Electric Machinery 王嘉帷 MA320108.

Slides:



Advertisements
Similar presentations
Analysis of magnetic circuits
Advertisements

CHAPTER 5: TRANSFORMER AND MUTUAL INDUCTANCE
Transformers A transformer consists of several independent windings (N 1, N 2, N 3, …) which link the same, low reluctance, magnetic path. One terminal.
STUDY GUIDE CHAPTER 23 SECTION 5 MSTC Physics C. Mutual Inductance If 2 coils of wire are placed near one another, a changing I in one will induce an.
Inductors and Inductance A capacitor can be used to produce a desired electric field. Similarly, an inductor (symbol ) can be used to produce a desired.
3.1 FORCES AND TORQUES IN MAGNETIC FIELD SYSTEMS
Electromagnetism and magnetic circuits.
Magnetic Circuits and Transformers
Magnetic Flux Let us consider a loop of current I shown in Figure(a). The flux  1 that passes through the area S 1 bounded by the loop is Suppose we pass.
Lesson 14 – Capacitors & Inductors. Learning Objectives Define capacitance and state its symbol and unit of measurement. Predict the capacitance of a.
Summary of the last lecture
Problem # 1-6/5 mean core length = 52 cm length of air gap = 0.14 cm
ECE 201 Circuit Theory I1 Physical Characteristics of Inductors.
Internal inductance versus external inductance
AHBMH DEE2113 : Chapter 5 - Transformer & Mutual Inductance 1 CHAPTER 5: TRANSFORMER AND MUTUAL INDUCTANCE Review of Magnetic Induction Mutual Inductance.
Physics 4 Inductance Prepared by Vince Zaccone
ELECTRICAL ENGINEERING: PRINCIPLES AND APPLICATIONS, Third Edition, by Allan R. Hambley, ©2005 Pearson Education, Inc. Chapter 15 Magnetic Circuits and.
Lesson 4: Solving Magnetic Circuits with Electrical Analogies ET 332a Dc Motors, Generators and Energy Conversion Devices 1.
Magnetic Field Basic Concepts:
Storey: Electrical & Electronic Systems © Pearson Education Limited 2004 OHT 14.1 Inductance and Magnetic Fields  Introduction  Electromagnetism  Reluctance.
Magnetic and Electromagnetic Fields
INDUCTANCE Plan:  Inductance  Calculating the Inductance  Inductors with Magnetic materials.
Inductance and Inductors
Self-Inductance When the switch is closed, the current does not immediately reach its maximum value Faraday’s law can be used to describe the effect.
Transformers Mechanical and Electrical Systems SKAA 2032
I l Amperes Law I is the total current linking the magnetic flux. It may be N wires carrying I/N amperes. l.
Inductance and AC Circuits. Mutual Inductance Self-Inductance Energy Stored in a Magnetic Field LR Circuits LC Circuits and Electromagnetic Oscillations.
Copyright © 2009 Pearson Education, Inc. Chapter 33 Inductance, Electromagnetic Oscillations, and AC Circuits.
CHAPTER 5 MAGNETIC CIRCUIT
Chapter 1 MAGNETIC CIRCUIT.
Chapter 2 Electromagnetism Dr. Mohd Junaidi Abdul Aziz
Introduction to Electromechanical Energy Conversion
Coupling Element and Coupled circuits Coupled inductor Ideal transformer Controlled sources.
Chapter 13 Principles of Electric Circuits, Conventional Flow, 9 th ed. Floyd © 2010 Pearson Higher Education, Upper Saddle River, NJ All Rights.
Fundamentals of Electromagnetics and Electromechanics
Tutorial - Magnetic Circuits & Electromagnetic Induction
Chapter 32 Inductance. Self-inductance Some terminology first: Use emf and current when they are caused by batteries or other sources Use induced emf.
Slide 1Fig 32-CO, p Slide 2  As the source current increases with time, the magnetic flux through the circuit loop due to this current also increases.
Chapter 13 Principles of Electric Circuits, Conventional Flow, 9 th ed. Floyd © 2010 Pearson Higher Education, Upper Saddle River, NJ All Rights.
Today Course overview and information 09/16/2010 © 2010 NTUST.
Copyright © 2009 Pearson Education, Inc. Chapter 32: Inductance, Electromagnetic Oscillations, and AC Circuits.
Chapter 29 Electromagnetic Induction and Faraday’s Law
ELECTRICAL ENGINEERING: PRINCIPLES AND APPLICATIONS, Fourth Edition, by Allan R. Hambley, ©2008 Pearson Education, Inc. Lecture 21 Magnetic Circuits, Materials.
9. Inductance M is a geometrical factor! L is a geometrical factor!
CHAPTER 32 : INDUCTANCE Source = source emf and source current Induced = emfs and currents caused by a changing magnetic field. S R I I 1st example Consider.
Inductance.
1 MAGNETOSTATIC FIELD (MAGNETIC FORCE, MAGNETIC MATERIAL AND INDUCTANCE) CHAPTER FORCE ON A MOVING POINT CHARGE 8.2 FORCE ON A FILAMENTARY CURRENT.
MAGNETIC CIRCUITS Electrical current flowing along a wire creates a magnetic field around the wire, as shown in Fig. That magnetic field can be visualized.
Lesson 3: Solving Magnetic Circuits
Monday, April 23, PHYS , Spring 2007 Dr. Andrew Brandt PHYS 1444 – Section 004 Lecture #19 Monday, April 23, 2007 Dr. Andrew Brandt Inductance.
1 ENE 325 Electromagnetic Fields and Waves Lecture 9 Magnetic Boundary Conditions, Inductance and Mutual Inductance.
BASIC ELECTRICAL TECHNOLOGY Chapter 4 – Magnetic Circuits
Copyright © 2009 Pearson Education, Inc. Chapter 30 Inductance, Electromagnetic Oscillations, and AC Circuits HW8: Chapter 28:18,31,40 Chapter 29:3, 30,48.
L-8 MAGNETIC CIRCUITS ELE 1001: Basic Electrical Technology
EMLAB 1 Chapter 9. Magnetic forces, materials, and inductance.
Magnetics.
Chapter 30 Inductance, Electromagnetic Oscillations, and AC Circuits
Mutual Inductance Mutual inductance: a changing current in one coil will induce a current in a second coil: And vice versa; note that the constant M, known.
TRANSFORMER A transformer is a static device.
BASIC ELECTRICAL TECHNOLOGY Chapter 4 – Magnetic Circuits
Electric Machine Magnetic Circuit
Magnetic Circuits.
ENE 325 Electromagnetic Fields and Waves
Problems
Energy Conversion and Transport George G. Karady & Keith Holbert
Chapter 1 Introduction to Machinery Principles
L-9 MAGNETIC CIRCUITS.
Electrical Machines (EELE 3351)
Chapter 32 Problems 6,7,9,16,29,30,31,37.
Chapter 32 Examples 1,2.
Presentation transcript:

