Presentation is loading. Please wait.

Presentation is loading. Please wait.

10/18/2005Comp 120 Fall 20051 26 October Questions? Instruction Execution.

Similar presentations


Presentation on theme: "10/18/2005Comp 120 Fall 20051 26 October Questions? Instruction Execution."— Presentation transcript:

1 10/18/2005Comp 120 Fall 20051 26 October Questions? Instruction Execution

2 10/18/2005Comp 120 Fall 20052 Five Execution Steps Instruction Fetch Instruction Decode and Register Fetch Execution, Memory Address Computation, or Branch Completion Memory Access or R-type instruction completion Memory Read Completion INSTRUCTIONS TAKE FROM 3 - 5 CYCLES! A FSM looks at the op-code to determine how many...

3 10/18/2005Comp 120 Fall 20053 Use PC to get instruction and put it in the Instruction Register. Increment the PC by 4 and put the result back in the PC. Can be described succinctly using RTL "Register-Transfer Language" IR = Memory[PC]; IR is “Instruction Register” PC = PC + 4; What is the advantage of updating the PC now? Step 1: Instruction Fetch

4 10/18/2005Comp 120 Fall 20054 Read registers rs and rt in case we need them Compute the branch address in case the instruction is a branch RTL: A = Reg[IR[25-21]]; B = Reg[IR[20-16]]; ALUOut = PC + (sign-extend(IR[15-0]) << 2); We aren't setting any control lines based on the instruction type (we are busy "decoding" it in our control logic) Step 2: Instruction Decode and Register Fetch

5 10/18/2005Comp 120 Fall 20055 ALU is performing one of three functions, based on instruction type Memory Reference: ALUOut = A + sign-extend(IR[15-0]); R-type: ALUOut = A op B; Branch: if (A==B) PC = ALUOut; Step 3 (instruction dependent)

6 10/18/2005Comp 120 Fall 20056 Loads and stores access memory MDR = Memory[ALUOut]; MDR is Memory Data Register or Memory[ALUOut] = B; R-type instructions finish Reg[IR[15-11]] = ALUOut; Step 4 (R-type or memory-access)

7 10/18/2005Comp 120 Fall 20057 Reg[IR[20-16]]= MDR; Step 5 Memory Read Completion

8 10/18/2005Comp 120 Fall 20058 Summary:

9 10/18/2005Comp 120 Fall 20059 Data Path with Control (5.28)

10 10/18/2005Comp 120 Fall 200510 FSM Control (5.31)

11 10/18/2005Comp 120 Fall 200511 IFetch and Decode (5.32)

12 10/18/2005Comp 120 Fall 200512 Memory Ref (5.33)

13 10/18/2005Comp 120 Fall 200513 R-type (5.34)

14 10/18/2005Comp 120 Fall 200514 Branch (5.35)

15 10/18/2005Comp 120 Fall 200515 Jump (5.36)

16 10/18/2005Comp 120 Fall 200516 Full State Diagram

17 10/18/2005Comp 120 Fall 200517 FSM

18 10/18/2005Comp 120 Fall 200518 Highlight Who’s been to the fair? Go! You can have your picture taken with W!


Download ppt "10/18/2005Comp 120 Fall 20051 26 October Questions? Instruction Execution."

Similar presentations


Ads by Google