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Section Solving Linear Systems Algebraically

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Presentation on theme: "Section Solving Linear Systems Algebraically"— Presentation transcript:

1 Section 3.2 - Solving Linear Systems Algebraically
ALGEBRA TWO CHAPTER THREE: SYSTEMS OF LINEAR EQUATIONS AND INEQUALITIES Section Solving Linear Systems Algebraically

2 LEARNING GOALS Goal One - Use algebraic methods to solve linear systems. Goal Two - Use linear systems to model real-life situations.

3 THE SUBSTITUTION METHOD
ALGEBRAIC SOLUTIONS THE SUBSTITUTION METHOD STEP 1: Solve one of the equations for one of its variables. STEP 2: Substitute the expression from Step 1 into the other equation and solve for the other variable. STEP 3: Substitute the value from Step 2 into the revised equation from Step 1 and solve. 1

4 STEP 1: Solve one of the equations for one variable.
SUBSTITUTION METHOD Use the substitution method to solve the linear system: Equation x + y = -2 Equation x - 3y = 17 STEP 1: Solve one of the equations for one variable. 6x + y = -2 Write original equation y = -6x -2 Subtract 6x from each side. 1

5 STEP 2: Substitute into other equation.
SUBSTITUTION METHOD Use the substitution method to solve the linear system: Equation x + y = -2 Equation x - 3y = 17 STEP 2: Substitute into other equation. 6x + y = -2 Write original equation y = -6x -2 Subtract 6x from each side. 4x - 3(-6x - 2) = 17 Substitute into other equation. 4x + 18x + 6 = 17 Use distributive property 22x = 11 Combine like terms. x = 1/2 Simplify 1

6 SUBSTITUTION METHOD STEP 3: Substitute into revised equation (Eq 1).
Use the substitution method to solve the linear system: Equation x + y = -2 Equation x - 3y = 17 STEP 3: Substitute into revised equation (Eq 1). y = -6x - 2 Write revised equation y = -6(1/2) - 2 Substitute 1/2 for x. y = = -5 Simplify y = -5 The solution to this linear system is (1/2 , -5). 1

7 STEP 1: Solve one of the equations for one variable.
SUBSTITUTION METHOD Use the substitution method to solve the linear system: Equation x - y = 6 Equation x + 2y = -9 STEP 1: Solve one of the equations for one variable. 1

8 STEP 1: Solve one of the equations for one variable.
SUBSTITUTION METHOD Use the substitution method to solve the linear system: Equation x - y = 6 Equation x + 2y = -9 STEP 1: Solve one of the equations for one variable. 2x - y = 6 Write original equation -y = -2x + 6 Subtract 2x from each side. y = 2x - 6 Multiply by -1. 1

9 STEP 2: Substitute into other equation.
SUBSTITUTION METHOD Use the substitution method to solve the linear system: Equation x - y = 6 Equation x + 2y = -9 STEP 2: Substitute into other equation. 2x + 2(2x - 6) = -9 Substitute into other equation. 2x + 4x - 12 = -9 Use distributive property 6x = 3 Combine like terms. x = 1/2 Simplify 1

10 STEP 3: Substitute into revised equation.
SUBSTITUTION METHOD Use the substitution method to solve the linear system: Equation x - y = 6 Equation x + 2y = -9 STEP 3: Substitute into revised equation. y = 2x - 6 Write revised equation y = 2(1/2) - 6 Substitute 1/2 for x. y = = -5 Simplify y = -5 The solution to this linear system is (1/2 , -5). 1

11 THE LINEAR COMBINATION METHOD
ALGEBRAIC SOLUTIONS THE LINEAR COMBINATION METHOD STEP 1: Multiply one or both of the equations by a constant to obtain coefficients that differ only in sign for one of the variables. STEP 2: Add the revised equations from Step 1. Combining like terms will eliminate one of the variables. Solve for the remaining variable. STEP 3: Substitute the value from Step 2 into either one of the original equations and solve for the other variable. 1

12 Use the linear combination method to solve the linear system:
Equation x + 3y = 3 Equation x + 4y = 4 STEP 1: Multiply by a constant. 6x + 3y = 3 times 4 24x + 12y = 12 8x + 4y = 4 times -3 -24x - 12y = -12 STEP 2: Add the equations. 0 = 0 Because the statement 0 = 0 is always true, there are infinitely many solutions. 1

13 Use the linear combination method to solve the linear system:
Equation x + 2y = 0 Equation x - 5y = 17 STEP 1: Multiply by a constant. 9x + 2y = 0 times 1 9x + 2y = 0 3x - 5y = 17 times -3 -9x + 15y = -51 17y = -51 STEP 2: Add the equations. y = -51/17 y = -3 1

14 Use the linear combination method to solve the linear system:
Equation x + 2y = 0 Equation x - 5y = 17 STEP 3: Substitute into either original equation. 9x + 2y = 0 Write equation The solution to the linear system is (2/3 , -3) 9x + 2(-3) = 0 Substitute -3 for y. 9x + (-6) = 0 Multiply 9x + (-6) + 6 = 0 + 6 Add 6 to each side 9x/ 9 = 6/9 Divide each side by 9 x = 2/3 Simplify 1

15 Use the linear combination method to solve the linear system:
Equation x - 3y = 5 Equation x + 9y = 12 STEP 1: Multiply by a constant. 2x - 3y = 5 times 3 6x - 9y = 15 -6x + 9y = 12 times 1 -6x + 9y = 12 0 = 27 STEP 2: Add the equations. Because the statement 0 = 27 is never true, there are no solutions to this system. 1

16 LINEAR COMBINATION METHOD STEP 1: Multiply by a constant.
Use the linear combination method to solve the linear system: Equation x + 6y = 1 Equation x + 2y = -3 STEP 1: Multiply by a constant. 11x + 6y = 1 3x + 2y = -3 1

17 Use the linear combination method to solve the linear system:
Equation x + 6y = 1 Equation x + 2y = -3 STEP 1: Multiply by a constant. 11x + 6y = 1 times 1 11x + 6y = 1 3x + 2y = -3 times -3 -9x - 6y = 9 2x = 10 STEP 2: Add the equations. x = 5 1

18 Use the linear combination method to solve the linear system:
Equation x + 6y = 1 Equation x + 2y = -3 STEP 3: Substitute into either original equation. 3x + 2y = -3 Write equation The solution to the linear system is (5, -9) 3(5) + 2y = -3 Substitute 5 for x. 15 + 2y = -3 Multiply 15 + 2y - 15 = Subtract 15 2y/ 2 = -18/2 Divide each side by 2 y = -9 Simplify 1

19 ASSIGNMENT READ & STUDY: pg WRITE: pg #11, #15, #21, #23, #27, #33, #35, #41, #49


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