Electric Machinery 王嘉帷 MA320108

1. 22 The magnetic circuit of Fig. 1 1.22 The magnetic circuit of Fig. 1.32 has two windings and two air gaps. The core can be assumed to be of infinite permeability. The core dimensions are indicated in the figure. 圖1.32的磁路具有兩個繞組和兩個空隙。鐵芯可以被假定為無窮滲透性。 Figure 1.32

a. Assuming coil 1 to be carrying a current Il and the current in coil 2 to be zero, calculate (i) the magnetic flux density in each of the air gaps, (ii) the flux linkage of winding l, and (iii) the flux linkage of winding 2. 假設線圈1帶電流I1,線圈2的電流為零,計算(i)在每個空隙磁通密度,(ⅱ)繞組1的磁通鏈,(iii)繞組2的磁通鏈。

b. Repeat part (a), assuming zero current in winding 1 and a current I2 in winding 2. 重複(a)部分,假設在繞組1電流為零,繞組2電流I2。

c. Repeat part (a), assuming the current in winding 1 to be I1 and the current in winding 2 to be I2. 重複(a)部分,假設繞組1電流是I1,繞組2電流為I2。

d. Find the self-inductances of windings 1 and 2 and the mutual inductance between the windings. 找出繞組1和2的自感,和繞組之間的互感的。

1. 23 The symmetric magnetic circuit of Fig. 1. 33 has three windings 1.23 The symmetric magnetic circuit of Fig. 1.33 has three windings. Windings A and B each have N turns and are wound on the two bottom legs of the core. The core dimensions are indicated in the figure. 圖1.33的對稱磁路具有三個繞組。繞組A和B各自有N個線匝,並纏繞在鐵芯的兩個底腿。 Figure 1.33

a. Find the self-inductances of each of the windings. 找到每個繞組的自感。

b. Find the mutual inductances between the three pairs of windings. 找出三對繞組之間的互感。

c. Find the voltage induced in winding 1 by time-varying currents iA(t) and iB (t) in windings A and B. Show that this voltage can be used to measure the imbalance between two sinusoidal currents of the same frequency. 找出感應繞組1隨時間變化繞組A和B中電流iA(t)和iB(t)的電壓。該電壓可以用來測量相同頻率的兩個正弦電流之間的不平衡。

1. 28 The coils of the magnetic circuit shown in Fig. 1 1.28 The coils of the magnetic circuit shown in Fig. 1.36 are connected in series so that the mmf's of paths A and B both tend to set up flux in the center leg C in the same direction. The coils are wound with equal turns, Nl = N2 = 100. 圖1.36所示的線圈磁路串聯連接,以使磁動勢的通道A和B兩者的傾向於在中間相同方向建立磁通量。線圈匝數以等比纏繞,N1= N 2= 100。 Figure 1.36

The dimensions are: Cross-section area of A and B legs = 7 cm 2 Cross-section area of C legs = 14 cm 2 Length of A path = 17 cm Length of B path = 17 cm Length of C path = 5.5 cm Air gap = 0.4 cm The material is M-5 grade, 0.012-in steel, with a stacking factor of 0.94. Neglect fringing and leakage. A和B的截面積=7平方公分、C的截面積=14平方公分 A長17cm、B長17cm、C長5.5cm 空隙=0.4cm 材質M-5級,0.012的鋼,0.94的疊層係數 忽視邊緣和洩漏

a. How many amperes are required to produce a flux density of 1 a. How many amperes are required to produce a flux density of 1.2 T in the air gap? From the M-5 magnetization curve, for B = 1.2 T, Hm = 14 A/m. Similarly, Hg = B/μ0 = 9.54 × 105 A/m. Thus, with I1 = I2 = I 要多少安培才能在空隙中產生的1.2T的磁通密度在空隙? 從M-5的磁化曲線,for B = 1.2 T, Hm = 14 A/m. 同理,Hg = B/μ0 = 9.54 × 105 A/m. Thus, with I1 = I2 = I

b. Under the condition of part (a), how many joules of energy are stored in the magnetic field in the air gap? 在(a)的狀況下,在空隙中的磁場儲存多少焦耳能量?

c. Calculate the inductance. 計算電感