Download presentation
1
Recrystallization Impure benzoic acid
Benzoic acid after recrystallization
2
Benzoic Acid
3
Purification of Organic Compounds
Solids: Recrystallization Liquids: Distillation Solids and Liquids: Gas or liquid chromotography
4
Types of impurities Soluble Insoluble Partly Soluble
5
Solubility of benzoic acid in water
6
Dissolve sample in hot solvent
Compound crystallizes upon cooling
7
Impure benzoic acid in hot water
8
Insoluble material is removed by filtration
Add water and heat until all soluble material dissolves Insoluble material is removed by filtration
9
The hot solution is filtered to remove insoluble impurities
10
Use fluted filter paper to maximize surface area.
11
Put flask on hot plate. To avoid crystallization in the funnel:
Use GLASS funnel. Put flask on hot plate.
12
Boil off excess solvent
13
Boiling Sticks
14
Hot solution after filtration:
Cool Seed Scratch
15
Crystals form in the warm solution
Next: Cool, filter, wash, dry, weigh, mp
16
Cool in ice bath
17
Buchner funnel .. Heavy-walled tubing Filter flask Vacuum
18
Filter paper .. Put filter paper in Buchner funnel
19
Filter, Wash Filter and wash with cold solvent
20
Summary Purified benzoic acid Insoluble impurities Soluble impurities
21
Solubility Example Solubility g/100 mL Compound 25o 100o A I1 I2 1.0
1.5 0.0 80 50 0.0
22
Example A I1 I2 dissolves dissolves 100 mL water at 1000 insoluble
Solubility g/100 mL Compound 25o 100o A I1 I2 1.0 1.5 0.0 80 50 0.0 A = 10 g I1 = 1.0 g I2 = 1.0 g Total = 12.0 g 100 mL water at 1000 A I1 I2 dissolves dissolves insoluble Example
23
Example Cool to 25o A dissolves I1 dissolves I2 insoluble A I1
Solubility g/100 mL Compound 25o 100o A I1 I2 1.0 1.5 0.0 80 50 0.0 A = 10 g I1 = 1.0 g I2 = 1.0 g Total = 12.0 g 100 mL water at 1000 Cool to 25o A dissolves I1 dissolves I2 insoluble A I1 9.0 g crystallize 0 g crystallize Example Yield = 100 * 9.0/12.0 = 75%
24
Example 50 ml of water at 1000 A I1 I2 dissolves dissolves insoluble
Solubility g/100 mL Compound 25o 100o A I1 I2 1.0 1.5 0.0 80 50 0.0 A = 10 g I1 = 1.0 g I2 = 1.0 g Total = 12.0 g 50 ml of water at 1000 A I1 I2 dissolves dissolves insoluble Example
25
Example NOT PURE! Cool to 25o 50 mL water at 1000 A dissolves
Solubility g/100 mL Compound 25o 100o A I1 I2 1.0 1.5 0.0 80 50 0.0 A = 10 g I1 = 1.0 g I2 = 1.0 g Total = 12.0 g Cool to 25o 50 mL water at 1000 A dissolves I1 dissolves I2 insoluble A I1 9.5 g crystallize 0.25 g crystallize Yield = 100 * 9.75/12.0 = 81% Example NOT PURE!
26
What volume of solvent is needed to give the maximum yield of pure A?
Solubility of I1 = 1.5 g/100 mL 1.5 g 100 mL 1.0 g x mL = X = (100 mL * 1.0 g)/1.5 g = 67 mL Example
27
Example What is the yield of pure A from 67 mL solvent?
Solubility of A = 1.0 g/100 mL 1.0 g 100 mL X g 67 mL Example = X = (67 mL x 1.0 g) / 100 mL = 0.67 g Yield = 10.0 g g = 9.33 g % yield = 100 * 9.33 / 12 = 78%
28
Second Crop Boil off some solvent Cool, filter, wash, dry, weigh, mp
29
Fractional Crystallization
30
Recrystallization Solvents
Does not react with compound Large temperature coefficient of solution Low boiling point
31
Mixed Solvents Ethanol – Water Ether Pentane
Similar presentations
© 2024 SlidePlayer.com Inc.
All rights reserved.