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Chapter 8
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8-1 Estimating Perimeter and Area Perimeter – total distance around the figure Area – number of square units a figure encloses
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8-1 Estimating Perimeter and Area-answers Perimeter – total distance around the figure Area – number of square units a figure encloses 12ft ; truck cab quite tall 8 in; book is not very wide 8 in; pizza not very big 2ft ; bathtub is not very deep
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8-1 Estimating Perimeter and Area
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8-1 Estimating Perimeter and Area-answers 10 yd 12 yd 16 yd13 yd
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8-1 Estimating Perimeter and Area
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8-1 Estimating Perimeter and Area-answers about 19 cm 2 about 7 cm 2 about 10 cm 2 about 18 cm 2 ft inmi 2
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8-2 Area of a Parallelogram height of a parallelogram – length of a perpendicular segment connecting base of parallelogram to the other. Area of parallelogram: Area = bh
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8-2 Area of a Parallelogram
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8-2 Area of a Parallelogram-answers 60 m 2 25 m 2 12 ft 2 150 in 2 392 m 2
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8-2 Area of a Parallelogram
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8-2 Area of a Parallelogram-answers 3ft by 7 ft
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8-3 Perimeter and Area of a Triangle base of a triangle – any side can be considered base height of triangle – length of perpendicular segment from a vertex to the bases opposite or and extension of base Area of triangle = ½ bh or bh/2
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8-3 Perimeter and Area of a Triangle
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8-3 Perimeter and Area of a Triangle - answers 8.2 ft 23.9 in 34.6 in 416 ft
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8-3 Perimeter and Area of a Triangle
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8-3 Perimeter and Area of a Triangle-ans 299 cm 2 59.22 mi 2 26.8 km 2 1325 yd 2 4, 4, 4; 5, 5, 2
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8-4 Area of Other Figures bases of trapezoid – two parallel sides of a trapezoid; b 1 and b 2 height of trapezoid – length of perpendicular segment connecting bases Area of trapezoid = ½h(b 1 + b 2 ) or h(b 1 + b 2 ) 2
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8-4 Area of Other Figures
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8-4 Area of Other Figures-answers 33 ft 2 748 ft 2 33.25 in 2 98 m 2 838 km 2 2586 yd 2
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8-5 Circumference and Area of a Circle Circumference – is the distance around the outside of a circle Π – the ratio of a circle’s circumference to its diameter d. Π is nonterminating and nonrepeating Π is approximate 3.14 or 22/7
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8-5 Circumference and Area of a Circle
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8-5 Circumference and Area of a Circle-answers C = Πd = Π*50 = 157.1 cm C = 2 Πr = 2*Π*40 = 251.3 in
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8-5 Circumference and Area of a Circle
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8-5 Circumference and Area of a Circle-answers C = Πd = Π*17 = 53.4 mm C = 2 Πr = 2*Π*7 = 44.0 cm
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8-5 Circumference and Area of a Circle
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A = Πr 2 = Π*6 2 = 36 Π = 113 in 2 A = Πr 2 = Π*15 2 = 225 Π = 707 ft 2
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8-5 Circumference and Area of a Circle A = Πr 2 = Π*11 2 = 121 Π = 380 cm 2 A = Πr 2 = Π*25 2 = 625 Π = 1963 cm 2
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8-8 Three-Dimensional Figures 3-D figure – figure that does not lie in plane face – flat surface of solid shaped like polygon edge – segment formed by intersection of 2 faces prism – 3-D figure with two parallel and congruent polygonal faces, called bases
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8-8 Three-Dimensional Figures Prisms are named for the shape of its bases. Name this prism.
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8-8 Three-Dimensional Figures Cube - rectangular prism with faces that are all squares Cylinder - bases are circles
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8-8 Three-Dimensional Figures Pyramids – are made up of triangular faces that meet at one point, called a vertex Cone – one base that is a circle and one vertex
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8-8 Three-Dimensional Figures Sphere – set of all points in space that are same distance from a center point
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8-8 Three-Dimensional Figures Sphere – set of all points in space that are same distance from a center point Rectangle, rectangular prism triangle, Triangular prism pentagon, Pentagonal prism
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8-8 Three-Dimensional Figures
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cylinder cone sphere Hexagonal pyramid cone Rectangular pyramid
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8-9 Surface Area of Rectangular Prisms Net – two – dimensional pattern that you can fold into a 3-d figure
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8-9 Surface Area of Rectangular Prisms Net – two – dimensional pattern that you can fold into a 3-d figure Draw a net for the triangular prism. 1)First label the bases and the side. 2)Then draw the net.
