Download presentation

1
EXAMPLE 1 Graph an equation of a circle Graph y2 = – x Identify the radius of the circle. SOLUTION STEP 1 Rewrite the equation y2 = – x in standard form as x2 + y2 = 36. STEP 2 Identify the center and radius. From the equation, the graph is a circle centered at the origin with radius r = = 6.

2
EXAMPLE 1 Graph an equation of a circle STEP 3 Draw the circle. First plot several convenient points that are 6 units from the origin, such as (0, 6), (6, 0), (0, –6), and (–6, 0). Then draw the circle that passes through the points.

3
**Write an equation of a circle**

EXAMPLE 2 Write an equation of a circle The point (2, –5) lies on a circle whose center is the origin. Write the standard form of the equation of the circle. SOLUTION Because the point (2, –5) lies on the circle, the circle’s radius r must be the distance between the center (0, 0) and (2, –5). Use the distance formula. r = (2 – 0)2 + (–5 – 0)2 = = The radius is 29

4
**Write an equation of a circle**

EXAMPLE 2 Write an equation of a circle Use the standard form with r to write an equation of the circle. = x2 + y2 = r2 Standard form = ( )2 x2 + y2 Substitute for r 29 x2 + y2 = 29 Simplify

5
EXAMPLE 3 Standardized Test Practice SOLUTION A line tangent to a circle is perpendicular to the radius at the point of tangency. Because the radius to the point (1–3, 2) has slope = 2 – 0 – 3 – 0 = 2 3 – m

6
**Standardized Test Practice**

EXAMPLE 3 Standardized Test Practice the slope of the tangent line at (–3, 2) is the negative reciprocal of or An equation of 2 3 2 – 3 the tangent line is as follows: y – 2 = (x – (– 3)) 3 2 Point-slope form 3 2 y – 2 = x + 9 Distributive property 3 2 13 y = x + Solve for y. ANSWER The correct answer is C.

7
GUIDED PRACTICE for Examples 1, 2, and 3 Graph the equation. Identify the radius of the circle. 1. x2 + y2 = 9 SOLUTION 3

8
GUIDED PRACTICE for Examples 1, 2, and 3 2. y2 = –x2 + 49 SOLUTION 7

9
GUIDED PRACTICE for Examples 1, 2, and 3 3. x2 – 18 = –y2 SOLUTION 2

10
GUIDED PRACTICE for Examples 1, 2, and 3 4. Write the standard form of the equation of the circle that passes through (5, –1) and whose center is the origin. SOLUTION x2 + y2 = 26 5. Write an equation of the line tangent to the circle x2 + y2 = 37 at (6, 1). SOLUTION y = –6x + 37

Similar presentations

© 2023 SlidePlayer.com Inc.

All rights reserved.

To make this website work, we log user data and share it with processors. To use this website, you must agree to our Privacy Policy, including cookie policy.

Ads by Google