Splash Screen. Lesson Menu Five-Minute Check (over Chapter 7) Main Idea and Vocabulary Example 1:Write Expressions With Addition Example 2:Write Expressions.

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Presentation transcript:

Splash Screen

Lesson Menu Five-Minute Check (over Chapter 7) Main Idea and Vocabulary Example 1:Write Expressions With Addition Example 2:Write Expressions With Addition Example 3:Write Expressions with Subtraction Example 4:Write Expressions with Subtraction Example 5:Identify Parts of an Expression Example 6:Simplify Algebraic Expressions Example 7:Simplify Algebraic Expressions Example 8:Real-World Example

Main Idea/Vocabulary equivalent expressions term coefficient like terms Use the Distributive Property to simplify algebraic expressions. constant simplest form simplifying the expression

Example 1 Write Expressions With Addition Use the Distributive Property to rewrite 3(x + 5). 3(x + 5) = 3(x) + 3(5) = 3x + 15Simplify. Answer: 3x + 15

1.A 2.B 3.C 4.D Example 1 Use the Distributive Property to rewrite 2(x + 6).

Example 2 Use the Distributive Property to rewrite (a + 4)7. (a + 4)7= a ● ●7 = 7a + 28Simplify. Answer: 7a + 28 Write Expressions With Addition

1.A 2.B 3.C 4.D Example 2 Use the Distributive Property to rewrite (a + 6)3.

Example 3 Write Expressions With Subtraction Use the Distributive Property to rewrite (q – 3)9. (q – 3)9 = [q + (–3)]9Rewrite q – 3 as q + (–3). = (q)9 + (–3)9Distributive Property = 9q + (–27)Simplify. = 9q – 27Definition of subtraction Answer: 9q – 27

1.A 2.B 3.C 4.D Example 3 Use the Distributive Property to rewrite (q – 2)8.

Example 4 Write Expressions With Subtraction Use the Distributive Property to rewrite –3(z – 7). Answer: –3z + 21 –3(z – 7)= –3[z + (–7)]Rewrite z – 7 as z + (–7). = –3(z) + (–3)(–7)Distributive Property = –3z + 21Simplify.

1.A 2.B 3.C 4.D Example 4 Use the Distributive Property to rewrite –2(z – 4).

Example 5 Identify Parts of an Expression Identify the terms, like terms, coefficients, and constants in 3x – 5 + 2x – x. 3x – 5 + 2x – x= 3x + (–5) + 2x + (–x)Definition of subtraction = 3x + (–5) + 2x + (–1x)Identity Property; –x = –1x Answer: The terms are 3x, –5, 2x, and –x. The like terms are 3x, 2x, and –x. The coefficients are 3, 2, and –1. The constant is –5.

1.A 2.B 3.C 4.D Example 5 Identify the terms, like terms, coefficients, and constants in 6x – 2 + x – 4x.

Example 6 Simplify Algebraic Expressions Simplify the expression 6n – n. 6n – n are like terms. Answer: 5n 6n – n= 6n – 1nIdentity Property; n = 1n = (6 – 1)nDistributive Property = 5nSimplify.

1.A 2.B 3.C 4.D Example 6 Simplify the expression 7n + n.

Example 7 Simplify Algebraic Expressions Simplify 8z + z – 5 – 9z z, z, and –9z are like terms. –5 and 2 are also like terms. Answer: –3 8z + z – 5 – 9z + 2= 8z + z + (–5) + (–9z) + 2Definition of subtraction = 8z + z + (–9z) + (–5) + 2 Commutative Property = [ (–9)]z + [(–5) + 2]Distributive Property = 0z + (–3) or –3Simplify.

1.A 2.B 3.C 4.D Example 7 Simplify 6z + z – 2 – 8z + 2.

Example 8 THEATER Tickets for the school play cost $5 for adults and $3 for children. A family has the same number of adults as children. Write an expression in simplest form that represents the total amount of money spent on tickets. Words$5 each for adults and $3 each for the same number of children. VariableLet x represent the number of adults or children. Equation5 ● x + 3 ● x

Example 8 Simplify the expression. 5x + 3x= (5 + 3)xDistributive Property = 8xSimplify. Answer: The expression $8x represents the total amount of money spent on tickets.

1.A 2.B 3.C 4.D Example 8 A.$2.50x B.$7.50x C.$15.50x D.$17.50x MUSEUM Tickets for the museum cost $10 for adults and $7.50 for children. A group of people have the same number of adults as children. Write an expression in simplest form that represents the total amount of money spent on tickets to the museum.

End of the Lesson

Resources Five-Minute Check (over Chapter 7) Image Bank Math Tools Graphing Equations with Two Variables Two-Step Equations

1.A 2.B 3.C 4.D Five Minute Check 1 Find the area of a triangle with base 10 in. and height 15 in. (over Chapter 7) Find the area of a circle with diameter 14 m.

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