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Heat Loss due to Infiltration & Ventilation Infiltration 1.1 x [(ACH x vol.) /60] x (Ti -To) -or-.018 x ACH x Vol. x (Ti- To) Note: CFM = (ACH x volume)

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Presentation on theme: "Heat Loss due to Infiltration & Ventilation Infiltration 1.1 x [(ACH x vol.) /60] x (Ti -To) -or-.018 x ACH x Vol. x (Ti- To) Note: CFM = (ACH x volume)"— Presentation transcript:

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2 Heat Loss due to Infiltration & Ventilation Infiltration 1.1 x [(ACH x vol.) /60] x (Ti -To) -or-.018 x ACH x Vol. x (Ti- To) Note: CFM = (ACH x volume) / 60 min per hour Ventilation 1.1 x [( R a x SF) + (No. of people x R p )] x (Ti –To) Area out Outdoor Rate (based on SF) People Outdoor Air Rate (based number of people )

3 Heat Loss Due to Infiltration Infiltration Please Note: For tight construction use 0.5 for ACH. For medium construction use.85 for ACH. For loose construction use 1.3 for ACH. For really bad construction use 2.0 for ACH For the summer months (cooling) use 70% of the winter values.

4 Heat Gains from Occupant Loads Sensible per occupant X number of occupants = Btu h Latent per occupant X number of occupants = Btu h

5 Heat Gains from Infiltration Loads Sensible Btu h = 1.1 x CFM x TD Latent Btu h = 4,500 x CFM x (W room – W oa )

6 Heat Gains from Outside Air for Ventilation Loads Sensible Btu h = 1.1 x CFM x TD Latent Btu h = 4,500 x CFM x (W room – W oa ) -or- Btu h =.68 x CFM x (W 2 – W 1 )

7 Degree Days Temperatures between 60 0 and 80 0 Fahrenheit are comfortable. Temperatures between 60 0 and 80 0 are nicknamed the Goldilocks Zone. Degree days HDD heating is based on each degree below the base of 65 0 U.S. 60 o in Great Britain Degree days CDD cooling is based on each degree above the base of 80 0 U.S. 60 o in Great Britain

8 Degree Days for Pullman HDD = 6655 CDD = 1154 Degree Day = 65°F - ((high temp. – low temp])/2)

9 Formula Operating Hours = [Degree Days x 24] / [ Temperature Difference] Heating Degree Days for Pullman = HDD = 6655 (look up) Temperature Difference =ΔT (for project)

10 Formula Operating Hours = [Degree Days x 24] / [ Temperature Difference] Heating Degree Days Example: The Kirk Building Operating Hours = (6655 x 24)/87 Operating Hours = 1,836

11 Formula Operating Hours = [Degree Days x 24] / [ Temperature Difference] Cooling Degree Days for Pullman = CDD = 1154 Temperature Difference =ΔT (for project)

12 Formula Operating Hours = [Degree Days x 24] / [ Temperature Difference] Cooling Degree Days Example: The Kirk Building Operating Hours = (1154 x 24)/25 Operating Hours = 1,108

13 Estimating Annual Energy Heating $/Yr Electric (BTU/Hr) * (hours of operation) * $/energy unit BTU/energy Unit * Efficiency Electric conversion = 3,400 BTU h/Kilowatt Efficiency = 1.0 Note: Does not include fan energy. Add 10% for residential and 20% for commercial fan energy

14 Estimating Annual Energy Heating $/Yr Gas (BTU/Hr) * (hours of operation) * $/energy unit BTU/energy Unit * Efficiency Electric conversion = 100,000 BTU h/Therm Efficiency = 80% - 96% Note: Does not include fan energy. Add 10% for residential and 20% for commercial fan energy

15 Estimating Annual Energy Cooling $/Yr (Btu/Hr) * (hours of operation) * $/energy unit SEER * 1000 Note: Does not include fan energy. Add 10% for residential and 20% for commercial fan energy

16 Estimating Annual Energy SEER Seasonal Energy Efficiency Ratio The U.S. Department of Energy claims energy we use in an average house is responsible for twice as many greenhouse gas emissions as an average car.

17 Estimating Annual Energy

18 SEER Seasonal Energy Efficiency Ratio The efficiency of central air conditioning regulated by the U.S. Department of Energy (DOE). The SEER is defined as the total cooling output (in British thermal units or Btu) provided by the The change from SEER 10 to SEER 13 represented a 30 percent improvement in energy efficiency. SEER = (seasonal Btu of cooling) / (seasonal watt-hours of electricity used)

19 Estimating Annual Energy SEER Seasonal Energy Efficiency Ratio Great strides have been made in the last 10 years in efficiency of air conditioners and heat pumps. SEER ratings for air conditioning and air-source heat pump systems manufactured today range from 13 SEER to 24. Central air conditioners that are in the top 25 percent of efficient may carry the ENERGY STAR® label. To qualify, they must have a minimum SEER efficiency level of 14

20 Estimating Annual Energy Example: The Kirk Building Heating $/Yr (2,324,056) * (hours of operation) * $/energy unit BTU/energy Unit * Efficiency Note: Does not include fan energy. Add 10% for residential and 20% for commercial fan energy

21 Electrical Cost to Heat [(BTU/Hr) * (hours of operation) * $/energy unit]/ BTU/energy Unit * Efficiency.08 electrical cost per kilowatt hours [(2,310,240) * (1,836) *.08]/ (3,400 * 1.00) = $99,802.37


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