Chapter 5: Exponential and Logarithmic Functions 5.5.A: Logarithmic Functions to Other Bases Essential Question: What must you do to solve a logarithmic function in a base other than 10, with a calculator?
5.5.A: Logarithmic Functions to Other Bases Other logarithmic bases work the same as regular logarithms ◦ log 3 81 = 43 4 = 81 ◦ log 4 64 = 34 3 = 64 ◦ log = 1 / /3 = 5 ◦ log 8 (¼) = - 2 / /3 = ¼
5.5.A: Logarithmic Functions to Other Bases Solving Logarithmic Equations ◦ Log 2 16 = x Can be rewritten as 2 x = 16. Because 2 4 = 16, x = 4 ◦ log 5 (-25) = x Rewritten as 5 x = -25, which isn’t possible. Undefined ◦ log 5 x = 3 Can be rewritten as 5 3 = x, so x = 125
5.5.A: Logarithmic Functions to Other Bases Basic Properties of Other Bases ◦ Same as with regular logs log b v is defined only when v > 0 log b 1 = 0 log b b k = k for every real number k b log b v = v for every v > 0 ◦ Solving Logarithmic Equations log 3 (x – 1) = 4 Rewritten as 3 4 = x – 1 81 = x – 1 82 = x
5.5.A: Logarithmic Functions to Other Bases Laws of Logarithms to Other Bases ◦ Same as with regular logs Product Law:log b (vw) = log b v + log b w Quotient Law:log b ( v / w ) = log b v – log b w Power Law:log b (v k ) = k log b v
5.5.A: Logarithmic Functions to Other Bases Applications of Laws to Other Bases ◦ Given:log 7 2 = log 7 3 = log 7 5 = Find log 7 10, log 7 2.5, & log 7 48 log 7 10= log 7 (2 5) = log log 7 5 = = log 7 2.5= log 7 (5 / 2) = log 7 5 – log 7 2 = – =
5.5.A: Logarithmic Functions to Other Bases Applications of Laws to Other Bases ◦ Given:log 7 2 = log 7 3 = log 7 5 = log 7 48= log 7 (3 16) = log 7 (3 2 4 ) = log log = log log 7 2 = (0.3562) =
5.5.A: Logarithmic Functions to Other Bases Change-of-Base Formula ◦ and/or ◦ Proof: v = b log b v ln v = ln (b log b v )*take ln of both sides = log b v ln b*power rule *divide both sides by ln b Proof using log works the same way
5.5.A: Logarithmic Functions to Other Bases Change-of-Base Formula (Application) ◦ Find log 8 9
5.5.A: Logarithmic Functions to Other Bases Transforming Logarithmic Functions ◦ Involving other bases works no differently from regular logarithmic transformations Describe the transformation from g(x) = log 2 x to h(x) = log 2 (x + 1) – 3 +1: close to the x, therefore horizontal Shifts one unit to the left (horizontal → opposite) - 3: away from the x, therefore vertical Shifts three units down
5.5A: Properties and Laws of Logarithms Assignment ◦ Page 377 ◦ Problems 41-71, odd problems ◦ Show work