Introductory Video Giancoli Lesson 10-7 to 10-9 10-7: Fluids In Motion; Flow Rate And Equation Of Continuity 10-8: Bernoulli’s equation 10-9: Applications.

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Presentation transcript:

Introductory Video

Giancoli Lesson 10-7 to : Fluids In Motion; Flow Rate And Equation Of Continuity 10-8: Bernoulli’s equation 10-9: Applications of Bernoulli’s Principle: From Torricelli To Sailboats, Airfoils, and TIA

Objectives  Know stuff

Reading Activity Questions?

Fluids In Motion  Fluid Dynamics – study of fluids in motion  Hydrodynamics – study of water in motion  Streamline or laminar flow – flow is smooth, neighboring layers of fluid slide by each other smoothly, each particle of the fluid follows a smooth path and the paths do not cross over one another

Fluids In Motion  Turbulent flow – characterized by erratic, small whirlpool-like circles called eddy currents or eddies  Eddies absorb a great deal energy through internal friction  Viscosity – measure of the internal friction in a flow

Speed Changes In Changing Diameter Of Tubes  Assumes laminar flow  Flow rate – the mass (Δm) of fluid that passes through a given point per unit time (Δt)

Speed Changes In Changing Diameter Of Tubes  Mass is equal to density times volume

Speed Changes In Changing Diameter Of Tubes  The volume (V) of fluid passing that point in time (Δt) is the cross-sectional area of the pipe (A) times the distance (Δl) travelled over the time (Δt)

Speed Changes In Changing Diameter Of Tubes  The velocity is equal to the distance divided by the time so, mass flow rate becomes ρAv

Speed Changes In Changing Diameter Of Tubes  Since no fluid escapes, the mass flow rate at both ends of this tube are the same

Speed Changes In Changing Diameter Of Tubes  If we assume the fluid is incompressible, density is the same and,  Equation of Continuity and  Volume Rate of Flow

Speed Changes In Changing Diameter Of Tubes  When cross-sectional area is large, velocity is small. When the cross- sectional area is small, velocity is high  Equation of Continuity and  Volume Rate of Flow

Speed Changes In Changing Diameter Of Tubes  That’s why you put your thumb over the end of the hose to squirt people at car washes  Equation of Continuity and  Volume Rate of Flow

Sample Problem Blood Flow. The radius of the aorta is about 1.0cm and the blood passing through it has a speed of about 30cm/s. A typical capillary has a radius of about 4x10 -4 cm and blood flows through it at a speed of about 5x10 -4 m/s. Estimate how many capillaries there are in the body.

Sample Problem Blood Flow. The radius of the aorta is about 1.0cm and the blood passing through it has a speed of about 30cm/s. A typical capillary has a radius of about 4x10 -4 cm and blood flows through it at a speed of about 5x10 -4 m/s. Estimate how many capillaries there are in the body.

Bernoulli’s Equation

 Daniel Bernoulli ( ) is the only reason airplanes can fly  Ever wonder why:  The shower curtain keeps creeping toward you?  Smoke goes up a chimney and not in your house?  When you see a guy driving with a piece of plastic covering a broken car window, that the plastic is always bulging out?

Bernoulli’s Equation  Ever wonder why:  Why a punctured aorta will squirt blood up to 75 feet, but yet waste products can flow into the blood stream at the capillaries against the blood’s pressure?  How in the world Roberto Carlos made the impossible goal?  It’s Bernoulli’s fault

Bernoulli’s Principle

Bernoulli’s Equation  Bernoulli’s principle states, where the velocity of a fluid is high, the pressure is low, and where the velocity is low, the pressure is high BLOWING PAPER DEMO  Not as straight forward as it sounds  Consider this,

Bernoulli’s Equation  We just said that as the fluid flows from left to right, the velocity of the fluid increases as the area gets smaller  You would think the pressure would increase in the smaller area, but it doesn’t, it gets smaller  But, the pressure in area 1 does get larger How come?

Bernoulli’s Equation  When you wash a car, your thumb cramps up holding it over the end of the hose.  This is because of the pressure built up behind your thumb.

Bernoulli’s Equation  If you stuck your pinky inside the hose, you would feel pressure at the tip of your finger, a decrease in the pressure along the sides of your finger, and an increase in the velocity of the water coming out of the hose.  You would also get squirted in the face but that’s your own fault for sticking your finger in a hose!

