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Bell Ringer Solve. 1. 7x – 1 = 2x + 19

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Presentation on theme: "Bell Ringer Solve. 1. 7x – 1 = 2x + 19"— Presentation transcript:

1 Bell Ringer Solve. 1. 7x – 1 = 2x + 19
5x = 20 x = 4 2. 5(x + 1)= 2x – 1 5x + 5 = 2x – 1 – 2x – 2x 3x + 5 = x = x = -2

2 Laws of Exponents Review!
Zero Exponent Property Negative Exponent Property Product of Powers Quotient of Powers Power of a Power Power of a Product Power of a Quotient

3 Laws of Exponents x0 = 1 30 = 1 120 = 1 x-4 = 5-1 = 5x-3y5 = 1 5y5 1
Zero Exponent Property – Any number raised to the zero power is 1. x0 = = = 1 Negative Exponent Property – Any number raised to a negative exponent is the reciprocal of the number. x-4 = = x-3y5 = 1 x4 1 5 5y5 x3

4 Laws of Exponents x2•x8 = x10 3x4•x-2 = 3x2 x6 x2 10x4y3 2x7y 5y2 x3
Product of Powers – When multiplying numbers with the same bases, ADD the exponents. Quotient of Powers – When dividing numbers with the same bases, SUBTRACT the exponents. x2•x8 = x10 3x4•x-2 = 3x2 x6 x2 10x4y3 2x7y 5y2 x3 = x4 =

5 Laws of Exponents (95)3 = 915 (x4y5)2 = x8y10 (xy)3 = x3y3 (2bc)2
Power of a Power - When you have an exponent raised to an exponent, multiply the exponents! (95)3 = 915 (x4y5)2 = x8y10 Power of a Product - Distribute the exponent on the outside of the parentheses to all of the terms inside of the parentheses. (xy)3 = x3y3 (2bc)2 = 4b2c2

6 ( ) ( ) ( ) ( ) 2 x 23 x3 8 x3 = = 3 x2y 34 x8y4 81 x8y4 = =
Laws of Exponents Power of a Quotient – Distribute the exponent on the outside of the parentheses to the numerator and the denominator of the fraction. ( ) ( ) 2 x 3 23 x3 8 x3 = = ( ) ( 3 x2y ) 4 34 x8y4 81 x8y4 = =


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