How to Figure a Bill of Materials

Materials Being Used ItemQuantityUnit CostTotal Cost ¾” Plywood$35 ½” OSB$25 2x4x8 Studs$3 2x4x16$7 2x12x16$9 Trusses$150 Shingles$ Tile$12 Drywall$ 18 Total

30 45 Spacing = 16”oc

Floor Materials – 2x12x16’s – ¾” Plywood Equations – Distance x 12/Spacing + 1 – Area/32 – End Caps

Floor x12x16’s – Distance x 12/spacing + 1 – 45x12/16+1= – = 35 – But a 16’ Board will not reach 30’ – 35 x 2= 70 End Caps – Length x 2/board length – 45x2/16 – 5.63 = 6 Plywood – Area/32 – 45 x 30/32 – 42.2 = 43

Walls Materials – 2x4x8 Studs – 2x4x16 – ½” OSB Equations – Distance x 12/Spacing + 1 – Area/32 – Sills/Top Plate

Wall x4x8 Studs – Distance x 12/spacing +1 – 45x12/ = 35x 2= 70 – 30x12/ = 24x2= 48 2x4x16 – (Length x 2/ Board length)x3 – (45+30)x2/ = 10 x3= 30

Wall OSB – Area/ 32 – Wall Height – 45x8/ = 12 x 2 = 24 – 30x8/ = 8 x 2 = 16 – Total Sheets 24+16= 40

Roof Materials – Trusses Equations Distance x 12/Spacing + 1 Trusses – 45x12/

Roof 36’ Height= 8’ Materials – ½” OSB – Shingles Equations – Pythagorean Theorem – Area/32 – Area/100

Roofing OSB – Pythagorean Theorem (8x8)+(18x18)=(CxC) = 20 – Area/32 20x45/ = 29 x2=28 36’ Height= 8’

Roofing Shingles – 45 x 20/100 – 9 x 2 – 18 Bundles – Shingles are sold in bundles that cover 10’ x 10’ 36’ Height= 8’

Drywall Materials – 4x12 Drywall Equations – Area/48 Problem – 45x8/ = 8 – 30x8/48 5 – 45x30/ = 29 – =

Tile Materials – 12” Tile – 10 Tile/Box Equations – Area/ Coverage Area – 45x30/1 – 1350 – 1350/10 – 135 Boxes

Materials Being Used ItemQuantityUnit CostTotal Cost ¾” Plywood$35 ½” OSB$25 2x4x8 Studs$3 2x4x16$7 2x12x16$9 Trusses$150 Shingles$ Tile$12 Drywall$ 18 Total