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National 4/5 Physics In addition to set homework you will be expected to finish off class notes and regularly review work against the learning outcomes.

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Presentation on theme: "National 4/5 Physics In addition to set homework you will be expected to finish off class notes and regularly review work against the learning outcomes."— Presentation transcript:

1 National 4/5 Physics In addition to set homework you will be expected to finish off class notes and regularly review work against the learning outcomes. You will be expected to take responsibility for your own learning and for seeking help when you need it. At the end of each section, you must ensure all notes are completed and examples attempted.

2 In unit 1 we will learn about the physics of motion.
We will focus on the language, principles and laws which describe and explain the motion of an object. Kinematics, also known as Mechanics is the science of describing the motion of objects using words, diagrams, numbers, graphs and equations. Print for lab books The goal is to develop mental models which describe and explain the motion of real-world objects.

3 Key words: vectors, scalars, distance, displacement, speed, velocity.
By the end of this section you will be able to: Describe what is meant by vector and scalar quantities State the difference between distance and displacement State the difference between speed and velocity State that force is a vector quantity Use a scale diagram to find the magnitude and direction of the resultant of two forces acting at right angles to each other. Tuesday 28th August Initial lesson only 25 minutes with class moves etc

4 Key words: average speed
By the end of this section you will be able to: Describe how to measure an average speed Carry out calculations involving distance, time and average speed.

5 Which of these are units of speed?
metres gallons miles per hour seconds minutes amperes miles kilometres per second miles per minute watts metres per second Newtons

6 Speeds in…. In Physics we normally use units m/s for velocity.

7 Average speed (m/s) High speed train Snail Sound 270 m/s 13.4 m/s
UK town Fast jet 747 jumbo jet 10.3 m/s 29790 m/s 97 m/s Air molecule Earth in orbit Falcon 60 m/s 648 m/s 7500 m/s Olympic sprinter UK motorway Earth satellite 500 m/s Can you match the correct speeds m/s 340 m/s Walking speed Light speed Concorde 1.7 m/s 31 m/s 833 m/s

8 Average speed ( m/s ) Light speed 300000000 m/s Earth in orbit
Earth satellite 7500 m/s Fast jet 833 m/s Concorde 648 m/s Air molecule 500 m/s Sound 340 m/s 747 jumbo jet 270 m/s Falcon 97 m/s High speed train 60 m/s UK motorway 31 m/s UK town 13.4 m/s Familiarisation with realistic speeds in m/s to aid calculations. Olympic sprinter 10.3 m/s Walking speed 1.7 m/s Snail 0.006 m/s

9 What is speed? When we talk about speed we mean…
the distance covered by an object in a given time.

10 What is speed? If Hamish (the dog) runs 10 metres in 2
seconds, what is his speed?

11 What is speed? His speed is 5 metres per second. So speed is

12 What is speed? If you forget the formula think of cars travelling at 30 kilometres per hour km Per Hour =

13 Key words: average speed
By the end of this section you will be able to: Describe how to measure an average speed Carry out calculations involving distance, time and average speed.

14 distance speed time

15 Speed Calculations A cyclist travels 100 m in 12 s. What is her speed?

16 Step 1: write down what you know.
d = 100 m t = 12 s speed = ?

17 Step 2: write down your formula. You can use the triangle to help you but remember you get no marks for this! d = 100 m t = 12 s speed = ? d = speed x t

18 d = speed x t Step 3: substitute in your values. d = 100 m t = 12 s

19 d = speed x t 100 = speed x 12 Step 4: rearrange d = 100 m t = 12 s

20 d = speed x t 100 = speed x 12 speed = = 8.33 100 12 Step 5: calculate
d = 100 m t = 12 s speed = ? 100 12

21 d = speed x t 100 = speed x 12 Speed = = 8.33 m/s 100 12
Step 6: units!!!! d = speed x t 100 = speed x 12 Speed = = 8.33 m/s d = 100 m t = 12 s speed = ? 100 12

22 Key words: average speed, instantaneous
By the end of this section you will be able to: Describe how to measure instantaneous speed. Identify situations where average speed and instantaneous speed are different.

23 Instantaneous and average speed
Are instantaneous and average speed the same?

24 Instantaneous or average?
A car’s speed between North Berwick and Edinburgh Average

25 Instantaneous or average?
The speed read from a car’s speedometer Instantaneous

26 Instantaneous or average?
A tennis ball’s speed as it crosses the net Instantaneous

27 Instantaneous or average?
A racing car’s speed over a lap of the track Average

28 Instantaneous or average?
A parachutist’s speed as he/she lands Instantaneous

29 Scalars and Vectors Imagine a boat making a distress call to the
coastguard. The boat tells the coastguard he is 60 km from Aberdeen.

