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Lesson Menu Main Idea and New Vocabulary Example 1:Add Integers with the Same Sign Key Concept:Add Integers with the Same Sign Example 2:Add Integers.

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Presentation on theme: "Lesson Menu Main Idea and New Vocabulary Example 1:Add Integers with the Same Sign Key Concept:Add Integers with the Same Sign Example 2:Add Integers."— Presentation transcript:

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2 Lesson Menu Main Idea and New Vocabulary Example 1:Add Integers with the Same Sign Key Concept:Add Integers with the Same Sign Example 2:Add Integers with the Same Sign Key Concept:Additive Inverse Property Example 3:Add Integers with Different Signs Example 4:Add Integers with Different Signs Key Concept:Add Integers with Different Signs Example 5:Add Integers with Different Signs Example 6:Add Integers with Different Signs Example 7:Add Integers with Different Signs Example 8:Real-World Example

3 Main Idea/Vocabulary Add integers. opposites additive inverse

4 Example 1 Add Integers with the Same Sign Find –6 + (–3). Start at 0. Move 6 units to the left to show –6. From there, move 3 units to the left to show –3. Answer: So, –6 + (–3) = –9. –6–3

5 Example 1 CYP A.–4 B.–2 C.0 D.4 Find –2 + (–2).

6 Key Concept 2

7 Example 2 Find –34 + (–21). Add Integers with the Same Sign – 34 + ( – 21) = –55Both integers are negative, so the sum is negative. Answer: So, –34 + (–21) = –55.

8 Example 2 CYP A.22 B.6 C.–6 D.–22 Find –14 + (–8).

9 Key Concept 3

10 Example 3 Add Integers with Different Signs Find 8 + (–7). Answer: So, 8 + (–7) = 1. +8 –7

11 Example 3 CYP A.–4 B.–2 C.2 D.4 Find 3 + (–1).

12 Example 4 Find –5 + 4. Add Integers with Different Signs Answer: So, –5 + 4 = –1. –5 +4

13 Example 4 CYP A.–11 B.–7 C.7 D.11 Find –9 + 2.

14 Key Concept 6

15 Example 5 Add Integers with Different Signs Find 2 + (–7). 2 + (–7) = –5Subtract absolute values; 7 – 2 = 5. Since 7 has the greater absolute value, the sum is negative. Answer: So, 2 + (–7) = –5.

16 Example 5 CYP A.14 B.2 C.–2 D.–14 Find 6 + (–8).

17 Example 6 Add Integers with Different Signs Find –9 + 6. – 9 + 6 = –3Subtract absolute values; 9 – 6 = 3. Since 9 has the greater absolute value, the sum is negative. Answer: So, –9 + 6 = –3.

18 Example 6 CYP A.12 B.10 C.–10 D.–12 Find –11 + 1.

19 Example 7 Add Integers with Different Signs Find 11 + (–4) + (–11). 11 + (–4) + (–11) = 11 + (–11) + (–4)Commutative Property (+) = [11 + (–11)] + (–4)Associative Property (+) = 0 + (–4)Additive Inverse Property = –4Additive Identity Property Answer: The solution is –4.

20 Example 7 CYP A.–12 B.–10 C.–7 D.–2 Find 5 + (–7) + (–5).

21 Example 8 FINANCIAL LITERACY Small businesses manage their inventory using integers. The cost of goods sold is calculated as starting inventory plus cost of items bought during the year plus a negative value on the ending inventory for the year. For example, a small horse farm owner might have a starting inventory of horses valued at $9,500, purchase a colt during the year for $2,000, and have an ending inventory value of $6,000. What is the cost of goods sold? Write an addition sentence to describe this situation. Then find the sum and explain its meaning.

22 Example 8 $9,500 + $2,000 + (–$6,000) = $11,500 + (–$6,000)$9,500 + $2,000 = $11,500 = $5,500Subtract the absolute values. Since $11,500 has the greater absolute value, the sum is positive. Answer: The cost of goods sold is $5,500.

23 Example 8 CYP A.Point E is 4 feet lower than point A. B.Point E is 6 feet lower than point A. C.Point E is 8 feet lower than point A. D.Point E is 10 feet lower than point A. ROLLER COASTERS The graphic shows the change in height at several points on a roller coaster. Write an addition sentence to find the height at point E in relation to point A. 20 + (–32) + 16 + (–10) = –6

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