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Published byElwin Gaines Modified over 8 years ago
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Objective: Divide numbers beyond the times tables using chunking © Hamilton Trust Stepping Up Term 2 Week 5 Day 2
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0 187 160 twenty 8s = 160 184 three 8s = 24 r3 187 ÷ 8 We can also write this using a vertical layout... Are there more than ten 8s in 187? So, how many 8s are in 187? 23 remainder 3
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© Hamilton Trust Stepping Up Term 2 Week 5 Day 2 187 ÷ 8 ? x 8 = 187 20 x 8 = 160 27 what’s left over? 3 x 8 = 24 3 this is the remainder. So, 187 ÷ 8 = 23 remainder 3
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© Hamilton Trust Stepping Up Term 2 Week 5 Day 2 0 250 240 forty 6s = 240 246 one 6 = 6 r4 Talk me through 250 ÷ 6 So, how many 6s are in 250? 41 remainder 4
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© Hamilton Trust Stepping Up Term 2 Week 5 Day 2 With a partner, use the vertical method for 228 ÷ 7 ? x 7 = 228 __ x 7 = ____ large multiple of 10 ___ what’s left over? ___ x 7 = ___ __ this is the remainder. So, 228 ÷ 7 = __ remainder __
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Aim to reach the top of the division steps… © Hamilton Trust Stepping Up Term 2 Week 5 Day 2
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