1. IDEAL gas law

2. Solve quantitative problems involving the relationships among the pressure, temperature, and volume of a gas using dimensional analysis.
Include: Avogadro, Ideal Gas Law and the mole
Additional KEY Terms
Molar volume Molar mass

3. Avogadro ( )
Any sample of any gas at the same temperature and pressure will contain the same number of particles.

4. * Experiment conducted at constant temperature and pressure

5. Particles are now counted in moles (n).
Defined 22.4 L as the molar volume for any gas.
Particles are now counted in moles (n).
The number of moles is directly proportional to pressure, temperature, and volume.

6. P1 V1 = P2 R k V2 n T1 T2 L · kPa 8.314 mol · K
Experiments with n, V, P, and T give Ideal gas law: P1 V1 = P2 R k V2 n T1 T2
R = experimentally determined ideal gas constant.
Value of R depends on the units used for pressure.
L · atm
L · kPa
0.0821
8.314
mol · K
mol · K
L · mmHg
62.4
mol · K

7. A steel container with a volume of 20
A steel container with a volume of 20.0 L is filled with nitrogen gas to a final pressure of kPa at 27.00C.
How many moles of gas was used?
L · kPa
mol · K
8.314 = P V n R T
27°C = 300 K =
2000
(20.0)
16.0 moles n
8.314
(300)

8. The mass of 1 mole is the molar mass - (g/mol)
One mole of any particle has a mass equal to its total formula mass – IN GRAMS.
The mass of 1 atom of Al = 27.0 µ
The mass of 1 mole of Al atoms = 27.0 g
The molecular mass of water (H2O) is 18.0 µ ...
So...the molar mass of water is 18.0 g/mol.

9. Molar mass of lead (II) chloride, PbCl2 ?
1 particle of PbCl2 - 1 atom of Pb, 2 atoms of Cl
1 mole of PbCl2 - 1 mole of Pb, 2 moles of Cl
PbCl2 = g/mol + 2(35.5 g/mol)
= g/mol
The molar mass of lead (II) chloride is g/mol.

10. What pressure is exerted by 640.0 g of methane (CH4) gas in a sealed 5.35L container at 27 ºC?
Molar mass of CH4 = 16.0 g/mol
640.0 g
16.0 g
1 mol
= moles
L · kPa
mol · K
8.314 P V = n R T
27°C = 300 K
(40.0)
8.314
(300)
1.9 x 104 kPa =
(5.35)

11. = 2.75 g of O2 = P V n R T = 101.3 (2.2) 0.086 moles 8.314 (310)
A child lung capacity is 2.2 L. How many grams of oxygen gas do lungs hold at a pressure of 1.00 atm and a normal body temperature of 37.00C?
L · kPa
mol · K
8.314 = P V n R T
37°C = 310 K =
101.3
(2.2)
0.086 moles
8.314
(310)
Molar mass of O2 = 32.0 g/mol
1 mol
32.0 g
0.086 mol
= g of O2

13. CAN YOU / HAVE YOU?
Solve quantitative problems involving the relationships among the pressure, temperature, and volume of a gas using dimensional analysis.
Include: Avogadro, Ideal Gas Law and the mole
Additional KEY Terms
Molar volume Molar mass