AP Chemistry Chapter 3 Stoichiometry.

Slides:



Advertisements
Similar presentations
CH 3: Stoichiometry Moles.
Advertisements

Balancing Chemical Equations and Stoichiometry
Calculations with Chemical Formulas and Equations
Chapter 3 Stoichiometry: Calculations with Chemical Formulas and Equations.
Chapter 3.  Reactants are left of the arrow  Products are right of the arrow  The symbol  is placed above the arrow to indicate that the rxn is being.
AP Chemistry Stoichiometry HW:
Chapter 3 Chemical Reactions and Reaction Stoichiometry
Chapter Three: Stoichiometry Nick Tang 2 nd Period Ms. Ricks.
Stoichiometric Calculations
Stoichiometry Chapter 3. Atomic Mass Atoms are so small, it is difficult to weigh in grams (Use atomic mass units) Atomic mass is a weighted average of.
Law of Conservation of Mass
Stoichiometry © 2009, Prentice-Hall, Inc. Warmup – Mass Percent Find the percent by mass: 1.What is the mass % of silver in silver nitrate? (63.5%) 2.
Stoichiometry Law of Conservation of Mass “We may lay it down as an incontestable axiom that, in all the operations of art and nature, nothing is created;
© 2012 Pearson Education, Inc. Chapter 3 Stoichiometry: Calculations with Chemical Formulas and Equations John D. Bookstaver St. Charles Community College.
Chapter 3 Stoichiometry: Calculations with Chemical Formulas and Equations.
Chemistry, The Central Science, 12th edition
Stoichiometry Calculations with Chemical Formulas and Equations Chapter 3 BLB 12 th.
Stoichiometry: Calculations with Chemical Formulas and Equations.
Chapter 3 – Stoichiometry: Calculations with Chemical Formulas and Equations Jennie L. Borders.
CHEMISTRY The Central Science 9th Edition
Chapter 3: Stoichiometry Emily Scheerer Section 3.1–Chemical Equations Section 3.2–Patterns of Chemical Reactivity Section 3.3–Atomic and Molecular Weights.
Ch. 3 Stoichiometry: Calculations with Chemical Formulas.
Conservation of Mass (again) I think it must be important? I think it must be important? Lavoisier- observed that the total mass of a substance present.
© 2012 Pearson Education, Inc. Chapter 3 Stoichiometry: Calculations with Chemical Formulas and Equations John D. Bookstaver St. Charles Community College.
Chapter 3 - Stoichiometry It is important to be able to quantify the amount of reagent(s) that will be needed to produce a given amount of product(s).
Chapter 3 Stoichiometry:
SAMPLE EXERCISE 3.3 continued
Chapter 3. Atomic Mass  amu = Average Atomic Mass Unit  Based on 12 C as the standard.  12 C = exactly 12 amu  The average atomic mass (weight) of.
Stoichiometry Chemistry 101 : Chap. 3 Chemical Equations
Stoichiometry  2009, Prentice-Hall, Inc. Chapter 3 Stoichiometry: Calculations with Chemical Formulas and Equations Chemistry, The Central Science, 11th.
© 2012 Pearson Education, Inc. Chapter 3 Stoichiometry: Calculations with Chemical Formulas and Equations Dr. Subhash C. Goel South GA State College Douglas,
Stoichiometry Calculations with Chemical Formulas and Equations.
Chemistry, The Central Science, 10th edition
Chapter 3 Stoichiometry: Calculations with Chemical Formulas and Equations.
