Check Worksheet 3 On Socrative: Put in your answers to the selected questions. Room Name: mrcosgrove.

Slides:



Advertisements
Similar presentations
4.3 Systems of Equations - Elimination Objective: The student will be able to: Solve systems of equations using elimination with addition and subtraction.
Advertisements

Simultaneous Equations The Elimination method. If a pair of simultaneous equations contain an x - term which are exactly the same, we can solve them by.
3-2: Solving Linear Systems
Drill Solve the linear system by substitution. 1.y = 6x – 11 -2x – 3y = x + y = 6 -5x – y = 21.
Do Now Pass out calculators. Solve the following system by graphing: Graph paper is in the back. 5x + 2y = 9 x + y = -3 Solve the following system by using.
Bell Work2/12/15 Solve the system by elimination..
5.3 Solving Systems using Elimination
Lesson 6-3 – Solving Systems Using Elimination
Solving Systems of Equations: Elimination Method.
Solving Systems of Linear Equations
3.2 Solving Systems Algebraically
Do Now 1/13/12  In your notebook, list the possible ways to solve a linear system. Then solve the following systems. 5x + 6y = 50 -x + 6y = 26 -8y + 6x.
Solve the equation -3v = -21 Multiply or Divide? 1.
3-2 Solving Equations by Using Addition and Subtraction Objective: Students will be able to solve equations by using addition and subtraction.
Goal: Solve a system of linear equations in two variables by the linear combination method.
Dr. Fowler CCM Solving Systems of Equations By Elimination – Harder.
Topic: Algebra LO: Solving simultaneous equations. BRONZE: When neither equation needs to be changed. SILVER: By changing one equation. SILVER: By changing.
Bell Ringer 2x – 3y = 4 5x + 3y = 10. HW Check Check elimination part 1 practice.
Bell Ringer October 14, 2010 y = 7 – 2x 4x + y = 5 Step 1: Put the equations in Standard Form. 2x + y = 7 4x + y = 5 Step 2: Determine which variable to.
7.4. 5x + 2y = 16 5x + 2y = 16 3x – 4y = 20 3x – 4y = 20 In this linear system neither variable can be eliminated by adding the equations. In this linear.
Do Now (3x + y) – (2x + y) 4(2x + 3y) – (8x – y)
Elimination method Solving linear equations simultaneously.
Solving Linear Equations Substitution. Find the common solution for the system y = 3x + 1 y = x + 5 There are 4 steps to this process Step 1:Substitute.
Good Morning, We are moving on to chapter 3. If there is time today I will show you your test score you can not have them back as I still have several.
Solving Systems of Equations So far, we have solved systems using graphing and substitution. These notes show how to solve the system algebraically using.
Bell Ringer 2. Systems of Equations 4 A system of equations is a collection of two or more equations with a same set of unknowns A system of linear equations.
Quiz next Friday, March 20 th Sections 1-0 to minutes – at the beginning of class.
Multiply one equation, then add
Slide Copyright © 2009 Pearson Education, Inc. 7.2 Solving Systems of Equations by the Substitution and Addition Methods.
Do Now Solve using elimination: 3x + 2y = – 19 – 3x – 5y = 25.
Task 2.6 Solving Systems of Equations. Solving Systems using Substitution  Solve using Substitution if one variable is isolated!!!  Substitute the isolated.
3.3 Solving Linear Systems by Linear Combination 10/12/12.
3-2: Solving Linear Systems. Solving Linear Systems There are two methods of solving a system of equations algebraically: Elimination Substitution.
Algebra II February 22 nd Students should complete warm-up problems. Quiz on solving systems by graphing. Students will be able to solve a system of linear.
Solving Systems by Elimination
Solve Linear Systems By Multiplying First
Simultaneous Equations 1
Solving Systems of Equations using Elimination
Solve Systems of Equations by Elimination
Solving Systems of Linear Equations in 3 Variables.
WARMUP.
Simultaneous equations
Solve for variable 3x = 6 7x = -21
Solve an equation by multiplying by a reciprocal
Solving Systems by Elimination
Warm Up Simplify each expression. 1. 3x + 2y – 5x – 2y
3-2: Solving Linear Systems
Solving harder linear Simultaneous Equations
Solving Systems of Equations using Substitution
Simultaneous Equations
The student will be able to:
Solve Linear Equations by Elimination
Before: December 4, 2017 Solve each system by substitution. Steps:
Objectives Solve systems of linear equations in two variables by elimination. Compare and choose an appropriate method for solving systems of linear equations.
Solving One and Two Step Equations
SIMULTANEOUS EQUATIONS 1
3-2: Solving Linear Systems
Simultaneous Equations starter
7.3 Notes.
Simultaneous Equations
Solving Systems of Linear Equations in 3 Variables.
Solving Simultaneous Equations by Elimination
6.3 Using Elimination to Solve Systems
3-2: Solving Linear Systems
Example 2B: Solving Linear Systems by Elimination
The student will be able to:
3-2: Solving Linear Systems
Simultaneous Equations
Solving Systems by ELIMINATION
Solving Linear Equations
Presentation transcript:

