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PowerPoint created by Parsheena Berch Resource : JBHM material Pictures: Google Images.

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Presentation on theme: "PowerPoint created by Parsheena Berch Resource : JBHM material Pictures: Google Images."— Presentation transcript:

1 PowerPoint created by Parsheena Berch Resource : JBHM material Pictures: Google Images

2 Solving Equations and Inequalities; Inverse Operations

3 Homework: Turn in page 162 that was for homework yesterday. Does any one have any questions?

4 Review for the test Which symbol will make the sentence true if x=3? 5x__9x a)< b)> c)= d)+

5 If 3x=15, give the value of x. a)0 b)5 c)9 d)395

6 Which equation requires division to solve? a)F + 6 = 14 b)F 6 = 14 c)F – 6 = 14 d)F ÷ 6 = 14

7 Which equation requires addition to solve? a)F + 6 = 14 b)F 6 = 14 c)F – 6 = 14 d)F ÷ 6 = 14

8 What value of D makes the sentence below true? D + 5 = 16 a)11 b)14 c)20 d)28

9 What number makes the sentence true? A – 4 = 6 a)2 b)10 c)11 d)8

10 Which symbol will make the sentence true? 5/p = 5___p a)+ b)- c) d)÷

11 Which symbol will make the sentence true? 5p = 5__p a)+ b)- c) d)÷

12 Which equation requires multiplication to solve? a)W + 6 = 15 b)W 6 = 15 c)W - 6 = 15 d)W ÷ 6 = 15

13 If 6x = 42, give the value of x. a)0 b)7 c)8 d)392

14 Give the value of d in the equation d ÷ 12 = 16 a)2 b)24 c)128 d)192

15 To solve the equation, r/3 = 15, which inverse operation should be used? a)Find the quotient of 15 and 3 b)Find the sum of 15 and 3 c)Find the difference of 15 and 3 d)Find the product of 15 and 3

16 The solution of G + 7= 16 can be represented by which equation? a)G = 16 - 7 b)G = 7 - 16 c)G = 16 + 7 d)G = 8

17 A hill in California is 6,539 feet taller than a hill in Washington. If the height of the hill in California is 11, 122 feet, which equation represents this problem? a)W + 6,539 = 11,122 b)W – 6,539 = 11,122 c)6,539 – w = 11,122 d)W + 11,122 = 6,539

18 Closure: Who would like to share their knowledge of equations and inequalities. Remember that you are having a unit test tomorrow on objectives 2a and 2d.


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