Chapter 3 Stoichiometry: Calculations with Chemical Formulas and Equations.
Lecture 5. Chapter 3. Chemical Equations:
Chapter 31 Stoichiometry Mrs. Weston Seneca Valley SHS.
Chapter 3: Stoichiometry Emily Scheerer Section 3.1–Chemical Equations Section 3.2–Patterns of Chemical Reactivity Section 3.3–Atomic and Molecular Weights.
Prentice Hall © 2003Chapter 3 Chapter 3 Stoichiometry: Calculations with Chemical Formulas and Equations FAYETTEVILLE STATE UNIVERSITY COLLEGE OF BASIC.
Chapter 3 Stoichiometry: Calculations with Chemical Formulas and Equations.
Chapter 3 Stoichiometry. Atomic Mass Carbon-12 is assigned a mass of exactly atomic mass units (amu) Masses of other elements are compared to Carbon-12.
1 Chapter 3 Stoichiometry: Calculations with Chemical Formulas and Equations.
ADVANCED CHEMISTRY Chapter 3 Stoichiometry. WHAT IS STOICHIOMETRY? Antoine Lavoisier observed that the total mass before a reaction is equal to the total.
Chemistry II Stoichiometry Chapter 3. Stoichiometery: Calculations with Chemical Formulas and Equations.
Chemistry, The Central Science, 10th edition
Copyright 1999, PRENTICE HALLChapter 31 Stoichiometry: Calculations with Chemical Formulas and Equations Chapter 3 David P. White University of North.
© 2012 Pearson Education, Inc. Chapter 3 Stoichiometry: Calculations with Chemical Formulas and Equations.
UNIT FOUR UNIT FOUR Stoichiometry: Calculations with Chemical Formulas and Equations CHEMISTRY The Central Science 9th Edition.
Chapter 3 Stoichiometry. 3.1 Chemical Equations Law of Conservation of Mass “We may lay it down as an incontestable axiom that, in all the operations.
© 2009, Prentice-Hall, Inc. Chapter 3: Stoichiometry Formula Weight A formula weight is the sum of the atomic weights for the atoms in a chemical formula.
Stoichiometry Law of Conservation of Mass “We may lay it down as an incontestable axiom that, in all the operations of art and nature, nothing is created;
Prentice Hall © 2003Chapter 3 Chapter 3 Stoichiometry: Calculations with Chemical Formulas and Equations CHEMISTRY The Central Science 9th Edition David.
Stoichiometry: Ratios of Combination
© 2015 Pearson Education, Inc. Chapter 3 Chemical Reactions and Reaction Stoichiometry James F. Kirby Quinnipiac University Hamden, CT Lecture Presentation.
Prentice Hall © 2003Chapter 3 Chapter 3 Stoichiometry: Calculations with Chemical Formulas and Equations CHEMISTRY The Central Science 9th Edition.
Mass Relationships in Chemical Reactions Chapter 3 Copyright © The McGraw-Hill Companies, Inc. Permission required for reproduction or display. Acknowledgement.
Chapter 3: Stoichiometry: Calculations with Chemical Formulas and Equations AP Chemistry
Chapter 3 Chemical Reactions and Reaction Stoichiometry
Chapter 3 Chemical Reactions and Reaction Stoichiometry
Law of Conservation of Mass
Reaction Types. Chapter 3 Stoichiometry: Calculations with Chemical Formulas and Equations.
Chapter 3 Chemical Reactions and Reaction Stoichiometry
Chapter 3: Stiochiometry
Chemistry, The Central Science, 11th edition
John D. Bookstaver St. Charles Community College Cottleville, MO
Chemistry, The Central Science, 10th edition
Presentation transcript:

AP Chemistry Chapter 3 Stoichiometry

Stoichiometry Is the study of the quantities of substances consumed and produced in chemical reactions Derived from the Greek words stoicheion meaning “element” and metron meaning “measure”

Law of Conservation of Mass Discovered by Antoine Lavoisier in the late 1700’s Found that the masses of substances after a chemical reaction are equal to the masses of substances before the reaction Atoms are neither created nor destroyed in a chemical reaction Reactions rearrange atoms in order to form new substances

2H2 + O2  2H2O Chemical Equations reactants products “reacts with” coefficient “produces” subscript Indicates relative numbers of molecules/atoms Indicates number of atoms in a molecule

Balancing Equations To satisfy the law of conservation of mass Done by adding or changing coefficients NEVER balance an equation by changing subscripts!

Balancing Equations Helpful Hints: Start balancing with the elements that appear in the fewest chemical formulas on each side of the equation Balance oxygen last Balance hydrogen next to last

Sample Exercise 3.1 The following diagram represents a chemical reaction in which the red spheres are oxygen atoms and the blue spheres are nitrogen atoms. (a) Write the chemical formula for the reactants and the products. (b) Write a balanced equation for the reaction. (c) Is the diagram consistent with the law of conservation of mass?

State Symbols Used to indicate the states of reactants and products in chemical reactions (g) (l) (s) (aq) ∆ above the arrow indicates addition of heat to the reaction

Sample Exercise 3.2 Balance this equation: Na(s) + H2O(l)  NaOH(aq) + H2(g)

Simple Patterns in Reactions Combination (Synthesis) Decomposition 2 or more substances react to form one product one substance undergoes a reaction to produce 2 or more other substances Examples: Examples: 2 Mg(s) + O2(g)  2MgO(s) 2 H2(g) + O2(g)  2H2O(g) 2NaN3(s)  2Na(s) + 3N2(g) CaCO3(s)  CaO(s) + CO2(g)

Decomposition Reactions Many compounds undergo decomposition reactions when heated. Metal carbonates often decompose to form a metal oxide and carbon dioxide gas.

Sample Problem 3.3 Write balanced equations for the following reactions: (a) The combination reaction that occurs when lithium metal and fluorine gas react. (b) The decomposition reaction that occurs when solid barium carbonate is heated.(Two products form: a solid and a gas.)

Combustion in Air Reaction with oxygen Rapid reaction that produces a flame Combustion of hydrocarbons produce CO2 and H2O Not enough oxygen available? CO formed Severe lack of oxygen? Solid carbon (soot) formed

Oxidation vs. Combustion Conversion of glucose in the body happens at body temperature and without the production of a flame…this is oxidation rather than combustion. C6H12O6 + 6O2  6CO2 + 6H2O

Sample Exercise 3.4 Write the balanced equation for the reaction that occurs when methanol, CH3OH(l), is burned in air.

Formula Weights Sum of atomic weights of each atom in the chemical formula of a compound Example: H2SO4 has a formula weight of 98.1 amu Atomic weight (for atoms) and molecular weight (for molecular compounds)

Sample Exercise 3.5 Calculate the formula weight of (a) sucrose, C12H22O11, and (b) calcium nitrate, Ca(NO3)2

Percentage Composition Percent by mass contributed by each element in the substance

Sample Exercise 3.6 Calculate the percentage of carbon, hydrogen, and oxygen in C12H22O11.

Avogadro’s Number & the Mole 6.022 x 1023 Indicates the number of particles (atoms, ions, or molecules) in a mole FYI: mole comes from Latin and means “a mass” molecule is the diminutive form of the word and means “a small mass”

Sample Exercise 3.7 Without using a calculator, arrange the following samples in order of increasing numbers of carbon atoms: 12 g 12C, 1 mol C2H2, 9 x1023 molecules of CO2.

Molar Mass Mass in grams of one mole of a substance Units are g/mol Numerically equivalent to formula weight

Sample Exercise 3.9 What is the mass in grams of 1.00 moles of glucose, C6H12O6?

Sample Exercise 3.10 Calculate the number of moles of glucose, C6H12O6, in 5.30 g of C6H12O6.

Sample Exercise 3.11 Calculate the mass, in grams, of 0.433 mol of calcium nitrate.

Converting between grams and atoms/molecules Conversion factors: 1 mole = 6.022 x 1023 particles 1 mole = ________ grams molar mass

Sample Exercise 3.12 (a) How many glucose molecules are in 5.23 g of C6H12O6? (b) How many oxygen atoms are in this sample?

