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Advanced Engineering Mathematics 6th Edition, Concise Edition

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1 Advanced Engineering Mathematics 6th Edition, Concise Edition
by Peter V. O’Neil

2 Ordinary Differential Equations
Part 1: Ordinary Differential Equations Ch1: First-Order Differential Equations Ch2: Second-Order Differential Equations Ch3: The Laplace Transform Ch4: Series Solutions

3 Differential equation --- contains derivatives
e.g., or or y : function of x, x : independent variable (b) Ordinary differential equation – involves only total derivatives Partial differential equation – involves partial derivatives What is

4 (c) The order of a differential equation e. g
(c) The order of a differential equation e.g., ○ The solution of a differential equation is a function y(x) of independent variable x that may be defined on e.g., i) , solution: y = sin2x for ii) , solution: y = xlnx – x for x > 0

5 Ch. 1: First-Order Differential Equations
1.1. Preliminary Concepts ○ First-order differential equation: -- involves a first but no higher derivatives e.g., y:function of x x:independent variable : solution

6 1.1.1. General and Particular Solutions
General solution: arbitrary constant Substitute into (A) Particular solutions: k = 1, ; k = 2 , k = ,

7 1.1.2. Implicitly Defined Solutions
○ Explicit function: Implicit function: e.g., , (Explicit solution) (Implicit solution)

8 1.1.3. Integral Curves ○ Example 1.1: General solution:
-- Help to comprehend the behavior of solution ○ Example 1.1: General solution:

9 1.1.4. Initial Value Problems
○ initial condition Graphically, the particular integral curve passes through point ( ) The objective is to obtain a unique solution ○ Example 1.4: , initial condition General solution: ,

10 -- A set of line segments tangent to a curve
Direction Field -- A set of line segments tangent to a curve -- Give a rough outline of the shape of the curve ○ Giving , instead of solving for y, solving for

11 -- A set of line segments tangent to a curve
Direction Field -- A set of line segments tangent to a curve -- Give a rough outline of the shape of the curve ○ Giving , instead of solving for y, solving for 11

12 Slope: , General Solution:
○ Example 1.5: Slope: , General Solution: Figure 1.5. Direction field for y'= y² and integral curves through (0,1), (0,2), (0,3), - 1, (0, - 2), and (0, - 3).

13 1.2. Separable Equations

14 ○ Example 1.7: , (the general solution) y = 0 is a solution, called a singular solution, it cannot be obtained from the general solution

15 1.3. Linear Differential Equations -------- (A)
(1) Find integrating factor: (2) Multiply (A) by (3)

16 ○ Example 1.14: i) Integrating factor ii) Multiply the equation by , iii) iv) Integrate

17 1.4. Exact Differential Equations
can be written as (A) If , s.t. and (implicitly define the solution) : potential function

18 ○ Example 1.17: Let From

19 * We can start with , then as well
From Solution: * We can start with , then as well 19

20 c(y) is not independent of x No potential function
* Not every is exact e.g. From c(y) is not independent of x No potential function

21 Theorem 1.1: Exactness is exact iff (a) If is exact, then s.t.
(b) If , show s.t.

22 Let : any point

23 ○ Example : 1.5. Integrating Factors If : not exact But : exact
is not exact 1.5. Integrating Factors If : not exact But : exact integrating factor

24 . ○ How to find : exact, Try as , or ○ Example 1.21:
The equation is not exact

25 Consider Let Try (B) Integrate

26 (A) Let be the potential function The implicit solution: The explicit solution:

27 ○ Example 1.22: Let Find integrating factor by

28 Try This cannot be solved for as a function of x (ii) Likewise, let

29 (iii) Try (B) Divide by

30 : independent Multiply (A) by Let Form

31 From Obtain the potential function The implicit solution: or

32 1.6. Homogeneous, Bernoulli, and Riccati Eqs.
1.6.1 Homogeneous Equation: (A) * A homogeneous equation is always transformed into a separable one by letting ↑=1 (A)

33 ○ Example 1.25: Let (A)

34 1.6.2. Bernoulli Equation linear separable
can be transformed into linear by

35 ○ Example 1.27: Let (A) Multiply by (linear) Integrating factor:

36 Riccati Equation Let S(x) be a solution and let The Riccati equation is transformed into linear ○ Example 1.28: By inspection, is a solution of (A) Let

37 (linear) Integrating factor: Integrate and Solution:

38 Initial Value Problems:
1.8. Existence and Uniqueness for Solutions of Initial Value Problems Initial Value Problems: The problem may have no solution and may have multiple solutions ○ Example 1.30: The equation is separable and has solution The equation has no real solution. is not a solution because it does not satisfy the initial condition.

