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Published byMartin Heath Modified over 9 years ago
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On average, home heating uses more energy than any other system in a home About 45% of total energy use More than half of homes use natural gas.
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In the winter homes lose heat to the outside through conduction, convection, radiation, and infiltration These losses can be reduced by good home design, but there is always some loss of heat To keep the inside of a home warm the lost heat needs to be replaced
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Heating systems replace lost heat to keep your home warm Typical kinds of heating systems are: ◦ Gas furnaces that burn natural gas or propane ◦ Oil-fired furnaces burning heating oil ◦ Heat pumps that use electricity to move heat into the home ◦ Electrical heating that turns electricity directly into heat Many new homes are now incorporating passive solar features to capture more of the sun’s energy for heating
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Good Construction Techniques ◦ Making sure joints are sealed and tight ◦ Installing insulation uniformly and at sufficient depths ◦ Windows and doors function properly and shut well ◦ Ensuring penetrations for plumbing and electricity are well sealed ◦ Radiant and infiltration barriers ◦ Well constructed ventilation ductwork Good materials ◦ High efficiency windows reduce conductive and radiant heat losses ◦ Ceiling and wall insulation that performs better than standard materials
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Typically, the best ways to save energy in existing homes is: Sealing holes between the house and the attic and then adding attic insulation Sealing the ductwork that moves heated air throughout the home in some systems Tuning or replacing the heating and cooling equipment. Incorporating passive solar systems when possible
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More efficient heating systems ◦ Some types of systems, such as electric heating, use more energy than needed to heat a home. In mild climates heat pumps can use less energy to warm the house by the same amount. ◦ The efficiency of all systems has increased over time. Replacing older systems (20 years old or more) can save energy. Look for Energy Star systems. (www. energystar.gov)
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Modeling a home is a good way to determine the least expensive ways to save energy Over the next several lessons you will explore a simplified model of a building The initial model calculates heat lost from a home assuming the heat does not come on Models from other lessons will use more advance programming functions to make the model more realistic
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Scope: A model that estimates the rate of heat loss from a home where the inside and outside temperatures are held constant. The heat loss is used to calculate a drop in temperature Output: The rate of heat loss from a home, assuming the heat loss is uniformly distributed around the house. The temperature change over 30 minutes if that rate of heat loss continued
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Relationships: Heat loss is higher the greater the difference between the inside and outside temperatures ◦ More heat is lost if it is 72° inside and 32° outside versus being 68° inside and 58° outside. Heat loss is higher with more wall surface area separating the inside and outside ◦ If an outside wall is 10 feet long and 8 feet high it will lose more heat than a wall that is 5 feet long and 8 feet high because there are more paths for heat to flow through the wall.
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Relationships (continued): Heat loss is lower the greater the wall’s resistance to heat loss ◦ The resistance to heat loss of a building material is often called the R-value ◦ Different materials have different R-values Glass is low Wood is moderate Insulation is high ◦ Heat loss is reduced by using materials with a high R-value and by using more than one layer
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Relationships (continued): A building with more mass (more things) inside takes longer to cool down than one with less mass (fewer things) inside ◦ This is know as the heat capacity, which is calculated as the amount of heat needed to raise the temperature of an item by one degree ◦ Some materials, such as water and stone/brick, store more heat than others, such as wood and curtains. As time passes, more heat is lost
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Construction (continued): The greater the heat loss, the greater the temperature change The greater the heat capacity, the smaller the temperature change The more time that passes, the more heat is lost and so the greater the temperature change
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Inside is 22 °C, outside is 0 °C R-value is 5 m²·°C/W Surface Area: 650 m² Heat capacity inside house: 5,000,000 joule/ °C Calculation of temperature drop over 30 minutes (1800 seconds): ◦ Heat loss = (22 – 0)* 650/5 = 2,860 joule/second ◦ Temp. change = 2,860*1800/5,000,000 = 1.0 °C ◦ Final temperature = 22°C – 1.0° C = 21°C
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