2ReviewThe pressure, volume, and temperature of a gas are related to each other.For ideal (or near-ideal) gases: PV = nRTIf you change one aspect of a gas, you change the others.
3Changes in Gases Constant temperature: Constant volume: As V increases, P decreases.As V decreases, P increases.Constant volume:As T increases, P increases.As T decreases, P decreases.Constant pressure:As T increases, V increases.As T decreases, V decreases.VPTPTV
4Changes in Gases Make a card with the letters P T V. Must be in that order.Hold one of the variables constant while changing one of the others.Observe what happens to the dependent variable.
5The Combined Gas Law We know that PV = nRT So nR = PV/T k = PV/T If the amount of gas stays the same, then nR = constant (k)k = PV/TThe conditions of a gas can change, but k must stay the same if the amount doesn’t change:k = P1V1 / T1k = P2V2 / T2
6The Combined Gas Law P1V1 T1 = P2V2 T2 P1 = initial pressure (any suitable unit)V1 = initial volume (any suitable unit)T2 = initial temperature (K)P2 = final pressure (same unit as P1)V2 = final volume (same unit as V1)T2 = final temperature (K)
7The Combined Gas Law (1.00 atm)(99.0 L) 273 K = (0.800 atm)(V2) 315 K At STP a certain gas sample occupies a volume of 99.0 L. What is the gas’s volume at 315 K and atm?(1.00 atm)(99.0 L)273 K=(0.800 atm)(V2)315 K0.363 atm*L/K=( atm/K)V2V2 = 143 L
8The Combined Gas LawWe can also employ cross-multiplication to solve CGL problems.
9The Combined Gas Law (400. mmHg)(12.0 mL) 325 K = (380. mmHg)(6.80 mL) A gas sample occupies 12.0 mL at 400. mmHg and 325 K. At what temperature (in K) would the sample occupy 6.80 mL when the pressure is 380. mmHg?(400. mmHg)(12.0 mL)325 K=(380. mmHg)(6.80 mL)T2(400. mmHg)(12.0 mL) T2 = (380. mmHg)(6.80 mL)(325 K)(4.80x103 mmHg*mL) T2 = 8.40x105 mmHg*mL*KT2 = 175 K
10The Combined Gas LawIf some aspect of a gas is being held constant, we can leave that aspect out of the combined gas law:Constant temperature:P1V1 = P2V2Boyle’s LawConstant pressure:V1/T1 = V2/T2Charles’s LawConstant volume:P1/T1 = P2/T2Gay-Lussac’s Law
11The Combined Gas LawA gas sample’s volume is 44.0 L when its pressure is 1.00 atm. If the pressure is changed to 2.00 atm at constant temperature, what is the new volume of the gas?Predict first! Will the gas’s volume go up or down?Use the modified combined gas law to solve!
12The Combined Gas LawA gas sample’s volume is 44.0 L when its pressure is 1.00 atm. If the pressure is changed to 2.00 atm at constant temperature, what is the new volume of the gas?P1V1 = P2V2(1.00 atm)(44.0 L) = (2.00 atm) V244.0 atm*L = (2.00 atm) V2V2 = 22.0 L