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 Naming Formulas  Percent composition  Empirical formulas  Balancing Equations  Types of Reactions  Activity Series.

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Presentation on theme: " Naming Formulas  Percent composition  Empirical formulas  Balancing Equations  Types of Reactions  Activity Series."— Presentation transcript:

1  Naming Formulas  Percent composition  Empirical formulas  Balancing Equations  Types of Reactions  Activity Series

2  A molecule is held together by covalent bonds.  Valence electrons are shared.  Between non-metals i.e. H 2 O, CO 2, O 2, NO

3  Use prefixes 1mono- 2di- 3tri- 4tetra- 5penta- 6hexa- 7hepta- 8octa- 9nona- 10deca-

4  Use prefixes 1mono- 2di- 3tri- 4tetra- 5penta- 6hexa- 7hepta- 8octa- 9nona- 10deca-

5  Determine the mass percentage of each element in the compound. Mass of element x 100% mass of compound What is the percent composition of Fe 2 O 3 ? 2 Fe 2 x 55.8 = 111.6 3 O 3 x 16.0 = 48.0 Formula mass 159.6 %Fe = 111.6/159.6 = 70.0% % O = 48.0/159.6 = 30.0%

6 X (empirical formula) = molecular formula so x = molecular formula mass empirical formula mass

7  What is the molecular formula of the molecule that has an empirical formula of CH 2 O and a molar mass of 120.12 g/mol? Empirical formula mass: 12.0 + 2.0 + 16.0 = 30.0 amu X = 120.12 amu = 4 30.0 amu So C 4 H 8 O 4 is the molecular formula.

8  Find the empirical formula of a compound that contains 53.7% iron and 46.3% sulfur.  % composition  mass of 100 g sample  moles  mole ratio  53.7g x 1 mol/55.8g =.962 mol Fe 46.3g x 1 mol/32.1g = 1.44 mol S.962/.962 = 1, 1.44/.962 = 1.5 1:1.5 ratio x 2 = 2:3 ratio Fe 2 S 3

9  “Honkle Brif” H2H2 O2O2 N2N2  Cl 2  Br 2 I2I2 F2F2

10  Yields  Gas(g)  Precipitate  Solid(s) or down arrow  Liquid(l)  Aqueous (aq)

11  Balancing Equations  Synthesis (Combination)  Decomposition  Single Displacement (Replacement)  Double Displacement (Replacement)  Neutralization  Combustion

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