Information given by chemical equations

Slides:



Advertisements
Similar presentations
LIMITING REACTANT The reactant that gives the least number of product moles “limits” the reaction. To understand this concept, let’s suppose you were an.
Advertisements

Chapter 11 “Stoichiometry”
Stoichiometry Chapter 12.
HONORS CHEMISTRY Feb 27, Brain Teaser Cu + 2 AgNO 3  2 Ag + Cu(NO 3 ) 2 – How many moles of silver are produced when 25 grams of silver nitrate.
Stoichiometry Chapter 12.
Unit 3 Test (Part 2) Review Stoichiometry. Balancing Equations Balance the following chemical equation: ____ Ag 2 O  ____ Ag + ____O 2.
Limiting Reagent What happens in a chemical reaction, if there is an insufficient amount of one reactant?
Limiting reagent, Excess reactant, Theoretical or Percent yield
Unit 3: Chemical Equations and Stoichiometry
Information given by chemical equations
Stoichiometry The Study of Quantitative Relationships.
STOICHIOMETRY CALCULATIONS COACH COX. MOLE TO MOLE CONVERSIONS Converting from moles of one substance in a chemical reaction to moles of another substance.
Stoichiometry The Math of Chemical Reactions Unit 9.
Quantitative Relationships (Stoichiometry). Lets take a moment… sit back… relax… and review some previously learned concepts… Lets take a moment… sit.
Turn in last week’s catalyst and grab calculator and worksheet. Sit in lab seats. Objective: Convert between moles of substances in an equation. Convert.
Chapter 9 Stoichiometry
Chapter 3. Atomic Mass  amu = Average Atomic Mass Unit  Based on 12 C as the standard.  12 C = exactly 12 amu  The average atomic mass (weight) of.
The Mathematics of Chemical Equations Stoichiometry.
1 STOICHIOMETRY 2 General Approach For Problem Solving 1. Clearly identify the Goal or Goals and the UNITS involved. (starting and ending unit) 2. Determine.
CHEMICAL EQUATIONS PRACTICE: –BALANCING FOR CONSERVATION OF MASS –TYPES OF REACTIONS.
Chapter 12 Review “Stoichiometry”
Notes #3 Grams to grams stoichiometry 4- step bridge.
Reaction Stoichiometry. Mole Ratio Coefficients of a balanced chemical equation show us the ratio of molecules or moles in a chemical reaction 2H 2 +
Solution types of stoichiometry problems are no harder than any other stoichiometry problem. You must use the concentration given (molarity) to convert.
MOLE-MOLE AND MASS-MASS CONVERSIONS Stoichiometry 1.
Stoichiometry. Information Given by the Chemical Equation  The coefficients in the balanced chemical equation show the molecules and mole ratio of the.
Proportional Relationships b Stoichiometry mass relationships between substances in a chemical reaction based on the mole ratio b Mole Ratio indicated.
Stoichiometry. The study of chemical changes is at the heart of chemistry. Stoichiometry is the area of study that examines the quantities of substances.
Reaction Stoichiometry. Mole Ratio Coefficients of a balanced chemical equation show us the ratio of molecules or moles in a chemical reaction 2H 2 +
Start-Up What is the molar mass for Calcium hydroxide? A g/mol B g/mol C g/mol D. 27 g/mol.
Reactions Chapter 8. Chemical Reaction Equations A reaction equation must… A reaction equation must… Represent all known facts Represent all known facts.
Do Now: 9/8 AgNO 3(aq) + CaCl 2(aq) --> Ca(NO 3 ) 2(aq) + AgCl (s) 1.What is the molar mass of Silver Nitrate? (AgNO 3 ) 2.What does it mean to have a.
 Objective: Understand molecular formulas and balancing equations.  Before: Introduction to molecular formulas  During: Discuss molecular formulas.
Stoichiometry.
III Equation Problems A What does an equation represent? Represents chemical change Made up “reactants” and “products”  Reactants  starting materials.