Check Worksheet 3 On Socrative: Put in your answers to the selected questions. Room Name: mrcosgrove

Questions 25 – 28 *Solve like a normal equation. Example: |x| + 3 = 10 |x| = 10 – 3 |x| = 7 So x can be either +7 or - 7

Important Dates Diagnostic Test (not included on PowerSchool) Tuesday September 2nd Quiz on Review Sheets 1-4 Thursday September 3rd

Simultaneous Equations LO: To be able to solve Simultaneous Equations by adding or subtracting. Also called ‘Systems of Linear Equations’ STARTER: Expand & Simplify: 1)3(x + 4) + 4(x + 7) 2)2(3y + 6) + 3(2y – 4) 3)6(2m – 10) – 4(5m + 3) 1)7x )12y 3)-8m -72

=80p =£1.30 Why do we need to use Simultaneous Equations? = 50p = 30p

Why do we need to use Simultaneous Equations? Bronze: Solve: 6x + y = 15 4x + y = 11 Silver: Solve: 4x + 3y = 27 2x + y = 17 Gold: Solve: 2x + 3y = 30 5x + 7y = 71 When we have 2 different unknown letters, we can solve the equations at the same time (simultaneously).

Solving Simultaneous Equations – Example 1 Bronze: Solve: 6x + 1y = 15 (1) 4x + 1y = 11 (2) SAME SIGN SUBTRACT Step 1: Eliminate the letter with the same co-efficient (by SUBTRACTING in this question)… 6x + 1y = 15 4x + 1y = x = 4 x = 2 We have 2 unknowns: x and y Step 2: To find y, we substitute x = 2 back into one of the original equations (equation 1) (6 x 2) + y = y = 15 (-12) y = 3

Solving Simultaneous Equations – Example 1 Bronze: Solve: 6x + 1y = 15 (1) 4x + 1y = 11 (2) SAME SIGN SUBTRACT Step 3: Check your answers using equation (2)… x= 2, y = 3 (4 x 2) + 3 = = = 11 We have 2 unknowns: x and y

Silver: Solve: 3x + 3y = 18 (1) 5x + y = -2 (2) When Co-Efficient’s are not the same… SAME SIGN SUBTRACT Step 2: Eliminate the letter with the same co-efficient (by SUBTRACTING in this question) (3) 15x + 3y = -6 (1) 3x + 3y = 18 – 12x = - 24 (÷ 12) x = -2 Step 1: When neither co-efficient’s are the same we multiply one or both equations to make them the same… Multiply equation (2) by x3 15x + 3y = -6 (3) We call this equation (3) We use the original equation 1 and new equation 3.

Silver: Solve: 3x + 3y = 18 (1) 5x + y = -2 (2) When Co-Efficient’s are not the same… Step 3: To find y, we substitute x = -2 back into one of the original equations (equation 1) (3 x -2) + 3y = y = 18 (+ 6) 3y = 24 (÷ 3) y = 8 Step 4: Check your answers using equation 2 x = -2, y = 8 (5 x -2) + 8 = = = -2

Gold:Solve: 2x + 3y = 30 (1) 5x + 7y = 71 (2) When Co-Efficient’s are not the same… (A Grade) SAME SIGN SUBTRACT Step 2: Eliminate the letter with the same co-efficient (by SUBTRACTING in this question) (4) 15x + 21y = 213 (3) 14x + 21y = 210 – x = 3 So x = 3 Step 1: When neither co-efficient’s are the same we may need to multiply both equations to make them the same… Multiply equation (1) by x7 14x + 21y = 210 (3) We call this equation (3) Multiply equation (2) by x3 15x + 21y = 213 (4) We call this equation (4) Now we solve using equation (3) & (4)

When Co-Efficient’s are not the same… (A Grade) Step 3: To find y, we substitute x = 3 back into one of the original equations (equation 1) (2 x 3) + 3y = y = 30 (- 6) 3y = 24 (÷ 3) y = 8 Step 4: Check your answers using equation 2 x = 3, y = 8 (5 x 3) + (7 x 8) = = = 71 Gold: Solve: 2x + 3y = 30 (1) 5x + 7y = 71 (2)

Plenary The sum of two numbers is 19 and their difference is 5. Find the value of each of the numbers.

Review Sheet 4 Questions 1-5 Question 6 as extension