39 ○ Example 1.31: The equation has solution This problem has multiple solutions i, Trivial solution: ii, Define Consider All satisfy the initial condition

40 ○ Theorem 1.2: If f, : continuous in , then s.t.
The initial value problem has a unique solution defined on The size of h depends on f and

41 the entire plane and hence on
○ Example 1.31: not continuous on (x, 0) ○ Example:The problem : both continuous on the entire plane and hence on s.t. the problem has a unique solution in Solve the problem , which is valid for , we can take 41

42 ○ Theorem 1.3: : continuous on I The problem , has a unique solution defined Proof: From the general solution of the linear equation and the initial condition , the solution of the initial value problem is : continuous on I, the solution is defined

43 Homework 1 Chapter 1 Sec.1.1: 1, 2, 7, 12 Sec.1.2: 1, 2, 11 Sec.1.3: 1 Sec.1.4: 1 Sec.1.5: 1

44 1.5(1): Determine a test involving M and N to tell
when has an integrating factor that is a function of y only. Ans: Let be an integrating factor such that is exact. Then,

45 must be independent of x.
The test is then that must be independent of x. 45

46 Homework 2 Chapter 1 Sec.1.6: 15, 16, 20, 21 Sec.1.8: 1, 3, 5

47 Chapter 2: Second-Order Differential Equations
2.1. Preliminary Concepts ○ Second-order differential equation e.g., Solution: A function satisfies , (I : an interval)

48 ○ Linear second-order differential equation
Nonlinear: e.g., 2.2. Theory of Solution ○ Consider y contains two parameters c and d

49 The graph of Given the initial condition

50 Given another initial condition
The graph of ◎ The initial value problem: ○ Theorem 2.1: : continuous on I, has a unique solution

51 ○ Theorem 2.2: : solutions of Eq. (2.2)
2.2.1.Homogeous Equation ○ Theorem 2.2: : solutions of Eq. (2.2) solution of Eq. (2.2) : real numbers Proof:

52 ※ Two solutions are linearly independent.
Their linear combination provides an infinity of new solutions ○ Definition 2.1: f , g : linearly dependent If s.t or ; otherwise f , g : linearly independent In other words, f and g are linearly dependent only if for

53 ○ Wronskian test -- Test whether two solutions of a homogeneous differential equation are linearly independent Define: Wronskian of solutions to be the 2 by 2 determinant

54 ○ Let If : linear dep., then or Assume

55 ○ Theorem 2.3: 1) Either or 2) : linearly independent iff Proof (2): (i) (if : linear indep. (P), then (Q) if ( Q) , then : linear dep. ( P) ) : linear dep.

56 (ii) (if (P), then : linear indep. (Q)
if : linear dep. ( Q), then ( P)) : linear dep., ※ Test at just one point of I to determine linear dependency of the solutions

57 。 Example 2.2: are solutions of : linearly independent

58 。 Example 2.3: Solve by a power series method The Wronskian of at nonzero x would be difficult to evaluate, but at x = 0 are linearly independent

59 ○ Definition 2.2: ◎ Find all solutions 1. : linearly independent
: fundamental set of solutions : general solution : constant ○ Theorem 2.4: : linearly independent solutions on I Any solution is a linear combination of

60 Proof: Let be a solution.
Show s.t. Let and Then, is the unique solution on I of the initial value problem

61 2. 2. 2. Nonhomogeneous Equation ○ Theorem 2
Nonhomogeneous Equation ○ Theorem 2.5: : linearly independent homogeneous solutions of : a nonhomogeneous solution of any solution has the form