30 Scalars and Vectors Is this enough information for the
coastguard to find the boat?

31 Scalars and Vectors

32 distance (size) direction Scalars and Vectors
The coastguard needs both distance (size) and direction to find the boat.

33 Scalars and Vectors - Definition
A scalar is a quantity which has only magnitude (size). It is defined by a number and a unit. A vector is a quantity which has magnitude (size) and direction. It is defined by a number, a unit and a direction. Print for lab books

34 Distance and Displacement
A pupil walks from her house to her school. Her brother makes the same journey, but via a shop. How far has the girl walked? How far has her brother walked? 500 m 300 m 400 m

35 Distance and Displacement
The girl has walked 500 m. Her brother has walked 700 m. Distance is a scalar quantity – it can be defined simply by a number and unit. 500 m 300 m 400 m

36 Distance and Displacement
Distance is simply a measure of how much ground an object has covered. 500 m 300 m 400 m

37 Distance and Displacement
But how far out of place is the girl? And her brother? Displacement is a vector which requires number, unit and direction. 500 m 300 m 400 m

38 Distance and Displacement
The girl has a displacement of 500 m at a bearing of 117° East of North. 500 m 300 m 400 m

39 Distance and Displacement
What is her brother’s displacement? 500 m 300 m 400 m

40 Distance and Displacement
Her brother has a displacement of 500 m at a bearing of 117° (117° East of North). 500 m 300 m 400 m

41 Distance and Displacement
Their displacement (how far out of place they each are) is the same. 500 m 300 m 400 m

42 Speed and Velocity Speed is a scalar quantity requiring only magnitude (number and unit). Velocity is a vector, requiring magnitude and direction. Print for lab books

43 Speed and Velocity Speed tells us how fast an object is moving.
Velocity tells us the rate at which an object changes position. Print for lab books Physics animations?

44 Speed and Velocity Imagine a person stepping one step
forward, then one step back at a speed of 0.5 ms-1. What is the person’s velocity? Remember velocity keeps track of direction. The direction of the velocity is the same as the direction of displacement.

45 Speed and Velocity Print for lab books

46 Key words: vectors, scalars, distance, displacement, speed, velocity.
By the end of this section you will be able to: Describe what is meant by vector and scalar quantities State the difference between distance and displacement State the difference between speed and velocity State that force is a vector quantity Use a scale diagram to find the magnitude and direction of the resultant of two forces acting at right angles to each other. Wednesday 29th August

47 Distance and Displacement

48 Speed and Velocity

49 A physics teacher walks 4 meters East, 2 meters South, 4 meters West, and finally 2 meters North. The entire motion lasted for 24 seconds. Determine the average speed and the average velocity.                                                          

50 The physics teacher walked a distance of 12 meters in 24
                                                          The physics teacher walked a distance of 12 meters in 24 seconds; thus, her average speed was 0.50 m/s. However, since her displacement is 0 meters, her average velocity is 0 m/s. Remember that the displacement refers to the change in position and the velocity is based upon this position change. In this case of the teacher's motion, there is a position change of 0 meters and thus an average velocity of 0 m/s.

51 Scalar or Vector?

52 Key words: vectors, scalars, resultant, scale diagram
By the end of this lesson you will be able to: Describe what is meant by vector and scalar quantities State the difference between distance and displacement State the difference between speed and velocity State that force is a vector quantity Use a scale diagram to find the magnitude and direction of the resultant of two forces acting at right angles to each other. Thursday 30th August.

53 Vectors Vectors can be represented by a line
drawn in a particular direction. The length of the line represents the magnitude of the vector. The direction of the line represents the direction of the vector.

54 Addition of Vectors When two or more scalars are added
together, the result is simply a numerical sum. For example a mass of 3kg and a mass of 5 kg, when added, make a mass of 8kg.

55 Addition of Vectors 8 N When two or more vectors are added
together, providing they act in the same direction, the addition is straightforward. 5 N 3 N 8 N

56 Addition of Vectors 2 N If they are acting in opposite directions 5 N

57 Key words: vectors, resultant
By the end of this section you will be able to: Use Pythagoras and Trigonometry to find the magnitude and direction of the resultant of two forces acting at right angles to each other. Thursday 30th August

58 Addition of Vectors The resultant of two or more vectors
which act at angle to each other can be found either using a scale diagram, or by Pythagoras and trigonometry.

