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Percent Composition and

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1 Percent Composition and
Empirical Formulas Copyright © by Pearson Education, Inc. Publishing as Benjamin Cummings

2 Percent Composition Percent composition
Is the percent by mass of each element in a formula. Example: Calculate the percent composition of CO2. CO2 = 1 C(12.01g) + 2 O(16.00 g) = g/mol) 12.01 g C x = % C 44.01 g CO2 32.00 g O x = % O 44.01 g CO %

3 Learning Check What is the percent composition of lactic acid, C3H6O3, a compound that appears in the blood after vigorous activity?

4 Solution STEP 1 3C(12.01) + 6H(1.008) + 3O(16.00) = 90.08 g/mol
36.03 g C g H g O STEP 2 %C = g C x 100 = 40.00% C 90.08 g %H = g H x 100 = 6.714% H %O = g O x 100 = % O

5 Learning Check The chemical isoamyl acetate C7H14O2 gives the odor of pears. What is the percent carbon in isoamyl acetate? 1) %C 2) %C 3) %C Copyright © by Pearson Education, Inc. Publishing as Benjamin Cummings

6 Solution 3) 64.58 %C Molar mass C7H14O2 = 7C(12.01) + 14H(1.008)
+ 2O(16.00) = g/mol Total C = 7C(12.01) = g % C = total g C x 100 total g % C = g C x 100 = % C g

7 Empirical Formulas The empirical formula
Is the simplest whole number ratio of the atoms. Is calculated by dividing the subscripts in the actual (molecular) formula by a whole number to give the lowest ratio. C5H10O5  5 = C1H2O1 = CH2O actual (molecular) empirical formula formula

8 Some Molecular and Empirical Formulas
The molecular formula is the same or a multiple of the empirical. Table 6.3 Copyright © by Pearson Education, Inc. Publishing as Benjamin Cummings

9 Learning Check A. What is the empirical formula for C4H8?
1) C2H4 2) CH2 3) CH B. What is the empirical formula for C8H14? 1) C4H7 2) C6H12 3) C8H14 C. Which is a possible molecular formula for CH2O? 1) C4H4O4 2) C2H4O ) C3H6O3

10 Solution A. What is the empirical formula for C4H8? 2) CH2 C4H8  4
B. What is the empirical formula for C8H14? 1) C4H7 C8H14  2 C. Which is a possible molecular formula for CH2O? 2) C2H4O ) C3H6O3

11 Learning Check A compound has an empirical formula SN. If there are 4 atoms of N in one molecule, what is the molecular formula? Explain. 1) SN 2) SN4 3) S4N4

12 Solution A compound has an empirical formula SN. If there are 4 atoms of N in one molecule, what is the molecular formula? Explain. 3) S4N4 In this molecular formula 4 atoms of N and 4 atoms of S and N are related 1:1. Thus, it has an empirical formula of SN.

13 Learning Check A compound contains 7.31 g Ni and 20.0 g Br. Calculate its empirical (simplest) formula.

14 Solution Convert 7.31 g Ni and 20.0 g Br to moles.
7.31 g Ni x 1 mol Ni = mol Ni 58.69 g Ni 20.0 g Br x 1 mol Br = mol Br 79.90 g Br Divide by smallest: 0.125 mol Ni = 1 Ni mol Br = 2 Br Write ratio as subscripts: NiBr2

15 Converting Decimals to Whole Numbers
When the number of moles for an element is a decimal, all the moles are multiplied by a small integer to obtain whole number. Table 6.4 Copyright © by Pearson Education, Inc. Publishing as Benjamin Cummings

16 Learning Check Aspirin is 60.0% C, 4.5 % H and 35.5 % O. Calculate its empirical (simplest) formula.

17 Solution STEP 1. Calculate the moles of each element in 100 g.
100 g aspirin contains 60.0% C or 60.0 g C, 4.5% H or 4.5 g H, and 35.5% O or 35.5 g O. 60.0 g C x 1 mol C = mol C 12.01 g C 4.5 g H x 1 mol H = mol H 1.008 g H 35.5 g O x 1mol O = mol O 16.00 g O

18 Solution (continued) STEP 2. Divide by the smallest number of mol.
5.00 mol C = mol C (decimal) 2.22 4.5 mol H = 2.0 mol H 2.22 mol O = mole O

19 Solution (continued) 3. Use the lowest whole number ratio as subscripts When the moles are not whole numbers, multiply by a factor to give whole numbers, in this case x 4. C: mol C x 4 = 9 mol C H: 2.0 mol H x 4 = 8 mol H O: mol O x 4 = 4 mol O Using these whole numbers as subscripts the simplest formula is C9H8O4


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