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Recrystallization Impure benzoic acid
Benzoic acid after recrystallization
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Purification of Organic Compounds
Solids: Recrystallization Liquids: Distillation Solids and Liquids: Gas or liquid chromotography
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Types of impurities Soluble Insoluble Partly Soluble
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Solubility of benzoic acid in water
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Dissolve sample in hot solvent
Compound crystallizes upon cooling
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Impure benzoic acid in hot water
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Add water and heat until all soluble material dissolves
Insoluble material is removed by filtration
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The hot solution is filtered to remove insoluble impurities
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Use fluted filter paper to maximize surface area.
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Use GLASS funnel. Put flask on hot plate.
To avoid crystallization in the funnel: Use GLASS funnel. Put flask on hot plate.
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Boil off excess solvent
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Boiling Sticks
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Hot solution after filtration:
Cool Seed Scratch
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Cool, filter, wash, dry, weigh, mp
Crystals form in the warm solution Next: Cool, filter, wash, dry, weigh, mp
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.. Buchner funnel Heavy-walled tubing Filter flask Vacuum
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Put filter paper in Buchner funnel
.. Put filter paper in Buchner funnel
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Filter and wash with cold solvent
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Purified benzoic acid Insoluble impurities Soluble impurities
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Solubility Example Solubility g/100 mL Compound 25o 100o A I1 I2 1.0
1.5 0.0 80 50 0.0
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A I1 I2 dissolves dissolves 100 mL water at 1000 insoluble
Solubility g/100 mL Compound 25o 100o A I1 I2 1.0 1.5 0.0 80 50 0.0 A = 10 g I1 = 1.0 g I2 = 1.0 g Total = 12.0 g 100 mL water at 1000 A I1 I2 dissolves dissolves insoluble
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Cool to 25o A dissolves I1 dissolves I2 insoluble A I1
Solubility g/100 mL Compound 25o 100o A I1 I2 1.0 1.5 0.0 80 50 0.0 A = 10 g I1 = 1.0 g I2 = 1.0 g Total = 12.0 g 100 mL water at 1000 Cool to 25o A dissolves I1 dissolves I2 insoluble A I1 9.0 g crystallize 0 g crystallize Yield = 100 * 9.0/12.0 = 75%
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50 ml of water at 1000 A I1 I2 dissolves dissolves insoluble
Solubility g/100 mL Compound 25o 100o A I1 I2 1.0 1.5 0.0 80 50 0.0 A = 10 g I1 = 1.0 g I2 = 1.0 g Total = 12.0 g 50 ml of water at 1000 A I1 I2 dissolves dissolves insoluble
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NOT PURE! Cool to 25o 50 mL water at 1000 A dissolves I1 dissolves
Solubility g/100 mL Compound 25o 100o A I1 I2 1.0 1.5 0.0 80 50 0.0 A = 10 g I1 = 1.0 g I2 = 1.0 g Total = 12.0 g Cool to 25o 50 mL water at 1000 A dissolves I1 dissolves I2 insoluble A I1 9.5 g crystallize 0.25 g crystallize Yield = 100 * 9.75/12.0 = 81% NOT PURE!
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What volume of solvent is needed to give the maximum yield of pure A?
Solubility of I1 = 1.5 g/100 mL 1.5 g 100 mL 1.0 g x mL = X = (100 mL * 1.0 g)/1.5 g = 67 mL
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What is the yield of pure A from 67 mL solvent?
Solubility of A = 1.0 g/100 mL 1.0 g 100 mL X g 67 mL = X = (67 mL x 1.0 g) / 100 mL = 0.67 g Yield = 10.0 g g = 9.33 g % yield = 100 * 9.33 / 12 = 78%
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