59 To find the resultant of a set of vectors using a scale diagram
1. Decide on a suitable scale and write this down at the start 2 Take the direction to the top of the page as North. Draw a small compass to show this. 3 Draw the first vector ensuring it is the correct length to represent the magnitude of the vector, and it is the correct direction.

60 To find the resultant of a set of vectors using a scale diagram
Draw an arrow to represent the second vector starting at the head of the first. Vectors are always added head to tail. 5 The resultant vector can now be determined by drawing it on the diagram from the tail of the first to the head of the last vector. The magnitude and direction of this vector is the required answer. 6 The final answer must have magnitude and direction – either a bearing from North or an angle marked clearly on the diagram

61 Scale Diagrams Scale: remember if the question is in ms-1 then your scale should be a conversion from cm to ms-1. Direction: draw compass on page 1st vector: length and direction 2nd vector: tail of 2nd starts at tip of first Resultant vector: tail of 1st to tip of last Answer must include magnitude (including units) and direction Print for lab books

62 Scale Diagrams Direction should be given as a three
figure bearing from North e.g. 045° or 175° or 035° If you give any other angle, you must clearly mark it on the scale diagram. Print for lab books

63 A car travels 100 km South, then 140 km
East. The time taken for the whole journey is 3 hours. Using a scale diagram (and the six step process) find the car’s total distance travelled its average speed its overall displacement its average velocity Review on board – pupils to come up and draw / write

64 Scale Diagrams Scale diagrams are used to find the
magnitude and direction of the resultant of a number of a set of vectors.

65 The tropical island of Sohcahtoa

66 The tropical island of Sohcahtoa

67 The tropical island of Sohcahtoa

68 The tropical island of Sohcahtoa Print for lab books

69 hyp opp θ° adj Print for lab books

70 Tan = Opp/Adj; Cos= Adj/Hyp;
The Old Arab Carried A Heavy Sack Of Hay Tan = Opp/Adj; Cos= Adj/Hyp; Sin=Opp/Hyp

71 hyp opp θ° adj

72 N + 3 km North E 4 km East Remember: The vectors above are not tip to tail. You must join them tip to tail

73 N R = ? + 3 km North E 4 km East = Bearing of

74 We ADD vectors HEAD to TAIL [tip to toe]
6N 6N North, 8N East - what is the resultant force R ? We ADD vectors HEAD to TAIL [tip to toe] 8N 6N R 8N

75 Key words: acceleration, velocity
By the end of this section you will be able to: Explain the term “acceleration” State that acceleration is the change in velocity per unit time Carry out calculations involving the relationship between initial velocity, final velocity, time and uniform acceleration.

76 Measuring Acceleration Activity
What do you expect to happen to the value of acceleration as the light gate is moved further up the slope? Position of light gate from bottom of slope Acceleration (m/s2) 1st attempt 2nd attempt 3rd attempt Position 1 m Position 2 Position 3 Position 4 Average acceleration (m/s2) Print for lab books

77 What is acceleration? Acceleration is the change in velocity of an object per second (in one second). Is acceleration a vector or scalar quantity?

78 Acceleration What is the definition of acceleration?
Is it a vector or a scalar? Acceleration is the rate of change of velocity per unit time OR change in velocity per unit time. Vector – since velocity is a vector.

79 What is acceleration? The rocket starts off at 0 m/s and 1
second later is travelling at 10 m/s. What is its acceleration? 10 metres per second per second 10 m/s2 change in speed in one second

80 Calculating acceleration
We need to know… the change in velocity so… initial velocity (u) final velocity (v) and… time (t)

81

82 change in velocity in one second

83 Acceleration a = acceleration measured in m/s2
u = initial velocity measured in m/s v = final velocity measured in m/s t = time measured in s

84 Units of acceleration a = acceleration is measured in m/s2
final velocity – initial velocity a = time acceleration is measured in m/s2 If the speed is measured in kilometres per hour, acceleration can be measured in kilometres per hour per second.

85 Acceleration An object accelerates at a rate of 4 m/s2.
What does this mean? The object goes 4 m/s faster each second.

86 Acceleration The object goes 4 m/s faster each second.
If the object is initially at rest, what is its velocity after: 1s? 4 m/s 2s? 8 m/s 3s? 12 m/s 4s? 16 m/s

87 Acceleration What does it mean if an object has a negative
value of acceleration? It means that it is slowing down. For example: an object which has an acceleration of -2 m/s2 is becoming 2 m/s slower each second.

