Download presentation

Presentation is loading. Please wait.

1
IDEAL gas law

2
Solve quantitative problems involving the relationships among the pressure, temperature, and volume of a gas using dimensional analysis. Include: Avogadro, Ideal Gas Law and the mole Additional KEY Terms Molar volume Molar mass

3
Avogadro ( ) Any sample of any gas at the same temperature and pressure will contain the same number of particles.

4
*** Experiment conducted at constant temperature and pressure**

5
**Particles are now counted in moles (n).**

Defined 22.4 L as the molar volume for any gas. Particles are now counted in moles (n). The number of moles is directly proportional to pressure, temperature, and volume.

6
**P1 V1 = P2 R k V2 n T1 T2 L · kPa 8.314 mol · K**

Experiments with n, V, P, and T give Ideal gas law: P1 V1 = P2 R k V2 n T1 T2 R = experimentally determined ideal gas constant. Value of R depends on the units used for pressure. L · atm L · kPa 0.0821 8.314 mol · K mol · K L · mmHg 62.4 mol · K

7
**A steel container with a volume of 20**

A steel container with a volume of 20.0 L is filled with nitrogen gas to a final pressure of kPa at 27.00C. How many moles of gas was used? L · kPa mol · K 8.314 = P V n R T 27°C = 300 K = 2000 (20.0) 16.0 moles n 8.314 (300)

8
**The mass of 1 mole is the molar mass - (g/mol)**

One mole of any particle has a mass equal to its total formula mass – IN GRAMS. The mass of 1 atom of Al = 27.0 µ The mass of 1 mole of Al atoms = 27.0 g The molecular mass of water (H2O) is 18.0 µ ... So...the molar mass of water is 18.0 g/mol.

9
**Molar mass of lead (II) chloride, PbCl2 ?**

1 particle of PbCl2 - 1 atom of Pb, 2 atoms of Cl 1 mole of PbCl2 - 1 mole of Pb, 2 moles of Cl PbCl2 = g/mol + 2(35.5 g/mol) = g/mol The molar mass of lead (II) chloride is g/mol.

10
**What pressure is exerted by 640.0 g of methane (CH4) gas in a sealed 5.35L container at 27 ºC?**

Molar mass of CH4 = 16.0 g/mol 640.0 g 16.0 g 1 mol = moles L · kPa mol · K 8.314 P V = n R T 27°C = 300 K (40.0) 8.314 (300) 1.9 x 104 kPa = (5.35)

11
**= 2.75 g of O2 = P V n R T = 101.3 (2.2) 0.086 moles 8.314 (310)**

A child lung capacity is 2.2 L. How many grams of oxygen gas do lungs hold at a pressure of 1.00 atm and a normal body temperature of 37.00C? L · kPa mol · K 8.314 = P V n R T 37°C = 310 K = 101.3 (2.2) 0.086 moles 8.314 (310) Molar mass of O2 = 32.0 g/mol 1 mol 32.0 g 0.086 mol = g of O2

13
CAN YOU / HAVE YOU? Solve quantitative problems involving the relationships among the pressure, temperature, and volume of a gas using dimensional analysis. Include: Avogadro, Ideal Gas Law and the mole Additional KEY Terms Molar volume Molar mass

Similar presentations

Presentation is loading. Please wait....

OK

The Ideal Gas Law PV = nRT.

The Ideal Gas Law PV = nRT.

© 2017 SlidePlayer.com Inc.

All rights reserved.

Ads by Google

Download ppt on coordinate geometry for class 9th model Three dimensional viewing ppt on ipad Download ppt on operating system Ppt on how industries are polluting our water resources Upload and view ppt online Ppt on viruses and anti viruses free downloads Ppt on idiopathic thrombocytopenia purpura genetic Ppt on bresenham's line drawing algorithm Ppt on asymptotic notation of algorithms definition Download ppt on jammu and kashmir tourism