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Products Percent Yield. Theoretical Yield Maximum amount of product Calculation Balanced Equation Given mass Molar Mass Mole Ratios.

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Presentation on theme: "Products Percent Yield. Theoretical Yield Maximum amount of product Calculation Balanced Equation Given mass Molar Mass Mole Ratios."— Presentation transcript:

1 Products Percent Yield

2 Theoretical Yield Maximum amount of product Calculation Balanced Equation Given mass Molar Mass Mole Ratios

3 Actual Yield Amount of product from an experiment. What are these?

4 Why are they not the same? Reactants and product stick to containers Competing reactions Other ideas?

5 Percent Yield

6 LiOH + HBr  LiBr + H 2 O If you start with 10.0 grams of lithium hydroxide, how many grams of lithium bromide will be produced? Find percent yield if an experiment yielded 35.0 grams of lithium bromide.

7 LiOH + HBr  LiBr + H 2 O 10 g LiOH 1 mol LiOH 1 mol LiBr 87 g LiBr = 36.3 g LiBr 24 g LiOH 1 mol LiOH 1 mol LiBr Given 10 g mass-to-mole mole mole-to-mass unknown ratio mass

8

9 C 2 H 4 + 3 O 2  2 CO 2 + 2 H 2 O If you start with 45 grams of ethylene (C 2 H 4 ), how many grams of carbon dioxide will be produced? Find percent yield if an experiment yielded 132.4 grams of carbon dioxide.

10 C 2 H 4 + 3 O 2  2 CO 2 + 2 H 2 O 45 g C 2 H 2 1 mol C 2 H 2 2 mol CO 2 44 g CO 2 = 141 g CO 2 28 g C 2 H 2 1 mol C 2 H 2 1 mol CO 2 Given 45 g mass-to-mole mole mole-to-mass unknown ratio mass

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