1. Units of Measurement
Meter m
Liter L
Celsius C

2. Mass is the amount of matter, weight is a measure of the gravitational pull on matter

3. SI Units Prefix Symbol Scientific notation Factor Example Mega M
1,000,000
megagram (Mg)
Kilo k
1 x 103
1,000
kilometer (km)
Hecto h
1 x 102
100
hectoliter (hL)
Deka
da or (D)
1 x 101 10
dekagram (Dg)
BASE UNIT
1 x 100 1
meter
Deci d
1 x 10-1 .1
deciliter (dL)
Centi c
1 x 10-2
.01
centimeter (cm)
Milli m
1 x 10-3
.001
milligram (mg)
Micro u
1 x 10-6
microgram (ug)
Nano n
1 x 10-9
nanometer (nm)
Pico p
1 x 10-12
picogram (pg)

4. Practice In each pair below, circle the larger
Millimeter
Centimeter
picometer
Micrometer
kilogram
Hectogram
deciliter
millileter

5. Basic SI Units Quantity Base unit Length meter (m) Mass gram (g) Time
second (s)
Volume
Liter (L)
Temperature
Kelvin (K) or Celsius (C)
Amount of substance
mole (mol)
Heat & Energy
joule (J)

6. Metric Conversion king henry Died by drinking chocolate milk
K h D base d c m
1.) cm= Dm
2.) g= cg
243.5
3.) mL= L
0.0238
4.) km= m
14800
5.) cg= dg
2.35

7. Temperature Celsius + 273 = Kelvin Kelvin -273 = Celsius 293 20°C = K
Use both the Kelvin and Celsius scale, to convert
Celsius = Kelvin
Kelvin -273 = Celsius
293
20°C = K
100
373 K = °C

8. Volume: measured in cubic centimeters (cm3) or liters
1 liter (L) = 1 cubic decimeter (dm3) = 1000 millileters (mL)
1 mL= 1 cm3

9. Volume can be measure by Length x x or the Water Displacement method
width
height

10. Volume can be measure by Length x width x height or
the Water Displacement method
Know the relationship between the following volume units…
L = mL = cm3 (or cc in medical lingo) 1
1000
1000

11. Density
Is the ratio of mass per unit of volume. How much matter is packed into a given amount of space
Density = mass ÷ volume
D= M V

12. The Density of a substance stays regardless of the size of the sample
The Density of a substance stays regardless of the size of the sample. For example: if you cut a block of copper in half, you have decreased both the mass and volume, the ratio of the 2 stays the same. This is called an Intensive Physical Property.
Constant

13. The appropriate units of density are: for solids for liquids
g/cm3
g/mL

14. Example problems:
A sample of aluminum metal has a mass of 8.4g. The volume of the sample is 3.1 cm3. Calculate the Density of aluminum.
D =
M = V
8.4
3.1
=2.7 g/cm3 2 sig figs

15. Example problems: 3.26 g/cm3 x 0.350 cm3 D = M V = 1.14 g
Diamond has a density of 3.26 g/cm3. What is the mass of a diamond that has a volume of cm3?
D = 3.26 g/cm3
M = ?
V = cm3
D = M V
3.26 g/cm3 x cm3
= 1.14 g
3 sig figs

16. Example problems:
What is the volume of a sample of liquid mercury that has a mass of 76.2 g, given that the density of mercury is 13.6 g/mL?
V = ?
M = 76.2 g
D = 13.6 g/mL D= M V
76.2 g
13.3 g/mL = mL =
5.73 mL

17. Reliable Measurements
refers to the closeness of the measure value is to the , or real, value.
refers to how a series of measurements are to one another.
Accuracy
Actual
Precision
Close

18. is calculated by subtracting the value from the value.
Error
accepted
Experimental

19. The is the ratio of an error to an accepted value.
percent error

20. % error = error x 100 = accepted value – experimental value x 100
accepted value accepted value

21. Example
An experiment finds the density of lead to be g/cm3. The literature value for the density of lead is g/cm3.

22. The error: accepted value – experimental value=
An experiment finds the density of lead to be g/cm3. The literature value for the density of lead is g/cm3.
The error: accepted value – experimental value=
13.34 – =
2.39

23. The error: accepted value – experimental value=
13.34 – = 2.39
The % error: error x 100 % =
accepted value
x 100 % =
13.34
17.9 %

24. Practice
Sara’s lab shows the atomic mass of aluminum to be What is her percent error if the accepted value is 27.0?
28.9 – 27.0 =
1.90
1.90/27.0 x 100% =
7.04%

25. Practice
What is the percent error in a measurement of the boiling point of bromine if the textbook value is 60.8 °C and the lab value is 40.6 °C?
60.8 °C – 40.6 °C =
20.2 °C
20.2 °C / 60.8 °C x 100% =
33.2%