1. Mechanical Systems For Al-Zakah Hospital
Graduation Project 2
Mechanical Systems For Al-Zakah Hospital
Students:
Mohammed Sawalhi ( )
Mohammed Younis ( )
Mohammed Hannon ( )
Nedal Al-Masri ( )
Aya Nairat ( )
Supervisor:
Dr. Iyad Assaf

2. Introduction:
In our project, we are going to Design the following Mechanical systems for Al Zakah hospital in Palestine-Tulkarm which consists of 7 floors two of them under the ground : 1- HVAC System “Heat, Ventilation & Air conditioning” 2- Plumbing System 3- Fire Fighting System 4- Medical Gases System.

3. Building’s Description
Country : Palestine / West bank .
City: Tulkarm.
Street Al-Montaza street .
Latitude:
Building face sits at south orientation.
The wind speed is greater than 5 m/s

4. Heating load Equations
Qs,cond = U A (Ti – To) .
Q s,vent = 1.2 Vvent (Ti – To).
Q L,vent = 3 Vvent (Wi- Wo).
Qtotal = Qs,cond + Qs,vent +Ql,vent

5. Heating Results: Floor No. Heating Load (Kw) (TON Ref.) (CFM)
Basement 2
27.38
7.823
Basement 1
Ground Floor
24.81
7.088
Second Floor
23.46
6.704
Third Floor
29.48
8.423
Fourth Floor
70.85
20.244
Fifth Floor
39.48
11.280
4512
Total heating
load
209.14
59.753

6. Boiler selection
Boiler capacity = (Q building + Q domestic hot water) * 1.1
= ( ) * 1.1 = KW
we select boiler model: FM500 that gives power = 500 KW

7. Cooling Equations: Qs| transmitted = A * SHG * SC * CLF . From glass
Qs = U * A * CLTD corc For Wall And Ceiling.
CLTD corr = ( CLTD + LM ) K + ( Tin ) + ( To – 29.4 ).
Qs| transmitted = A * SHG * SC * CLF From glass
Qs| convection = U * A * ( CLTD ) correction From glass
Qs| vent = 1.2 *A * ( To – T in ) .
QL = 3 * A ( W o –W in )
Qs| people = qs * n * CLF
QL| people = ql * n
Qs| lighting = W * CLF
Qs| equipment = qs * CLF
Ql| equipment = ql

8. Cooling Results Floor No. Cooling Load (Kw) (TON Ref.) Cooling Load
(CFM)
Basement 2
65.68
18.76
7504
Basement 1
Ground Floor
85.93
24.55
9820
Second Floor
57.77
16.5
6600
Third Floor
74.70
21.34
8536
Fourth Floor
141.36
40.39
16156
Fifth Floor
69.36
19.82
7928
Total Cooling
load
468.81
133.95
43580

9. Chiller Selection
Q chiller = Q cooling for building * 1.1 = KW = Ton Refr.
From the Petra catalogue according to the following data:
Ambient temperature = 95 (Fo)
Leaving chiller water temperature = 45 (Fo)
Q chiller = Ton Ref.
Frequency = 50Hz

10. Air Handling Units Selection
From Petra catalogue:

11. Fan coil selection:
From Petra catalogue As example: Doctor Room1 at ground floor

12. Fans selection:

13. Pumps selection: Chiller Pump From Salsmon catalogues:
m pump = (L/s ) & ΔH = 7.8m >> ΔP = Pa
L total= L to the farthest diffuser * 2 * 1.5 = 204 m
(ΔP/L) = 375 (Pa/m) Where < (ΔP/L) < 550
Model No from Salsmon catalogues
Boiler Pump From Salsmon catalogues: m pump = (Qs)/(Cp * ΔT) = 3.75 (L/s) m pump = 3.75 (L/s) , ΔH = 7.1m >> ΔP = Pa L total = 204 m (ΔP/L) = (Pa/m) Where 200 < (ΔP/L) < 550 Model No from Salmson catalogues

14. Duct Sizing

15. Steel Pipes Sizing

16. Plumbing Results
Potable water Sizing “Steel Pipes”: As an Example for 3rd Floor:

17. Potable Pump Head
(ΔP) pump = (ΔP) friction + fitting ± (ΔP) head + (ΔP) flow
Where:
- (ΔP) friction + fitting = 1.8 * (ΔP) friction
> (ΔP) friction = (ΔP/L) AB * LAB + (ΔP/L) BC * LBC + (ΔP/L) CD * LCD
- (ΔP) friction + fitting = kpa (ΔP) head = ρ * g * H = Kpa
- (ΔP) flow = 15*6.8 = 102 Kpa
(ΔP) pump = Kpa
Flow rate |Pump = L/s

19. Drainage System:
At each number of fixtures we find the diameter size from tables.
Main Results : Horizontal branch diameter: 4"
Riser diameter: 4"
Building drain diameter: 4"
Building drain slope: 1%

21. Fire Fighting System
In this project, we used 1 landing valve and 1 cabinet for each floor:
Cabinet: Residual pressure = 65 PSI
Size = 1½"
Landing valve: Residual pressure = 100 PSI
Size = 2½"
Stand pipe diameter = 4"
Pump flow rate = 500 g.p.m
Tank volume = ((Flow rate * 3.8 * t) / (1000))
= ((500*3.8*120)/ (1000))
= 228 m3 .

22. Fire Fighting Pump head
(ΔP) pump = (ΔP) friction + fitting ± (ΔP) head + (ΔP) flow
Where:
- (ΔP) friction + fitting = 1.5 * (ΔP) friction
> (ΔP) friction = (ΔP/L) AB * LAB + (ΔP/L) BC * LBC + (ΔP/L) CD * LCD…
- (ΔP) friction + fitting = kpa (ΔP) head = ρ * g * H = 1000* 9.81* 3 = -29 Kpa
- (ΔP) flow = 100*6.8 Kpa = 680 kpa
(ΔP) pump = Kpa
Jockey Pump Flow rate = (5 – 10) g.p.m
(ΔP)Jockey pump = (ΔP) pump + (10 PSI* 6.8) = kpa

24. FM-200 system: Mass of clean agent: M = (V/S) [C / (100 – C)]
Leakage rate:
Leakage rate = * Pc (8.7)
> Pc = g * Ho * (rm – ra)
Results :

25. Volume of FM-200 Cylinder:
Weight = (ρ * g * Volume)
Total mass * g = (ρ * g * Volume)
Volume = (Total mass/ ρ) = ( /100) = 3.98 m3

27. Medical Gases
Results As an Example for 3rd floor:

28. Medical Gases Volume of cylinders for each gas: 1- Oxygen gas:
54.5 SCFM >> (L/s) >> (m3/s)
2- Medical vacuum:
92.5 SCFM >> 42 (L/s) >> (m3/s)
3- Medical air:
7 SCFM >> 3.1 (L/s) >> (m3/s)

30. Thank You