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Circle O and P are tangent to the x-axis at (4,0) and (13,0), respectively. Point A (4,8) is on circle O and point B (13,10) is on circle P. Line segment.

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Presentation on theme: "Circle O and P are tangent to the x-axis at (4,0) and (13,0), respectively. Point A (4,8) is on circle O and point B (13,10) is on circle P. Line segment."— Presentation transcript:

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2 Circle O and P are tangent to the x-axis at (4,0) and (13,0), respectively. Point A (4,8) is on circle O and point B (13,10) is on circle P. Line segment OP connects the center of circle O to the center of circle P. What is the slope of segment OP?

3 As you can see I plotted the points.

4 After graphing it, I found the diameters of the circles So the middle of the diameters where the center point Next I found the center point of the other circle. I connected the two. The center points were (4,4 ) and (13,5). I used the formula Y2-Y1/X2-X1 to find the slope. I plugged in the numbers for the formula. 5-4/13-4

5 After setting it up as 5-4/13-4. I got 1/9 as the slope

6 I got as my slope

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