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Due: Reaction rate WS Today: HW Pick up an iPad & Calculator

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Presentation on theme: "Due: Reaction rate WS Today: HW Pick up an iPad & Calculator"— Presentation transcript:

1 Due: Reaction rate WS Today: HW Pick up an iPad & Calculator
Factors the affect rates of reactions (quick review) Concentration calculations HW Concentration WS

2 In which diagram will the reaction go
Which diagram represents an endothermic reaction? Exothermic? In which diagram will the reaction go faster? Explain using evidence from the diagram 2

3 Factors Affecting Rate
Nature of Reactants Ionic vs. Covalent Temperature Surface Area Concentration/Pressure Presence of Catalysts/Inhibitors 3

4 Endothermic Reaction w/Catalyst
4

5 Exothermic Reaction w/Catalyst
5

6 Calculations of Solution Concentration

7 Calculations of Solution Concentration: Molarity
Molarity is the ratio of moles of solute to liters of solution 3 M = 3 moles or [3] L

8 Calculations of Solution Concentration: Mass Percent
Mass percent is the ratio of mass units of solute to mass units of solution, expressed as a percent

9 Practice Problem Seawater contains roughly 28.0g per liter. What is the molarity of sodium chloride in seawater? How many grams of HCl are in a 2M solution?

10 Making Dilutions Only weaker solutions can be made.
MconcVconc = MdilVdil   mol x L = mol x L L L The moles of conc. = the moles diluted

11 Sample problems:  Describe how you would make 3 L of a 0.25 M calcium chloride solution. Step 1. First figure out how many moles you will need. Step 2 Convert the moles to grams.

12 Step 3 Describe the process. Include the use of a volumetric flask.

13 Sample problem:  How would you make 4.00 L of a .15 M CaCl2 starting from a 2.5 M solution. Mconc x Vconc = Mdil x Vdil

14 Sample Problem: How would you make 2.0 L of M HCl, if you have a stock solution of 6.0 M HCl?

15 Calculations of Solution Concentration: Parts per Million
Parts per million is the ratio of mass units of solute to mass units of solution, multiplied by one million (106)

16 A Simplifying Assumption
1 ml of water = 1 gram of water 1000 ml of water = 1 liter = 1000 grams Assume that solutions with water as the solvent have the density of pure water (1 mL = 1 gram) It’s not true, but it’s close enough 


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