Stoichiometry. What Is It? Branch of chemistry that shows the relationships among reactants and products in a chemical reaction Equations must be balanced.
$100 $200 $300 $400 $500 $100 $200 $300 $400 $500 $100 $200 $300 $400 $500 $100 $200 $300 $400 $500 $100 $200 $300 $400 $500 $100 $200 $300.
REVIEW: Converting to MOLES WHAT DOES A MOLE REPRESENT? 6.02 x MASS # MOLES Molecular Weight # particles # MOLES 6.02 X Volume of a gasMoles.
I. I.Stoichiometric Calculations Stoichiometry. History of Stoichiometry b Comes from the Greek: Stoicheion - to measure the elements.
Chapter 12 Notes. Information given by chemical equations 2 C 6 H 6 (l) + 15 O 2 (g)  12 CO 2 (g) + 6 H 2 O (g)  In this equation there are 2 molecules.
Unit 3 Test (Part 2) Review Stoichiometry. Balancing Equations Balance the following chemical equation: ____ Ag 2 O  ____ Ag + ____O 2.
The Mole, part II Glencoe, Chapter 11 Sections 11.3 & 11.4.
1 Chapter 9 Mole Factors Calculations with Equations Limiting Reactions Percent Yield.
Unit 8 Review Stoichiometry Complete on Markerboard or in your notes.
Chemistry 20 Stoichiometry. This unit involves very little that is new. You will merely be applying your knowledge of previous units to a new situation.
Stoichiometry.
Stoichiometry Warmup I have 1 mole of CO 2 gas at STP. How many grams of CO 2 do I have? How many Liters of CO 2 do I have? How many molecules of CO 2.
Mass-Mass Stoichiometry If the mass of any reactant or product is known for a chemical reaction, it is possible to calculate the mass of the other reactants.
Stoichiometry is… Greek for “measuring elements” Defined as: calculations of the quantities in chemical reactions, based on a balanced equation. There.
By Steven S. Zumdahl & Donald J. DeCoste University of Illinois Introductory Chemistry: A Foundation, 6 th Ed. Introductory Chemistry, 6 th Ed. Basic Chemistry,
Can’t directly measure moles Measure units related to moles: –Mass (molar mass) –Number of particles (6.02 x ) –Liters of gas (22.4 Liters at STP)
Mass to Mass Conversions. Mole to Mole Conversions are the CRUCIAL LINK Follow the same steps: Step 1: Balance the equation Step 2: Write down what you.
Good Morning! Today is Tuesday, January 5, 2016 HW Due: Balancing Review Please put in the Inbox Do-Now: What do you think the term stoichiometry means?
Stoichiometry GPS 13. Stoichiometry Example: 2H 2 + O 2 → 2H 2 O Equivalencies: 2 mol H 2 for every 1 mol O 2 2 mol H 2 for every 2 mol H 2 O 1 mol O.
Stoichiometry: Limiting Reactants Chapter 9 Lesson 3.
Chemical Reactions. Signs of a Chemical Reaction: -Evolution of light and heat -Formation of a gas -Formation of a precipitate -Color change.
Stoichiometry. Stoichiometry is the study of the mass relationships of the reactants and the products in a chemical reaction. How much stuff it takes.
The Mole & Chemical Composition Chemical Equations.
Stoichiometry Chapter 9 Limiting Reagents Stoich ppt _5 Limiting Reagents Practice.
Stoichiometry Introduction to Chemistry. Stoichiometry Example: 2H 2 + O 2 → 2H 2 O Equivalencies: 2 mol H 2 for every 1 mol O 2 2 mol H 2 for every 2.
Limiting Reagent What happens in a chemical reaction, if there is an insufficient amount of one reactant?
7.4 Calculations Involving Limiting Reagents
Chapter 12 Review.
Chapter 12 Review.
Stoichiometric Calculations (p. 352 – 367)
Unit 4: Chemical Equations and Stoichiometry
Unit 4: Chemical Equations and Stoichiometry
Information given by chemical equations
Stoichiometry Easy as 1,2,3!!! .
Mole ratios Mole to mole conversions
Presentation transcript:

