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Math 3120 Differential Equations with Boundary Value Problems

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1 Math 3120 Differential Equations with Boundary Value Problems
Chapter 4: Higher-Order Differential Equations Section 4-4: Undetermined Coefficients – Superposition Approach

2 Method of Undetermined Coefficients
Recall the non homogeneous equation where p, q, g are continuous functions on an open interval I. The associated homogeneous equation is In this section we will learn the method of undetermined coefficients to solve the non homogeneous equation, which relies on knowing solutions to homogeneous equation. The general solution of non homogeneous equation can be written in the form where y1, y2 form a fundamental solution set of homogeneous equation, c1, c2 are arbitrary constants and yp is a specific solution to the non homogeneous equation.

3 Method of Undetermined Coefficients
Recall the nonhomogeneous equation with general solution In this section we use the method of undetermined coefficients to find a particular solution Y to the nonhomogeneous equation, assuming we can find solutions y1, y2 for the homogeneous case. The method of undetermined coefficients is usually limited to when p and q are constant, and g(t) is a polynomial, exponential, sine or cosine function.

4 Example 1: Exponential g(t)
Consider the nonhomogeneous equation We seek Y satisfying this equation. Since exponentials replicate through differentiation, a good start for Y is: Substituting these derivatives into differential equation, Thus a particular solution to the nonhomogeneous ODE is

5 Example 2: Sine g(t), First Attempt (1 of 2)
Consider the nonhomogeneous equation We seek Y satisfying this equation. Since sines replicate through differentiation, a good start for Y is: Substituting these derivatives into differential equation, Since sin(x) and cos(x) are linearly independent (they are not multiples of each other), we must have c1= c2 = 0, and hence A = 3A = 0, which is impossible.

6 Example 2: Sine g(t), Particular Solution (2 of 2)
Our next attempt at finding a Y is Substituting these derivatives into ODE, we obtain Thus a particular solution to the nonhomogeneous ODE is

7 Example 3: Polynomial g(t)
Consider the nonhomogeneous equation We seek Y satisfying this equation. We begin with Substituting these derivatives into differential equation, Thus a particular solution to the nonhomogeneous ODE is

8 Example 4: Product g(t) Consider the nonhomogeneous equation
We seek Y satisfying this equation, as follows: Substituting derivatives into ODE and solving for A and B:

9 Discussion: Sum g(t) Consider again our general nonhomogeneous equation Suppose that g(t) is sum of functions: If Y1, Y2 are solutions of respectively, then Y1 + Y2 is a solution of the nonhomogeneous equation above.

10 Example 5: Sum g(t) Consider the equation
Our equations to solve individually are Our particular solution is then

11 Example 6: First Attempt (1 of 3)
Consider the equation We seek Y satisfying this equation. We begin with Substituting these derivatives into ODE: Thus no particular solution exists of the form

12 Example 6: Homogeneous Solution (2 of 3)
Thus no particular solution exists of the form To help understand why, recall that we found the corresponding homogeneous solution in Section 3.4 notes: Thus our assumed particular solution solves homogeneous equation instead of the nonhomogeneous equation.

13 Example 6: Particular Solution (3 of 3)
Our next attempt at finding a Y is: Substituting derivatives into ODE,

14 Ch 4.3: Nonhomogeneous Equations: Method of Undetermined Coefficients
The method of undetermined coefficients can be used to find a particular solution Y of an nth order linear, constant coefficient, nonhomogeneous ODE provided g is of an appropriate form. As with 2nd order equations, the method of undetermined coefficients is typically used when g is a sum or product of polynomial, exponential, and sine or cosine functions. Section 4.4 discusses the more general variation of parameters method.

15 Example 1 Consider the differential equation For the homogeneous case,
Thus the general solution of homogeneous equation is For nonhomogeneous case, keep in mind the form of homogeneous solution. Thus begin with As in Chapter 3, it can be shown that

16 Example 2 Consider the equation For the homogeneous case,
Thus the general solution of homogeneous equation is For the nonhomogeneous case, begin with As in Chapter 3, it can be shown that

17 Example 3 Consider the equation
As in Example 2, the general solution of homogeneous equation is For the nonhomogeneous case, begin with As in Chapter 3, it can be shown that

18 Example 4 Consider the equation For the homogeneous case,
Thus the general solution of homogeneous equation is For nonhomogeneous case, keep in mind form of homogeneous solution. Thus we have two subcases: As in Chapter 3, can be shown that


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