1. Energy Review: Chapter 5 Section 1, Pages 116- 119 Kinetic Energy (KE) Energy of _________________________________________ If an object is ___________________________ it has KE Measured using the formula: KE = List 2 examples of KE: 1. 2. Potential Energy (PE) Energy of _______________________ or ______________________ List 2 examples of PE: 1. 2. motion moving Swinging a bat Car moving position shape Bow bending Stretching a rubber band

2. Energy Review: Chapter 5 Section 1, Pages 116- 119 Gravitational Potential Energy (GPE) A specific type of _________________________ Created when you do _________________ on an object using a ________________ (such as lifting) that opposes________________. Measured using the formula: GPE = List 3 examples of GPE: 1. 2. 3. Mechanical Energy (ME) Total energy of ______________________ & _________________ of an object Potential energy (PE) work force gravity weight x HEIGHT Lifting a backpack Diver on a diving board Standing on the edge of a hill or cliff Motion (KE) Position (PE)

3. Energy Review: Chapter 5 Section 1, Pages 116- 119 Measured using the formula: ME = ME always remains ____________________________ for a given object Describe an example of ME: Describe the Energy Of The Pendulum 14. A ____________ 15. B ____________ 16 16. 16. C ____________ A B C PE + KE constant Car rolling down a track, as KE increases, PE decreases, ME remains constant. PE, GPE, ME PE, GPE, ME, KE KE, ME

4. Energy Review: Chapter 5 Section 1, Pages 116- 119 Describe what happens to Potential Energy and Kinetic Energy as the Marble rolls down the track. 17. Point A __________________ 18. Point B __________________ 19. Point C __________________ 20. Describe why mechanical energy stays the same throughout points A, B, C.________________________________________________________ A B C PE,GPE at maximum PE KE KE at maximum As the roller coaster rolls down the track, PE decreases as KE increases at the same rate so ME stays constant (does not change) ME is the sum of KE and PE.

5. What is the KE of a soccer ball which has a mass of 0.8 kg and is kicked at a velocity of 10 m/s? square this first 0.8 kg x (10 m/s)2 /2 0.8 kg x (100 m/s) /2 80 /2 = 40 J KE = 40 J Calculate the KE of a running back that has a mass of 80 kg and is running at a velocity of 8 m/s. 80 kg x (8 m/s)2 /2 80 kg x (64 m/s) /2 5120 /2 = 2560 J KE = 2560J