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LAB 1: Properties of Materials By: Tamsyn Steel. PURPOSE To determine the relationship between mass and volume for metal objects of different shapes and.

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Presentation on theme: "LAB 1: Properties of Materials By: Tamsyn Steel. PURPOSE To determine the relationship between mass and volume for metal objects of different shapes and."— Presentation transcript:

1 LAB 1: Properties of Materials By: Tamsyn Steel

2 PURPOSE To determine the relationship between mass and volume for metal objects of different shapes and sizes

3 THEORY With increased mass, there will be increased volume. This will be demonstrated by measuring the water displacement The shape of the object will not effect the overall volume of the object because volume is a ratio and directly proportional to mass. Increased mass will increase the volume.

4 PROCEDURE Gather necessary materials: digital scale, 50 mL graduated cylinder, metal objects (5 or more), vernier caliper Carefully weigh each metal object and record the mass in data table 1 Carefully measure each object with the vernier caliper and note the length and shape of each object in data table 1 Fill the graduated cylinder to 35 mL Carefully place the 1 st metal object into the graduated cylinder, making sure not to loose any water Record the final water level in data table 2 Repeat steps 4-6 for each of the remaining objects

5 DATA

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8 ANALYSIS Graph 1: The mass obtained from an electric scale vs. the volume found from water displacement

9 CONCULSION The calculated data proved the theory that with increased mass there will be increased volume. The data from data table 3 illustrates this comparison perfectly. The shape of the graphs and the equations are what were expected in the theory. The theory proposed, that with increased mass there would be increased volume, and the linear graphs prove this.

10 ANALYSIS Graph 2: Mass obtained from an electric scale vs. the calculated volume The Graph 1 and Graph 2 are similar, but not exactly the same: Graph 1 Mass = 7.62 g/mL * V Graph 2 Mass = 7.33 g/mL * V The difference could be a result of measuring errors.


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