62 Proof: Given , solutions
: a homogenous solution of : linearly independent homogenous solutions (Theorem 2.4)

63 1. Find the general homogeneous solutions
○ Steps: 1. Find the general homogeneous solutions of 2. Find any nonhomogeneous solution of 3. The general solution of is 2.3. Reduction of Order -- A method for finding the second independent homogeneous solution when given the first one

64 ○ Let Substituting into ( : a homogeneous solution ) Let (separable)

65 For symlicity, let c = 1, 。 Example 2.4: : a solution Let
: independent solutions 。 Example 2.4: : a solution Let

66 Substituting into (A), For simplicity, take c = 1, d = 0 : independent The general solution:

67 2. 4. Constant Coefficient Homogeneous A, B : numbers ----- (2
2.4. Constant Coefficient Homogeneous A, B : numbers (2.4) The derivative of is a constant (i.e., ) multiple of Constant multiples of derivatives of y , which has form , must sum to 0 for (2,4) ○ Let Substituting into (2,4), (characteristic equation)

68 i) Solutions : : linearly independent The general solution:

69 。 Example 2.6: Let , Then Substituting into (A), The characteristic equation: The general solution:

70 ii) By the reduction of order method, Let Substituting into (2.4)

71 Choose : linearly independent The general sol. : 。 Example 2
Choose : linearly independent The general sol.: 。 Example 2.7: Characteristic eq. : The repeated root: The general solution:

72 iii) Let The general sol.:

73 。 Example 2.8: Characteristic equation: Roots: The general solution: ○ Find the real-valued general solution 。 Euler’s formula:

74 Maclaurin expansions:

75 。 Eq. (2.5),

76 Find any two independent solutions Take
The general sol.:

77 2.5. Euler’s Equation , A , B : constants -----(2.7)
Transform (2.7) to a constant coefficient equation by letting

78 Substituting into Eq. (2. 7), i. e. , --------(2
Substituting into Eq. (2.7), i.e., (2.8) Steps: (1) Solve (2) Substitute (3) Obtain

79 Characteristic equation: Roots: General solution:
。 Example 2.11: (A) (B) (i) Let Substituting into (A) Characteristic equation: Roots: General solution:

80 ○ Solutions of constant coefficient linear equation have the forms:
Solutions of Euler’s equation have the forms:

81 2.6. Nonhomogeneous Linear Equation ------(2.9)
The general solution: ◎ Two methods for finding (1) Variation of parameters -- Replace with in the general homogeneous solution Let Assume (2.10) Compute

82 Substituting into (2.9), -----------(2.11) Solve (2.10) and (2.11) for
Likewise,

83 。 Example 2. 15: ------(A) i) General homogeneous solution : Let
。 Example 2.15: (A) i) General homogeneous solution : Let . Substitute into (A) The characteristic equation: Complex solutions: Real solutions: :independent

84 ii) Nonhomogeneous solution Let

85 iii) The general solution:

86 (2) Undetermined coefficients Apply to A, B: constants Guess the form of from that of R e.g. : a polynomial Try a polynomial for : an exponential for Try an exponential for

87 。 Example 2.19: ---(A) It’s derivatives can be multiples of or Try Compute Substituting into (A),

88 : linearly independent
and The homogeneous solutions: The general solution:

89 。 Example 2. 20: ------(A) , try Substituting into (A),
。 Example 2.20: (A) , try Substituting into (A), * This is because the guessed contains a homogeneous solution Strategy: If a homogeneous solution appears in any term of , multiply this term by x. If the modified term still occurs in a homogeneous solution, multiply by x again

90 Try Substituting into (A),

91 ○ Steps of undetermined coefficients: (1) Find homogeneous solutions (2) From R(x), guess the form of If a homogeneous solution appears in any term of , multiply this term by x. If the modified term still occurs in a homogeneous solution, multiply by x again (3) Substitute the resultant into and solve for its coefficients

92 ○ Guess from Let : a given polynomial , : polynomials with unknown coefficients
Guessed