88 Acceleration Calculations
A car, starting from rest, reaches a velocity of 18 m/s in 4 seconds. Find the acceleration of the car. What do I know? Initial velocity u = 0 m/s Final velocity v = 18 m/s time t = 4 s

89 Acceleration Calculations
What do I know? Initial velocity u = 0 m/s Final velocity v = 18 m/s time t = 4 s Formula? Example on p5 to do themselves

90 Acceleration Calculations
A cheetah starting from rest accelerates uniformly and can reach a velocity of 24 m/s in 3 seconds. What is the acceleration? Use technique and show all working! Units!!

91 Acceleration Calculations
A student on a scooter is travelling at 6 m/s. 4 seconds later, she is travelling at 2 m/s. Calculate her acceleration. Use technique and show all working! Units!! What do you notice about her change in velocity?

92 Rearranging the acceleration equation
v-u a t Pupils found rearranging the equation difficult!

93 Rearranging the acceleration equation
v-u a t

94 Key words: acceleration, velocity
By the end of this section you will be able to: Explain the term “acceleration” State that acceleration is the change in velocity per unit time Carry out calculations involving the relationship between initial velocity, final velocity, time and uniform acceleration. Graph results

95 Acceleration using two light gates
The length of the mask is 5 cm. Calculate the acceleration. Remember calculate u (initial velocity) and v (final velocity) and use

96 Acceleration using a double mask
The length of each section mask is 4 cm. The gap is also 4 cm. Calculate the acceleration. Remember calculate u (initial velocity) and v (final velocity) and use

97 Key words: acceleration, velocity, displacement
By the end of this seection you will be able to: Draw velocity-time graphs of more than one constant motion. Describe the motions represented by a velocity-time graph. Calculate displacement and acceleration, from velocity-time graphs, for more than one constant acceleration. Tuesday 11th September

98 Graphing Motion Information about the motion of an
object can be obtained from velocity-time graphs. Similarly, we can graph motion based on descriptions of the motion of an object.

99 Velocity-time graph The motion of a moving object can be
represented on a velocity – time graph. Virtual Int 2 Physics – can pupils predict – remember area under speed time graph = distance, so area under velocity time graph = displacement.

100 Vectors and Direction direction.
When dealing with vector quantities we must have both magnitude and direction. When dealing with one-dimensional kinematics (motion in straight lines) we use + and – to indicate travel in opposite directions. We use + to indicate acceleration and – to indicate deceleration.

101 Velocity-Time Graphs Describe the motion of this object.
Constant velocity – does not change with time

102 Velocity-Time Graphs Describe the motion of this object.
Increasing with time – constant acceleration

103 Velocity-Time Graphs Describe the motion of this object.
Decreases with time – constant deceleration

104 Velocity-Time Graphs Describe the motion of this object.

105 Speed-Time Graphs Calculate the distance covered by the object
in the first 10 s of its journey. The area under the graph tells us the distance travelled.

106 Speed-Time Graphs Calculate the distance covered by the object
in the first 10 s of its journey. The area under the graph tells us the distance travelled.

107 Describe the effects of forces in terms of their ability to
Key words: forces, newton balance, weight, mass, gravitational field strength. By the end of this section you will be able to: Describe the effects of forces in terms of their ability to change the shape, speed and direction of travel of an object. Describe the use of a newton balance to measure force. State that weight is a force and is the Earth’s pull on an object. Distinguish between mass and weight. State that weight per unit mass is called the gravitational field strength. Carry out calculations involving the relationship between weight, mass and gravitational field strength including situations where g is not equal to 10 N/kg.

108 What effect can a force have?
Force is simply a push or a pull. Some forces (e.g. magnetic repulsion, or attraction of electrically charged objects) act at a distance.

109 What is force? A force can change the shape of an object
change the velocity of an object change the direction of travel of an object

110 Units of Force? Force (F) is measured in newtons (N).

111 Measuring Forces A Newton (or spring) balance can be used to measure
Show newton balances – hang masses on and read off force.

112 Mass and Weight We often use the words mass and weight
as though they mean the same… but do they?

113 Mass and Weight An object’s mass is
a measure of how much “stuff” makes up that object – how much matter, or how many particles are in it. Mass is measured in grams or kilograms.

114 Mass and Weight An object’s weight is
the force exerted by gravity on a mass. Since it is a force, weight must be measured in newtons.

115 Investigating the relationship between mass and weight
How can we find the relationship between mass and weight? A newton balance can be used to find the weight of known masses.

