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2.5 Absolute Value Equations and Inequalities

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1 2.5 Absolute Value Equations and Inequalities
Evaluate and graph the absolute value function Solve absolute value equations Solve absolute value inequalities

2 The Absolute Value Function (1 of 2)
The absolute value function is defined by ƒ(x) = |x|. The following See the Concept (next slide) describes many of the properties of this function.

3 The Absolute Value Function (2 of 2)

4 Absolute Value Function Alternate Formula
That is, regardless of whether a real number x is positive or negative, the expression equals the absolute value of x. Examples:

5 Example: Analyzing the graph of y = |ax + b| (1 of 2)
For the linear function f, graph y = f (x) and y = |f (x)| separately. Discuss how the absolute value affects the graph of f. f(x) = − 2x + 4 (For continuity of the solution, it appears completely on the next slide.)

6 Example: Analyzing the graph of y = |ax + b| (2 of 2)
The graph of y = | −2x + 4| is a reflection of f across the x-axis when y = −2x + 4 is below the x-axis.

7 Absolute Value Equations (1 of 6)
Solutions to |x| = k with k > 0 are given by x = ±k. These concepts can be illustrated graphically.

8 Absolute Value Equations (2 of 6)
Solving |x| = 5 Graphically Two solutions: −5, 5

9 Absolute Value Equations (3 of 6)
Solving |x| = 5 Graphically Two solutions: −k, k

10 Absolute Value Equations (4 of 6)
Solutions to |ax + b| = k are given by ax + b = ±k.

11 Absolute Value Equations (5 of 6)

12 Absolute Value Equations (6 of 6)
Let k be a positive number. Then |ax + b| = k is equivalent to ax + b = ±k.

13 Example: Solving an absolute value equation (1 of 3)
Solve the equation |2x + 5| = 2 graphically, numerically, and symbolically. Solution Graph Y1 = abs(2x + 5) and Y2 = 2 Solutions: − 3.5, 1.5

14 Example: Solving an absolute value equation (2 of 3)
Table Y1 = abs(2x + 5) and Y2 = 2 Solutions to y1 = y2 are −3.5 and −1.5.

15 Example: Solving an absolute value equation (3 of 3)

16 Absolute Value Inequalities (1 of 2)

17 Absolute Value Inequalities (2 of 2)
Let solutions to |ax + b| = k be s1 and s2, where s1 < s2 and k > |ax + b| < k is equivalent to s1 < x < s2. 2. |ax + b| > k is equivalent to x < s1 or x > s2. Similar statements can be made for inequalities involving ≤ or ≥.

18 Example: Solving inequalities involving absolute values symbolically
Solve the inequality |2x − 5| ≤ 6 symbolically. Write the solution set in interval notation.

19 Absolute Value Inequalities (Alternative Method)
Let k be a positive number. 1. |ax + b| < k is equivalent to −k < ax + b < k. 2. |ax + b| > k is equivalent to ax + b < −k or ax + b > −k. Similar statements can be made for inequalities involving ≤ or ≥.

20 Example: Solving absolute value inequalities
Solve the inequality |4 − 5x | ≤ 3. Write your answer in interval notation. Solution |4 − 5x| ≤ 3 is equivalent to the three-part inequality


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