Chapters 6 & 7.  Graphing Graphing  Substitution Substitution  Linear Combinations Linear Combinations  Multiple Choice Questions Multiple Choice.

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Presentation transcript:

Chapters 6 & 7

 Graphing Graphing  Substitution Substitution  Linear Combinations Linear Combinations  Multiple Choice Questions Multiple Choice Questions  Word Problems Word Problems

 Multiplication Properties Multiplication Properties  Zero Property Zero Property  Negative Exponent Property Negative Exponent Property  Division Properties Division Properties  Scientific Notation Scientific Notation  Exponential Growth Exponential Growth  Exponential Decay Exponential Decay

y = 3x + 4 2x + y = 9 y = 3x + 4 m = 3 b = 4 2x + y = 9 -2x y = -2x + 9 m = -2 b = 9 (1, 7) The solution is (1,7)

-2x + 2y = 2 2x + y = -2 2x + y = -2 -2x y = -2 – 2x y = -2 – 2* -1 y = 0 Answer: (-1, 0) -2x + 2y = 2 -2x + 2(-2 – 2x) = 2 -2x – 4 – 4x = 2 -6x – 4 = x = x = -1

3 ( ) -2( ) 2x + 5y = 5 3x + 2y = -9 2x + 5y = 5 2x + 5 * 3 = 5 2x + 15 = x = x = -5 6x + 15y = 15 -6x – 4y = 18 11y = y = 3 (-5, 3)

Solve the system: 3x + 2y = 4 -x + 3y = -5 a. (4, -4) b. (2, -1)c. (3,1) PLUG IN THE OPTIONS!!

You want to burn 380 calories during 40 minutes of exercise. You burn about 8 calories per minute inline skating and 12 calories per minute swimming. How long should you spend doing each activity? x = inline skating y = swimming Calories: 8x + 12y = 380 Minutes: x + y = 40

To multiply powers with the same base, you ADD the exponents.

To find a power of a power, you MULTIPLY the exponents.

To find a power of a product, you DISTRIBUTE the exponent.

= 1 Any nonzero number to the zero power is ONE!

= = = = Any nonzero number raised to a negative exponent creates a FRACTION!

To divide powers with the same base, you SUBTRACT the exponents.

To find the power of a quotient, you DISTRIBUTE the exponent to all parts of the problem.

Write each number in scientific notation ,000, , ,502,000,000  2.4 x 10 7  3.64 x 10 4  3.5 x  2 x  x 10 9

y = C(1+r) t  C is the beginning amount  r is the rate (%)  t is the time  y is the ending amount (what you are looking for)

A company has 50 employees in The number of employees increases by 50% each year. How many employees are there in 2004? C = 50 r = 50% = 0.50 t = 4 y = ??? 253 employees

y = C(1-r) t  C is the beginning amount  r is the rate (%)  t is the time  y is the ending amount (what you are looking for)

You buy a used car for $18,000. The value of the car depreciates at a rate of 12% per year. What is the value of the car in 8 years? C = 18,000 r = 12% = 0.12 t = 8 y = ??? $

 Worksheet – “Chapters 6 & 7 Review”

 Page 386 #2,3,7,8  Page 455 #1-6,18-21,31,32