Bernoulli’s Equation  It makes sense from Newton’s Second Law  In order for the mass flow to accelerate from the larger pipe to the smaller pipe, there must be a decrease in pressure

Bernoulli’s Equation  Assumptions:  Flow is steady and laminar  Fluid is incompressible  Viscosity is small enough to be ignored  Consider flow in the diagram below:

Bernoulli’s Equation  We want to move the blue fluid on the left to the white area on the right  On the left, the fluid must move a distance of Δl 1  Since the right side of the tube is narrower, the fluid must move farther (Δl 2 ) in order to move the same volume that is in Δl 1

Bernoulli’s Equation  Work must be done to move the fluid along the tube and we have pressure available to do it

Bernoulli’s Equation  There is also work done by gravity (since the pipe has an increase in elevation) which acts on the entire body of fluid that you are trying to move  Force of gravity is mg, work is force times distance, so:

Bernoulli’s Equation  Total work done is then the sum of the three:

Bernoulli’s Equation  Anything we can do to make this longer?

Bernoulli’s Equation  Anything we can do to make this longer? How about the work – energy principle?

Bernoulli’s Equation  Better, but it needs to be cleaned up a little. Substitute for m, then since A 1 Δl 1 = A 2 Δl 2, we can divide them out

Bernoulli’s Equation  Manageable, but let’s make it look like something a little more familiar

Bernoulli’s Equation  Look familiar, like Conservation of Energy?

Sample Problem Water circulates throughout a house in a hot-water heating system (Iceland). If the water is pumped at a speed of 0.50 m/s through a 4.0 cm diameter pipe in the basement under a pressure of 3 atm, what will be the flow speed and pressure in a 2.6 cm diameter pipe on the second floor 5.0 m above?

Sample Problem Water circulates throughout a house in a hot-water heating system (Iceland). If the water is pumped at a speed of 0.50 m/s through a 4.0 cm diameter pipe in the basement under a pressure of 3 atm, what will be the flow speed and pressure in a 2.6 cm diameter pipe on the second floor 5.0 m above?

Sample Problem Water circulates throughout a house in a hot-water heating system (Iceland). If the water is pumped at a speed of 0.50 m/s through a 4.0 cm diameter pipe in the basement under a pressure of 3 atm, what will be the flow speed and pressure in a 2.6 cm diameter pipe on the second floor 5.0 m above?

Sample Problem Water circulates throughout a house in a hot-water heating system (Iceland). If the water is pumped at a speed of 0.50 m/s through a 4.0 cm diameter pipe in the basement under a pressure of 3 atm, what will be the flow speed and pressure in a 2.6 cm diameter pipe on the second floor 5.0 m above?

Sample Problem Water circulates throughout a house in a hot-water heating system (Iceland). If the water is pumped at a speed of 0.50 m/s through a 4.0 cm diameter pipe in the basement under a pressure of 3 atm, what will be the flow speed and pressure in a 2.6 cm diameter pipe on the second floor 5.0 m above? Whew!

Applications: Torricelli’s Theorem  Consider water flowing out of a “spigot” at the bottom of a reservoir  Because the diameter of the reservoir is extremely large in comparison to the spigot, velocity of reservoir can be neglected  Atmospheric pressure is the same at both ends (P 1 =P 2 )  Bernoulli’s equation becomes:  Now solve for v s

Applications: Torricelli’s Theorem  Consider water flowing out of a “spigot” at the bottom of a reservoir  Because the diameter of the reservoir is extremely large in comparison to the spigot, velocity of reservoir can be neglected  Atmospheric pressure is the same at both ends (P 1 =P 2 )  Bernoulli’s equation becomes:  Now solve for v s

Applications: No Change in Height  Bernoulli’s equation becomes:  As velocity increases, pressure decreases  As velocity decreases, pressure increases

Applications: Atomizers and Ping Pong Balls

Applications: Airfoils

Applications: Transient Ischemic Attack  Temporary lack of blood supply to the brain  WARNING: This discussion may make you feel faint! (feint attempt at humor)

Summary Review  Do you know more stuff than before?

#34-43 Homework