Empirical Formulas Gives the relative numbers of atoms of each element in a substance Based on experiments that give the # of moles of each element in a sample of the compound Empirical means based on observation & experiment

Finding Empirical Formulas Mass % of elements assume 100 grams Empirical formula Grams of each element divide by the smallest # of moles use molar mass Moles of each element Mole ratio* multiply until all #’s are whole * Due to experimental errors, results may not lead to exact integers Ex. 1.99 2

Molecular Formulas Subscripts in a molecular formula are always a whole number multiple of the corresponding subscripts in the corresponding empirical formula Whole # multiple = molecular weight empirical formula weight

Sample Exercise 3.13 Ascorbic acid (vitamin C) contains 40.92% C, 4.58% H, and 54.50% O by mass. What is the empirical formula of ascorbic acid?

Sample Exercise 3.14 Mesitylene, a hydrocarbon that occurs in small amounts in crude oil, has an empirical formula of C3H4. The experimentally determined molecular weight of the substance is 121 amu. What is the molecular formula of mesitylene?

Sample Exercise 3.15 Isopropyl alcohol, a substance sold as rubbing alcohol, is composed of C, H, and O. Combustion of 0.255 g of isopropyl alcohol produces 0.561 g of CO2 and 0.306 g of H2O. Determine the empirical formula of isopropyl alcohol.

Quantitative Information from Equations Coefficients  indicate relative numbers of molecules involved in a reaction (also relative # of moles) Stoichiometrically equivalent to…use coefficients to make mole conversion factors between different substances involved in a reaction

Sample Exercise 3.16 How many grams of water are produced in the oxidation of 1.00 g of glucose, C6H12O6?

Sample Exercise 3.17 Solid lithium hydroxide is used in space vehicles to remove exhaled carbon dioxide. The lithium hydroxide reacts with gaseous carbon dioxide to form solid lithium carbonate and liquid water. How many grams of carbon dioxide can be absorbed by 1.00 gram of lithium hydroxide?

2 Bd + Ch  Bd2Ch Limiting Reactants Let’s make a sandwich! 10 slices can make 5 sandwiches can make 7 sandwiches In this reaction, bread is the limiting reactant and will be completely used up. Cheese is the excess reactant. We will have 2 slices of cheese left over once the reaction has completed.

Limiting Reactants Also called limiting reagents In a chemical reaction, the reaction stops when one reactant is totally used up. This is the limiting reactant.

Limiting Reactant Example 2H2(g) + O2(g)  2H2O(l) Initially we have 10 mol hydrogen gas and 7 moles oxygen gas. Which is limiting and how much excess remains unreacted?

Sample Exercise 3.18 The most important commercial process for converting N2 from the air into nitrogen-containing compounds is based on the reaction of N2 and H2 to form ammonia (NH3): N2(g) + 3H2(g)  2NH3(g) How many moles of NH3 can be formed from 3.0 mol of N2 and 6.0 mol of H2?

Sample Exercise 3.19 Consider the following reaction: 2 Na3PO4 (aq) + 3 Ba(NO3)2(aq)  Ba3(PO4)2 (s) + NaNO3 (aq) Suppose a solution containing 3.50 g of Na3PO4 is mixed with a solution containing 6.40 g of Ba(NO3)2. How many grams of Ba3(PO4)2 can be formed?

Sample Exercise 3.20 Adipic acid, H2C6H8O4 , is used to produce nylon. The acid is made commercially by a controlled reaction between cyclohexane (C6H12) and O2: 2 C6H12 (l) + 5 O2(g)  2 H2C6H8O4 (l) + 2H2O (g) (a) Assume that you carry out this reaction starting with 25.0 g of cyclohexane and that cyclohexane is the limiting reactant. What is the theoretical yield of adipic acid? (b) If you obtain 33.5 g of adipic acid from your reaction, what is the percent yield of adipic acid?