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Estimating Crowds.

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Presentation on theme: "Estimating Crowds."— Presentation transcript:

1 Estimating Crowds

2 WARM UP What is the largest gathering of people have you ever been involved in? How many people were involved? How do you think the event counted the people?

3 Estimating Crowds 5 Feet

4 Use the previous value to estimate the size of a crowd that is 10 feet deep on both sides of the street standing along a 1-mile section of a parade route. {10 Feet {10 Feet 1 Mile = 5,280 Feet

5 So our ratio is ________ Area = 5,280 x 10 = 52,800 ft2
Use the previous value to estimate the size of a crowd that is 10 feet deep on both sides of the street standing along a 1-mile section of a parade route. So our ratio is ________ Area = 5,280 x 10 = 52,800 ft2 Multiply the ratio by the area: ________ x 52,800 =____________ x 2 Final Answer: ____________

6 Our ratio is The area = 52,800 ft2 x 52,800 =21,120 x 2
One rule of thumb for estimating crowds is that each person occupies 2.5 ft2. Use this rule to estimate the size of the crowd. Our ratio is The area = 52,800 ft2 x 52,800 =21,120 x 2 Final Answer: 42,240

7 Our ratio is 6/9 Area = 3 yd. x 18 ft. = 9 ft. x 18 ft. = 162 ft.
Six people fit comfortably in a 3 ft. by 3 ft. area. Use this value to estimate the size of a crowd that is 3 yards deep and 18 feet long. Our ratio is 6/9 Area = 3 yd. x 18 ft. = 9 ft. x 18 ft. (*Units are based on the ratio’s units) = 162 ft. 6/9 x 162 = 108 people

8 Our ratio is 9/16 ft. Area = 2 yd. x 1 mile. = 6 ft. x 5,280 ft.
Nine people fit comfortably in a 4 ft. by 4 ft. area. Use this value to estimate the size of a crowd that is 2 yards deep and 1 mile long. Our ratio is 9/16 ft. Area = 2 yd. x 1 mile. = 6 ft. x 5,280 ft. (*Units are based on the ratio’s units) = 31,680 ft. 9/16 x 31,680 = 17,820 people

9 1 mile = 5,280 feet 12 inches = 1 foot 5,280 x 12 = 63,360 in.
When the PS4 was released, the line was single file for 1 mile. If each person occupies 18 inches, how many were in the line? 1 mile = 5,280 feet 12 inches = 1 foot 5,280 x 12 = 63,360 in. 63,360 / 18 = 3,520 people

10 Practice Problem A basketball court is 94 feet by 50 feet. Eight fans can fit next to each other in a 3 ft. by 3 ft. area. How many kids would you estimate can fit side by side over the entire floor? 94 x 50 = 4700


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