Download presentation

Presentation is loading. Please wait.

Published byDaniel Manning Modified over 5 years ago

1
MOLARITY A measurement of the concentration of a solution Molarity (M) is equal to the moles of solute (n) per liter of solution M = n / V = mol / L 2. Calculate the molarity of a solution prepared by mixing 23.0 g of NaCl in 500.0 mL of water. 1. Calculate the moles necessary to make 50.0 mL of a 3.0 M solution of hydrochloric acid. 3. How many grams of sodium sulfate will be required to make 150.0 mL of a 0.25 M solution?

2
MOLARITY & DILUTION M 1 V 1 = M 2 V 2 The act of diluting a solution is to simply add more water (or solvent) thus leaving the amount of solute unchanged.

3
Q. Calculate the concentration of a NaCl solution made by diluting 20.0 mL of 2.55 M with 235.0 mL of water.

4
MOLARITY & Stoichiometry In the past chapters, you measured out a solid reactant and needed to predict the mass of the product. You learned to use the molar mass and mole ratio to achieve that goal. The same reasoning applies with solution chemistry but instead to using the molar mass you will use the molarity to convert to moles. Stoichiometry Flow chart

5
Solution Stoichiometry

6
MOLARITY & Stoichiometry 1.How much calcium carbonate will be precipitated by adding 40.0 mL calcium chloride to 35.0 mL of 2.55 M potassium carbonate? 2.What is the concentration of 50.0 mL of hydrochloric acid needed to completely react with 9.55 g of magnesium metal?

7
PRACTICE PROBLEMS #37a _________1. What is the concentration of 250.0 mL of 0.60 moles of HCl? _________ 2. What volume of 0.7690 M LiOH will contain 55.3 g of LiOH? _________ 3. How many liters of water must be added to 100.0 mL of 4.50 M HBr to make a solution that is 0.250 M HCl? _________ 4. How many grams of barium sulfate that will precipitate when 500.0 mL of 0.340 M BaCl 2 and 300.0 mL of 1.70 M Na 2 SO 4 are mixed? 5. How would you prepare 850.0 mL of a 0.020 M ferric chloride solution if you start with crystals of FeCl 3. 6H 2 O? 2.4 M 3.00 L 1.80 L 39.6 g Weigh out 4.59 g of the hydrated salt to a graduated cylinder with 800.0 mL then add enough DI water to make 850 mL exactly.

8
PRACTICE PROBLEM #37b 1. What is the concentration of 35.0 mL of 0. 0556 moles of KCl? 2. How many grams of KCl is needed to prepare 50.0 mL of a 0.10 M solution? 3. How many milliliters of water must be added to 30.0 mL of 9.0 M KCl to make a solution that is 0.50 M KCl? 4. How many grams of calcium carbonate will precipitate when 500.0 mL of 0.340 M CaCl 2 and 300.0 mL of 1.70 M Na 2 CO 3 are mixed? 5. What is the concentration of the product solution (assuming the volumes are additive) when 500.0 mL of 0.340 M CaCl 2 and 300.0 mL of 1.70 M Na 2 CO 3 are mixed? 1.59 M 0.38 g 510 mL 17.0 g 0.425 M

9
GROUP STUDY PROBLEM #37a ______1. How many grams of K 3 PO 4 is needed to prepare 500.0 mL of a 0.00567 M solution? ______2. What volume of 0.7690 M LiOH will contain 55.3 g of LiOH? ______3. How many milliliters of water must be added to 600.0 mL of 3.40 M HCl to make a solution that is 0.500 M HCl? ______ 4. What is the concentration of the product solution (assuming the volumes are additive) when 24.9 mL of 0.70 M BaCl 2 and 45.0 mL of 0.15 M Na 3 PO 4 are mixed?

10
GROUP STUDY PROBLEM #37b ______1. What is the concentration of 250.0 mL of 0.60 moles of NaOH? ______2. What mass of MgCl 2 will be required to prepare 500 mL of 0.150 M solution? ______3. How many milliliters of water must be added to 50.0 mL of 1.97 M NaOH to make a solution that is 0.025 M NaOH? ______ 4. How many grams of barium sulfate that will precipitate when 500.0 mL of 0.340 M BaCl 2 and 300.0 mL of 1.70 M Na 2 SO 4 are mixed? ______ 5. What is the concentration of the product solution (assuming the volumes are additive) when 500.0 mL of 0.340 M BaCl 2 and 300.0 mL of 1.70 M Na 2 SO 4 are mixed?

Similar presentations

© 2020 SlidePlayer.com Inc.

All rights reserved.

To make this website work, we log user data and share it with processors. To use this website, you must agree to our Privacy Policy, including cookie policy.

Ads by Google