116 Results Mass Weight in N 100g 200g 300g 400g 500g 1kg 2kg 5kg

117 Relationship between mass and weight
From this we can see a relationship between mass and weight 100g = 0.1 kg -> 1 N 1kg -> 10 N To convert kg -> N multiply by 10 To convert N -> kg divide by 10

118 Gravitational Field Strength (g)
Gravitational field strength on Earth is 10 N / kg

119 What is gravitational field strength?
This is the pull of gravity on each kilogram of mass. So on Earth, the pull of gravity on a 1kg mass is 10 N

120 What is gravitational field strength?
and the pull of gravity on a 2 kg mass is 20 N

121 A planet’s gravitational field strength is the pull of gravity on
Definition A planet’s gravitational field strength is the pull of gravity on a 1 kg mass.

122 Gravity in the universe
Is gravitational field strength always the same? No! It varies on different planets.

123 Your weight on different planets
Use the website to find your weight on different planets for a mass of 60 kg (a weight of 600 N on Earth). From this calculate the gravitational field strength for each planet.

124 Mass on Earth = 60 kg Weight on Earth = 600 N Gravitational field strength = Weight on Mercury = N g = Weight on Venus = N g = Weight on the Moon = 99.6 N g = Weight on Mars = N g = Weight on Jupiter = N g = Weight on Saturn = N g =

125 10 N / kg Units for g We found g by dividing weight in newtons
by mass in kilograms. What are the units for g? 10 N / kg

126 Which of the planets has the greatest
gravitational field strength? Why do you think this is the case?

127 Weight, mass and gravity
We have seen that there is a link between weight, mass and gravity. On Earth 1 kg acted on by 10 N / kg weighs 10 N m x g = W mass Gravitational field strength g weight

128 Weight, mass and gravity
W = mg Why is weight measured in newtons? Gravitational field strength measured in N / kg Mass measured in kg Weight measured in newtons

129 Key words: friction, force
By the end of this section you will be able to: State that the force of friction can oppose the motion of an object. Describe and explain situations in which attempts are made to increase or decrease the force of friction. 18th September 2007

130 Frictional Forces Moving vehicles such as cars can slow
down due to forces acting on them. These forces can be due to… road surface and the tyres the brakes air resistance.

131 Frictional Forces The force which tries to oppose motion is
called the force of friction. A frictional force always acts to slow an object down.

132 Increasing Friction In some cases, we want to increase
friction. Some examples of this are: Car brakes – we need friction between the brake shoes and the drum to slow the car down Bicycle tyres – we need friction to give “grip” on the surface

133 Increasing Friction On the approach to traffic lights and
roundabouts, different road surfaces are used to increase friction compared with normal roads.

134 Decreasing Friction In some cases, we want to decrease
friction. Some examples of this are: Ice skating Skiing Aircraft design

135 Reducing Friction Friction can be reduced by:
Lubricating the surfaces – this generally means using oil between two metal surfaces. This is done in car engines to reduce wear on the engine – metal parts aren’t in contact because of a thin layer of oil between them.

136 Reducing Friction Friction can be reduced by:
Separating surfaces with air (e.g. a hovercraft). Making surfaces roll (e.g. by using ball bearings).

137 Reducing Friction Friction can be reduced by:
Streamlining. Modern cars are designed to offer as little resistance (or drag) to the air as possible, reducing friction on the car.

138 Streamlining Cars, aeroplanes and rockets are streamlined (that is, have their drag coefficient reduced) by: Reducing the front area Having a smooth body shape

139 Key words: force, vector, balanced forces
By the end of this section you will be able to: State that force is a vector quantity. State that forces which are equal in size but act in opposite directions on an object are called balanced forces and are equivalent to no force at all. Explain the movement of objects in terms of Newton’s first law.

140 Force and direction. Force is a vector quantity. What do we
mean by this? To describe it fully we must have size and direction.

141 Balanced Forces F F Balanced forces are EQUAL FORCES which act in OPPOSITE DIRECTIONS. They CANCEL EACH OTHER OUT.

142 If balanced forces act on a STATIONARY OBJECT, it REMAINS STATIONARY.
If balanced forces act on a MOVING OBJECT, it continues moving in the same direction with CONSTANT VELOCITY. F

143 This is summarised by NEWTON’S FIRST LAW which states:
An object remains at rest, or moves in a straight line with constant velocity unless an UNBALANCED FORCE acts on it.

144 To understand NEWTON’S FIRST LAW remember:
An object tends to want to keep doing what it is doing (so if it is sitting still it wants to stay that way, and if it is moving with constant velocity it wants to keep going).

145 This reluctance to change motion is known as inertia.
The greater the mass, the greater the reluctance. Think! Is it easier to stop a tennis ball travelling towards you at 10 m/s or to stop a car travelling towards you at 10 m/s?

