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Government engineering college, Palanpur

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Presentation on theme: "Government engineering college, Palanpur"— Presentation transcript:

1 Government engineering college, Palanpur
Topic - MESH & NODAL ANALYSIS WITH EXAMPLE Prepared by- Subject – Circuit & Network ( ) Department - Electrical engineering Faculty name - A.M.Patel sir

2 Nodal Analysis

3 Obtain values for the unknown voltages across the elements in the circuit below.
At node 1 At node 2

4 (a) The circuit of Example 4
(a) The circuit of Example 4.2 with a 22-V source in place of the 7-W resistor. (b) Expanded view of the region defined as a supernode; KCL requires that all currents flowing into the region must sum to zero, or we would pile up or run out of electrons. At node 1: At the “supernode:”

5 Determine the node-to-reference voltages in the circuit below.

6 Mesh Current Analysis

7 Determine the two mesh currents, i1 and i2, in the circuit below.
For the left-hand mesh, i ( i1 - i2 ) = 0 For the right-hand mesh, 3 ( i2 - i1 ) i = 0 Solving, we find that i1 = 6 A and i2 = 4 A. (The current flowing downward through the 3-W resistor is therefore i1 - i2 = 2 A. )

8 Find the three mesh currents in the circuit below.
Creating a “supermesh” from meshes 1 and 3: ( i1 - i2 ) ( i3 - i2 ) i3 = 0 [1] Around mesh 2: 1 ( i2 - i1 ) i ( i2 - i3 ) = 0 [2] Finally, we relate the currents in meshes 1 and 3: i1 - i3 = [3] Rearranging, i i i3 = 7 [1] -i i i3 = 0 [2] i i3 = 7 [3] Solving, i1 = 9 A, i2 = 2.5 A, and i3 = 2 A.

9 Thank you…


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