93 2.6.3. Superposition Let be a solution of is a solution of (A)

94 。 Example 2.25: The general solution: where homogeneous solutions

95 Chapter 3: The Laplace Transform
3.1. Definition and Basic Properties 。 Objective of Laplace transform -- Convert differential into algebraic equations ○ Definition 3.1: Laplace transform s.t. converges s, t : independent variables * Representation:

96 。Example 3.2: Consider

97

98 Not every function has a Laplace transform
* Not every function has a Laplace transform. In general, can not converge 。Example 3.1:

99 ○ Definition 3.2.: Piecewise continuity (PC) f is PC on if there are finite points s.t. and are finite i.e., f is continuous on [a, b] except at finite points, at each of which f has finite one-sided limits

100 If f is PC on [0, k], then so is and
exists

101 ◎ Theorem 3.2: Existence of f is PC on If Proof:

102 * Theorem 3.2 is a sufficient but not a necessary
condition.

103 * There may be different functions whose Laplace transforms are the same e.g., and have the same Laplace transform ○ Theorem 3.3: Lerch’s Theorem * Table 3.1 lists Laplace transforms of functions

104 ○ Theorem 3. 1: Laplace transform is linear Proof: ○ Definition 3. 3:
○ Theorem 3.1: Laplace transform is linear Proof: ○ Definition 3.3:. Inverse Laplace transform e.g., * Inverse Laplace transform is linear

105 3.2 Solution of Initial Value Problems Using Laplace Transform ○ Theorem 3.5: Laplace transform of f: continuous on : PC on [0, k] Then, (3.1)

106 Proof: Let

107 ○ Theorem 3.6: Laplace transform of : PC on [0, k] for s > 0, j = 1,2 … , n-1

108 。 Example 3.3: From Table 3.1, entries (5) and (8)

109

110 ○ Laplace Transform of Integral
From Eq. (3.1),

111 3.3. Shifting Theorems and Heaviside Function
3.3.1.The First Shifting Theorem ◎ Theorem 3.7: ○ Example 3.6: Given

112 ○ Example 3.8:

113 3.3.2. Heaviside Function and Pulses
○ f has a jump discontinuity at a, if exist and are finite but unequal ○ Definition 3.4: Heaviside function 。 Shifting

114 。 Laplace transform of heaviside function

115 3.3.3 The Second Shifting Theorem
Proof:

116 ○ Example 3.11: Rewrite

117 ◎ The inverse version of the second shifting theorem ○ Example 3.13:
where rewritten as

118

119

120 3.4. Convolution

121 ◎ Theorem 3.9: Convolution theorem Proof:

122 ◎ Theorem 3.10: ○ Exmaple 3.18 ◎ Theorem 3.11: Proof :

123 ○ Example 3.19:

124 3.5 Impulses and Dirac Delta Function
○ Definition 3.5: Pulse ○ Impulse: ○ Dirac delta function: A pulse of infinite magnitude over an infinitely short duration

125 ○ Laplace transform of the delta function ◎ Filtering (Sampling) ○ Theorem 3.12: f : integrable and continuous at a

126 Proof:

127 by Hospital’s rule ○ Example 3.20:

128 3.6 Laplace Transform Solution of Systems
○ Example 3.22 Laplace transform Solve for

129 Partial fractions decomposition Inverse Laplace transform

130 3.7. Differential Equations with Polynomial Coefficient
◎ Theorem 3.13: Proof: ○ Corollary 3.1:

131 ○ Example 3.25: Laplace transform

132 Find the integrating factor, Multiply (B) by the integrating factor

133 Inverse Laplace transform

134 ○ Apply Laplace transform to algebraic expression for Y
Differential equation for Y

135 ◎ Theorem 3.14: PC on [0, k],

136 ○ Example 3.26: Laplace transform ------(A) ------(B)

137 Finding an integrating factor, Multiply (B) by ,

138 In order to have

139 Formulas: ○ Laplace Transform: ○ Laplace Transform of Derivatives: ○ Laplace Transform of Integral:

140 ○Shifting Theorems: ○ Convolution: Convolution Theorem: ○

141


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