146 Forces and Supported Bodies
A stationary mass m hangs from a rope. What is the weight of the mass? In what direction does this act? W = mg downwards m

147 Forces and Supported Bodies
The mass is stationary. Newton’s law tells us that the forces must be balanced forces. The weight is counterbalanced by a force of the same size acting upwards due to the tension in the string. m

148 Forces and Supported Bodies
A book of mass m rests on a shelf. What is the weight of the book? In what direction does this act? W = mg downwards m

149 Forces and Supported Bodies
The mass is stationary. Newton’s law tells us that the forces must be balanced forces. The weight is counterbalanced by a force of the same size acting upwards due to the shelf. m

150 What forces are acting on this stationary hovering helicopter?
lift = W = mg W = mg

151 Newton’s First Law Newton’s first law tells us that when the
forces on an object are balanced, a stationary object will remain stationary. But it also says that if when forces are balanced, an object moving at constant velocity will continue in the same direction with the same velocity.

152 The ENGINE FORCE and the FRICTION FORCE must be equal.
A moving car If a car moves with constant velocity, then what forces are acting on it? The ENGINE FORCE and the FRICTION FORCE must be equal. Engine force Friction force

153 Newton’s Law & Car Seat Belts
If a car stops suddenly, someone inside the car appears to be “thrown forwards”. In fact, they simply carry on moving with the car’s previous speed. A seat belt prevents this happening by applying an unbalanced force to the person, in the direction opposite to motion. This causes rapid deceleration.

154 No seatbelt – what’s going to happen when the car hits the wall?
Explain this in terms of Newton’s 1st law.

155 What’s going to happen when the motorbike hits the wall?
Explain this in terms of Newton’s 1st law.

156 Air bags Air bags produce a similar effect to seatbelts. They apply a force which opposes the motion, causing rapid deceleration. The large surface area also spreads the force of impact, reducing the pressure and reducing injury.

157 Forces in a Fluid Terminal velocity
Any free-falling object in a fluid (liquid or gas) reaches a top speed, called ‘terminal velocity’.

158 Terminal Velocity The air resistance acting on a moving object increases as it gets faster. Terminal velocity is reached when the air-resistance (acting upwards) has increased to the same size as the person’s weight (acting downwards)

159 a = -10 m/s2 time = 0s, velocity = 0 m/s, friction = 0 N
Friction Ff(air resistance) = 0 N a = -10 m/s2 W = weight

160 Ff a < -10 m/s2 v W = weight

161 Equal & opposite forces Acceleration zero Terminal velocity
Ff a = 0 m/s2 v W = weight

162 Velocity – Time Graph velocity (m/s) Terminal velocity time (s)

163 air resistance Terminal velocity is reached when the air resistance balances the weight. weight

164 Terminal Velocity What effect does opening a parachute
have on the terminal velocity? When the parachute is opened, air resistance increases a lot. There is now an unbalanced force upwards, which causes deceleration. The velocity decreases, and the air resistance decreases until the forces are balanced again. The parachutist falls to the ground with a lower terminal velocity.

165 Key words: Newton’s second law, unbalanced forces, mass, force,
acceleration By the end of this section you will be able to: Describe the qualitative effects of the change of mass or of force on the acceleration of an object Define the newton Carry out calculations using the relationship between a, F and m and involving more than one force but in one dimension only

166 The example of the parachutist accelerating until the forces are balanced helps us to understand NEWTON’S SECOND LAW which states: When an object is acted on by a constant UNBALANCED FORCE the body moves with constant acceleration in the direction of the unbalanced force.

167 Force, mass and acceleration
Acceleration (m/s2) F = ma Force (N) mass (kg)

168 Force, mass and acceleration
One newton (1N) is the force required to accelerate 1 kg at 1 m/s2

169 F = ma Find the unbalanced force required to accelerate a 4 kg mass at 5 m/s2 What do I know? m = 4kg a = 5m/s2 F = ma F= 4 x 5 F = 20 N

170 Key words: free body diagrams, resultant force
By the end of this section you will be able to: Use free body diagrams to analyse the forces on an object State what is meant by the resultant of a number of forces Use a scale diagram, or otherwise, to find the magnitude and direction of the resultant of two forces acting at right angles to each other.

171 Newton’s First Law A body remains at rest, or continues at
constant velocity, unless acted upon by an external unbalanced force. (that is objects have a tendency to keep doing what they are doing)

172 Newton’s Second Law Newton’s Second Law is about the
behaviour of objects when forces are not balanced. The acceleration produced in a body is directly proportional to the unbalanced force applied and inversely proportional to the mass of the body.

