150 Ω E= 6 V Figure 5.5: Unbalance Wheatstone Bridge Calculate the current through the galvanometer ?

67 Slightly Unbalanced Wheatstone Bridge If three of the four resistors in a bridge are equal to R and the fourth differs by 5% or less, we can developed an approximate but accurate expression for Thevenins equivalent voltage and resistance.

68 Cont.. To find R th : An approximate Thevenins equivalent circuit

69 10 V 500 Ω 525 Ω 500 Ω Use the approximation equation to calculate the current through the galvanometer in Figure above. The galvanometer resistance, Rg is 125 Ω and is a center zero 200-0-200-μA movement.

70 The Kelvin Bridge is a modified version of the Wheatstone bridge. The purpose of the modification is to eliminate the effects of contact and lead resistance when measuring unknown low resistances. Used to measure values of resistance below 1 Ω.


72 It can be shown that, when a null exists, the value for R x is the same as that for the Wheatstone bridge, which is Therefore when a Kelvin Bridge is balanced

73 If in Figure 5-6, the ratio of R a and R b is 1000, R 1 is 5 and R 1 =0.5R 2. What is the value of R x.

74 The resistance of R x can be calculated by using the equation, R x /R 2 =R 3 /5 =1/1000 Since R 1 =0.5R 2, the value of R 2 is calculated as R 2 =R 1 /0.5=5 /0.5=10 So, R x =R 2 (1/1000)=10 x (1/1000)=0.01

75 A multimeter or a multitester is an electronic measuring instrument that combines several functions in one unit.electronic measuring instrument The most basic instruments include an ammeter, voltmeter, and ohmmeter ammetervoltmeter ohmmeter

76 DC Voltage Measurements AC Voltage RMS Measurements DC and AC Current Measurements Resistance Measurements Capacitance/Inductance Measurements Frequency/Period Measurements Diode Measurements


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