Information given by chemical equations 2 C6H6 (l) + 15 O2 (g)  12 CO2 (g) + 6 H2O (g) In this equation there are 2 molecules of benzene reacting with 15 molecules of oxygen to produce 12 molecules of carbon dioxide and 6 molecules of water. This equation could also be read as 2 moles of benzene reacts with 15 moles of oxygen to produce 12 moles of carbon dioxide and 6 moles of water. Since the relationship between the actual number of molecules and the number of moles present is 6.02 x 1023, a common factor between all species involved in the equation, a MOLE RATIO relationship can be discussed.

Information given by chemical equations 2 C6H6 (l) + 15 O2 (g)  12 CO2 (g) + 6 H2O (g) The MOLE RATIO for benzene and oxygen is 2 : 15. It can be written as: 2 moles C6H6 or as 15 moles of O2 15 moles O2 2 moles of C6H6 The MOLE RATIO for oxygen and carbon dioxide is 15 : 12. It can be written as: 12 moles CO2 or as 15 moles of O2 15 moles O2 12 moles of CO2 NOTE: The MOLE RATIO is used for converting moles of one substance into moles of another substance. Without the balanced equation there is no other relationship between two different compounds.

STOICHIOMETRY !!!!! 2 H2 (g) + O2 (g)  2 H2O (g) Using the mole ratio to relate the moles of one compound to the moles of another compound is the part of chemistry called STOICHIOMETRY !!!!! 2 H2 (g) + O2 (g)  2 H2O (g) Q. How many mole of hydrogen are necessary to react with 2 moles of oxygen in order to produce exactly 4 moles of water? A. 2 mol O2 (2 moles H2 / 1 mole O2) = 4 mole H2

STOICHIOMETRY The Stoichiometry Flow Chart Use mole ratio from equation Use Molar mass (A) Use Molar mass (B)

STOICHIOMETRY 2 H2 (g) + O2 (g)  2 H2O (g) Q1. How many moles of hydrogen are necessary to react with 15.0 g of oxygen? A. 15.0g O2 (1 mole O2 ) ( 2 mole H2) = 0.938 moles H2 32.0 g 1 mole O2 Q2. How many grams of hydrogen are necessary to react with 15.0 g of oxygen? A. 15.0g O2 (1 mole O2 ) ( 2 mole H2) ( 2.016 g H2) = 1.89 g H2 32.0 g 1 mole O2 1 mole H2

STOICHIOMETRY 2 H2 (g) + O2 (g)  2 H2O (g) Q3. How many grams of water are produced from 15.0 g of oxygen? A. 15.0g O2 (1 mole O2 ) ( 2 mole H2O) ( 18.0 g H2O) =16.9 g H2O 32.0 g 1 mole O2 1 mole H2O Q4. How much hydrogen and oxygen is needed to produce 25.0 grams of water? A. 25.0g H2O (1 mole H2O ) ( 2 mole H2) ( 2.016 g H2) = 2.80 g H2 18.0 g 2 mole H2O 1 mole H2 A. 25.0g H2O (1 mole H2O ) ( 1 mole O2) ( 32.0 g O2) = 22.2 g O2 18.0 g 2 mole H2O 1 mole O2 Notice that the Law of Conservation of Mass still applies.

3 Pb+2 H3PO4  Pb3(PO4)2 (s) + 3 H2 (g) How many grams of solid are formed when 10.0 g of lead reacts with excess phosphoric acid? Write the chemical equation: Pb + H3PO4  ? You recognize that this is a single displacement (replacement) reaction. So Pb (a metal) will displace (replace) H (the cation). Pb + H3PO4  Pb3(PO4)2 + H2 2. Balance the equation: 3 Pb+2 H3PO4  Pb3(PO4)2 + 3 H2 3. Make a list under the appropriate substance 3 Pb+2 H3PO4  Pb3(PO4)2 (s) + 3 H2 (g) 10.0g m=? Start with what is given: 10.0gPb (1 mole Pb)( 1 mole Pb3(PO4)2)(811 g Pb3(PO4)2) = 13.1 g Pb3(PO4)2 207 g Pb 3 mole Pb 1 mole Pb3(PO4)2

PRACTICE PROBLEM # 18 14.20g 0.182 mol 157.7 g 254 g 424.9 g 1. How many grams of gas can be produced from 0.8876 moles of HgO? 2 HgO  2 Hg + O2 2. How many moles of fluorine are required to produce 12.0 grams of KrF6? Given the equation: Kr + 3 F2  KrF6 3. How many grams of Na2CO3 will be produced from the thermal decomposition of 250.0 g of NaHCO3? 4. How many grams of CO2 can be produced by the reaction of 75.0 grams of C2H2 with excess oxygen? 5. Cu + 2 AgNO3  Cu(NO3)2 + 2 Ag. How many grams of silver is produced when 125.0 g of copper is reacted with excess silver nitrate solution? 14.20g 0.182 mol 157.7 g 254 g 424.9 g

GROUP STUDY PROBLEM # 18 ______1. How many grams of liquid product can be produced from 3.55 moles of HgO? 2 HgO  2 Hg + O2 ______2. How many moles of fluorine are required to produce 3.0 grams of KrF6? Given the equation: Kr + 3 F2  KrF6 ______3. How many grams of Na2CO3 will be produced from the decomposition of 20.0g of NaHCO3? ______4. How many grams of O2 are needed to combust 55.0 grams of C2H4? ______5. Cu + 2 AgNO3  Cu(NO3)2 + 2 Ag. How many grams of silver is produced when 50.0 g of copper is reacted with excess silver nitrate solution?