173 Newton’s Second Law In practice this means that
the acceleration produced increases as the unbalanced force increases the acceleration decreases as the mass of the body increases

174 Which forces? An object may be acted upon by a number of forces but
only an overall unbalanced force will lead to acceleration in the direction of that force.

175 Forces are measured in…?
Newton’s Second Law can be written as or more commonly

176 Forces are measured in…?
which gives us the definition of the Newton: 1N is the resultant (or unbalanced) force which causes a mass of 1kg to accelerate at 1m/ s2

177 Quick Quiz 5 10 5 10 1 Unbalanced force (N) Mass (kg) Acceleration
(m/ s2) 10 2 20 4 5 5 10 5 10 1

178 Direction of force To the right To the right
Consider the oil drop trail left by the car in motion. In which direction is the acceleration? In which direction is the unbalanced force? To the right To the right

179 Direction of force Consider the oil drop trail left by the car
in motion. In which direction is the unbalanced force? To the left – the car is moving to the right and slowing down.

180 Newton’s First and Second Laws
Remember Forces do not cause motion Forces cause acceleration

181 Free-Body Diagrams Free body diagrams are special
examples of a vector diagram. They show the relative magnitude and direction of all forces acting on an object. They are used to help you identify the magnitude and direction of an unbalanced Force acting on an object. Weight

182 Using Newton’s Second Law
In the simplest case m Fun

183 Using Newton’s Second Law
Direction of acceleration? Direction of unbalanced force? Formula for calculating acceleration? m F1 F2 Fu

184 Solving Problems Always draw a diagram showing all known
quantities (forces – magnitude and direction, resultant acceleration and direction, mass of object(s) ) Remember that Fun=ma can be applied to the whole system When working in the vertical direction always include the weight

185 Key words: acceleration, gravitational field strength, projectiles
By the end of this section you will be able to: Explain the equivalence of acceleration due to gravity and gravitational field strength Explain the curved path of a projectile in terms of the force of gravity Explain how projectile motion can be treated as two separate motions Solve numerical problems using the above method for an object projected horizontally.

186 Acceleration due to Gravity
Definition: A planet’s gravitational field strength equals the force of gravity PER UNIT MASS. Units? N/kg To calculate an object’s weight, use this equation -

187 Acceleration due to Gravity
Near a planet’s surface all objects experience the same gravitational acceleration. This acceleration is numerically equal to the planet’s gravitational field strength.

188 Acceleration due to Gravity
For example, on Earth – g = 10 N/kg A free-falling object will experience acceleration of a = -10 m/ s2 What does the –ve sign tell you?

189 Gravitational field strength
Is the gravitational field strength the same on each planet? How does distance affect gravitational field strength? It decreases the further away you are from the planet’s surface. What will happen to the weight of an object as it gets further from the surface? Explain your answer. It will decrease.

190 The force of gravity near
the Earth’s surface gives all objects the same acceleration. So why doesn’t the feather reach the ground at the same time as the elephant?

191 Why are the gaps between the balls increasing?

192 An object is released from rest close to the Earth’s
surface. Which formula can be used to find its velocity at a given time? v = u + at where v = ? u = a = t = What is its velocity: At the time of release? After 1 second? After 2 seconds? After 3 seconds? After 4 seconds?

193 Projectiles

194 Forces acting on projectiles
What would happen to a ball kicked off a cliff, in the absence of gravity?

195 Forces acting on projectiles
There would be no vertical motion therefore the ball would continue at constant speed in a straight line (remember Newton’s first law)

196 Objects projected horizontally Think about…
What is the initial vertical speed of a projectile fired horizontally? How will the horizontal speed vary during the object’s flight? 0 m/s It will remain the same as the initial horizontal speed.

197 Objects projected horizontally Think about…
Describe the vertical motion of an object projected horizontally: It will accelerate downwards due to gravity.

198 Objects projected horizontally Think about…
What formula can be used to find the horizontal displacement of an object fired horizontally if horizontal velocity and time of flight are known? time of flight (s) horizontal displacement (m) sh = vht horizontal velocity (m/s)

199 Which ball will hit the ground first?

200 Summary Horizontal motion Vertical motion Forces Are there forces
present? If so, in what direction are they acting? No Yes The force of gravity acts downward Acceleration Is there acceleration? If so, in what direction? What is the value of the acceleration? Acceleration = "g" downward at 10 m/s2 Velocity Constant or changing? Constant Changing by 10 m/s each second

201 Solving Numerical Problems
Always write down what you know – many questions have a lot of text surrounding the Physics so pick out the information from the question Write down other relevant information you have e.g. acceleration due to gravity Select formula – this isn’t a test of memory so while you should learn your formulae, don’t be afraid to check against the data book or text book Substitute values and rearrange formula Write answer clearly remembering magnitude and direction, and units.