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8-9 Surface Area of Rectangular Prisms-answers Net – two – dimensional pattern that you can fold into a 3-d figure
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8-9 Surface Area of Rectangular Prisms Surface Area – sum of all the area of the faces of a prism
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8-9 Surface Area of Rectangular Prisms-answers Surface Area – sum of all the area of the faces of a prism SA = (5+4+5+4)6 + (2*5*4) = 108 + 40 = 148 in 2 TOP = 5*4 = 20 Bottom = 5 * 4 = 20 Left = 6 * 5 = 30 Right = 6 * 5 = 30 Front = 6 *4 = 24 Back = 6 * 4 = +24 148 in 2
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8-9 Surface Area of Rectangular Prisms Surface Area – sum of all the area of the faces of a prism
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8-9 Surface Area of Rectangular Prisms Surface Area – sum of all the area of the faces of a prism SA = Ph + 2B = (7+4+7+4)6 + (2*7*4) = 132 + 56 = 188 m 2 TOP = 7*4 = 28 Bottom = 7 * 4 = 28 Left = 6 * 4 = 24 Right = 6 * 4 = 24 Front = 6 *7 = 42 Back = 6 * 7 = +42 188 m 2
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8-9 Surface Area of Rectangular Prisms Surface Area – sum of all the area of the faces of a prism
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8-9 Surface Area of Rectangular Prisms-ans Surface Area – sum of all the area of the faces of a prism SA = Ph + 2B = (1+1+1+1)2 + (2*1*1) = 8 + 2 = 10 ft 2 TOP = 1*1 = 1 Bottom = 1* 1 = 1 Left = 1 * 2 = 2 Right = 1 * 2 = 2 Front = 1 *2 = 2 Back = 1 * 2 = +2 10 ft 2
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8-9 Surface Area of Triangular Prisms Surface Area – sum of all the area of the faces of a prism
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8-9 Surface Area of Triangular Prisms-ans Surface Area – sum of all the area of the faces of a prism SA = Ph + 2B = (9+12+15)4 + 2((9*12)/2) = 144 + 108 = 252 cm 2 TOP (triangle) = 9 * 12 / 2 = 54 Bottom (triangle) = 9 * 12 / 2 = 54 Left (rectangle) = 9*4 = 36 Front (rectangle) = 15*4 = 60 Back (rectangle) = 12 * 4 = +48 252 cm 2
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8-9 Surface Area of Triangular Prisms Surface Area – sum of all the area of the faces of a prism
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8-9 Surface Area of Triangular Prisms-ans Surface Area – sum of all the area of the faces of a prism SA = Ph + 2B =(6+8+10)9 + 2((6*8)/2) = 216 + 48 = 264 m 2 Left (triangle) = 6 * 8 / 2 = 24 Right (triangle) = 6 * 8 / 2 = 24 Front (rectangle) = 9*10 = 90 Back (rectangle) = 9*6 = 54 Bottom (rectangle) = 8*9 = +72 264 m 2
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8-9 Surface Area of Cylinders Surface Area – sum of all the area of the faces of a prism
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8-9 Surface Area of Cylinders Surface Area – sum of all the area of the faces of a prism
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8-9 Surface Area of Cylinders-ans Surface Area – sum of all the area of the faces of a prism SA = 2 Πrh + 2Πr 2 = 2 Π10*15 + 2Π10 2 = 942 + 628 = 1570 yd 2
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8-9 Surface Area of Cylinders Surface Area – sum of all the area of the faces of a prism
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8-9 Surface Area of Cylinders-ans Surface Area – sum of all the area of the faces of a prism SA = 2 Πrh + 2Πr 2 = 2 Π5*20 + 2Π5 2 = 628 + 157 = 785 cm 2
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8-9 Surface Area of Cylinders Surface Area – sum of all the area of the faces of a prism
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8-9 Surface Area of Cylinders-ans Surface Area – sum of all the area of the faces of a prism SA = 2 Πrh + 2Πr 2 = 2 Π10*45 + 2Π10 2 = 2826 + 628 = 3454 m 2
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8-10 Volume of Prisms and Cylinders Volume – number of cubic units needed to fill the space INSIDE the figure Cubic unit – a cube with edges one unit long
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8-10 Volume of Prisms and Cylinders
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Volume of a Rectangular Prism V = Bh = area of base * height = l * w * h
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8-10 Volume of Prisms and Cylinders
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8-10 Volume of Prisms and Cylinders-answers V = Bh = l * w * h = 20 * 7 * 8 = 1120 in 3 V = Bh = l * w * h = 8 * 10 * 8 = 640 ft 3
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8-10 Volume of Prisms and Cylinders
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8-10 Volume of Prisms and Cylinders-ans V = Bh = b*h * h 2 = 6*6* 8 2 = 192 cm 3 V = Bh = b*h * h 2 = 3*4* 5 2 = 30 in 3
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8-10 Volume of Prisms and Cylinders
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8-10 Volume of Prisms and Cylinders-ans V = Bh = b*h * h 2 = 12*28* 10 2 = 1680 m 3
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8-10 Volume of Prisms and Cylinders Find the height of each rectangular prism given the volume, length, and width. V = 3375 m 3 V = 900 ft 3 L = 15 m L= 45 ft W = 15 m W = 2 ft H = ?
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8-10 Volume of Prisms and Cylinders-ans Find the height of each rectangular prism given the volume, length, and width. V = 3375 m 3 V = 900 ft 3 L = 15 m L= 45 ft W = 15 m W = 2 ft H = ? 15 m H = ? 10 ft
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8-10 Volume of Prisms and Cylinders
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8-10 Volume of Prisms and Cylinders-ans V = Bh = Πr 2 * h = Π 1 2 * 10 = 31 ft 3 V = Bh = Πr 2 * h = Π 14 2 * 80 = 49260 m 3
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8-10 Volume of Prisms and Cylinders
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8-10 Volume of Prisms and Cylinders-ans V = Bh = Πr 2 * h = Π 6 2 * 18 = 2036 in 3
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