202 Example A flare is fired horizontally out to sea from a
cliff top, at a horizontal speed of 40 m/s. The flare takes 4 s to reach the sea. What is the horizontal speed of the flare after 4 s? There are no forces acting in the horizontal. The horizontal speed remains the same = 40 m/s.

203 Example (b) Calculate the vertical speed of the flare after 4s
final speed v = ? initial vertical speed u = 0 m/s Initial vertical speed is always 0 m/s! acceleration a = 10 m/s2 time t = 4 s v = u + at v = x 4 v = 40 m/s

204 Example (c) Draw a graph to show how vertical speed varies with time.
Initial vertical speed = 0 m/s Final vertical speed = 40 m/s

205 Example (d) Use this graph to calculate the height of the cliff.
Displacement = area under velocity-time graph ½ bh = ½ x 4 x 40 = 80 m Height of cliff = 80 m

206 Key words: Newton’s third law, newton pairs
By the end of this section you will be able to: State Newton’s third law Identify “Newton pairs” in situations involving several forces State that momentum is the product of mass and velocity. State that momentum is a vector quantity.

207 Forces acting between objects
Newton realised that When a body is acted upon by a force there must be another body which also has a force acting on it. The forces are equal in size but act in opposite directions.

208 Newton’s Third Law If object A exerts a force on object B, then B exerts an equal and opposite force on A Forces always occur in equal and opposite pairs For every action there is an equal and opposite reaction

209 Firing a gun Force of GUN on BULLET Force of BULLET on GUN

210 Force of RUNNER on BLOCKS
Starting a sprint Force of RUNNER on BLOCKS Force of BLOCKS on RUNNER

211 A falling apple Force of EARTH on APPLE Force of APPLE on EARTH

212 A Rocket Force of GAS on ROCKET Force of ROCKET on GAS

213 Key words: work done, energy, force, distance, power, time
By the end of this section you will be able to: State that work done is a measure of the energy transferred. Carry out calculations involving the relationship between work done, force and distance. relationship between work done, power and time.

214 Work done? What is meant by work done in Physics?
When a force acts upon an object to cause a displacement of the object, it is said that work was done upon the object.

215 Work done? There are three key ingredients to work –
force, displacement, and cause. In order for a force to qualify as having done work on an object, there must be a displacement and the force must cause the displacement. Note; at this level, we can use distance instead of displacement.

216 Work done? Formula linking work done, force and displacement?
Examples of work done? a horse pulling a plough through the field a shopper pushing a grocery cart down the aisle of a supermarket a pupil lifting a backpack full of books upon her shoulder a weightlifter lifting a barbell above his head an Olympian launching the shot-put, etc. In each case described here there is a force exerted upon an object to cause that object to be displaced.

217 Work done A dog pulls a 4 kg sledge for a distance on
15 m using a force of 30 N. How much work does he do? What do I know? F = 30N d = 15m

218 Work done What do I know? F = 30N d = 15m Formula?

219 Power Power is the rate of doing work i.e. if
work is done then the work done per second is the power. Energy in joules time in seconds Power in watts (joules per seconds)

220 Power A dog pulls a 4 kg sledge for a distance on
15 m using a force of 30 N in 20 s. Calculate the power of the dog. What do I know? F = 30N d = 15m t = 20s

221 Power What do I know? F = 30N d = 15m t = 20s Formula?

222 Power What do I know? F = 30N d = 15m t = 20s Ew = 450J Formula?

223 By the end of this section you will be able to:
Key words: gravitational potential energy, mass, gravitational field strength, kinetic energy By the end of this section you will be able to: Carry out calculations involving the relationship between change in gravitational potential energy, mass, gravitational field strength and change in height. between kinetic energy, mass and velocity.

224 Gravitational Potential Energy
…is the potential energy gained by an object when we do work to lift it vertically in a gravitational field.

225 Gravitational Potential Energy
The work done in lifting an object vertically What force is required?

226 Gravitational Potential Energy
To lift the object we must overcome the weight W=mg

227 Gravitational Potential Energy
Vertical distance – we call this height h

228 Gravitational Potential Energy

229 …is the energy associated with a moving object.
Kinetic Energy …is the energy associated with a moving object.

230 Kinetic Energy depends on… The mass of the object

231 Kinetic Energy depends on… The velocity of the object

232 Kinetic Energy

233


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