Chapter 20 AC Network Theorems.

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Presentation transcript:

Chapter 20 AC Network Theorems

Superposition Theorem Voltage across (or current through) an element Determined by summing voltage (or current) due to each independent source All sources (except dependent sources) other than the one being considered are eliminated

Superposition Theorem Replace current sources with opens Replace voltage sources with shorts

Superposition Theorem Circuit may operate at more than one frequency at a time Superposition is the only analysis method that can be used in this case Reactances must be recalculated for each different frequency

Superposition Theorem Diode and transistor circuits will have both dc and ac sources Superposition can still be applied

Superposition Theorem Superposition theorem can be applied only to voltage and current It cannot be used to solve for total power dissipated by an element Power is not a linear quantity Follows a square-law relationship

Superposition for Dependent Sources If controlling element is external to the circuit under consideration Method is the same as for independent sources

Superposition for Dependent Sources Simply remove sources one at a time and solve for desired voltage or current Combine the results

Superposition for Dependent Sources If the dependent source is controlled by an element located in the circuit Analysis is different Dependent source cannot be eliminated

Superposition for Dependent Sources Circuit must be analyzed by considering all effects simultaneously

Thévenin’s Theorem Converts an ac circuit into a single ac voltage source in series with an equivalent impedance First, identify and remove the element or elements across which the equivalent circuit is to be found

Thévenin’s Theorem Label two open terminals Set all sources to zero Replace voltage sources with shorts Current sources with opens

Thévenin’s Theorem Calculate the Thévenin equivalent impedance Replace the sources and determine open-circuit voltage

Thévenin’s Theorem If more than one source is involved Superposition may be used Draw resulting Thévenin equivalent circuit Including the portion removed

Norton’s Theorem Converts an ac network into an equivalent circuit Consists of a single current source and a parallel impedance First, identify and remove the element or elements across which the Norton circuit is to be found

Norton’s Theorem Label the open terminals Set all sources to zero

Norton’s Theorem Determine Norton equivalent impedance Replace sources and calculate short-circuit current

Norton’s Theorem Superposition may be used for multiple sources Draw resulting Norton circuit Including portion removed

Thévenin and Norton Circuits Possible to find Norton equivalent circuit from Thévenin equivalent circuit Use source transformation method ZN = ZTh IN = ETh/ZTh

Thévenin’s and Norton’s Theorems If a circuit contains a dependent source controlled by an element outside the area of interest Previous methods can be used to find the Thévenin or Norton circuit

Thévenin’s and Norton’s Theorems If a circuit contains a dependent source controlled by an element in the circuit Other methods must be used

Thevenin’s and Norton’s Theorems If a circuit has a dependent source controlled by an element in the circuit Use following steps to determine equivalent circuit

Thevenin’s and Norton’s Theorems First Identify and remove branch across equivalent circuit is to be determined Label the open terminals

Thevenin’s and Norton’s Theorems Calculate open-circuit voltage Dependent source cannot be set to zero Its effects must be considered Determine the short-circuit current

Thevenin’s and Norton’s Theorems ZN = ZTh = ETh/IN Draw equivalent circuit, replacing the removed branch

Thevenin’s and Norton’s Theorems A circuit may have more than one independent source It is necessary to determine the open-circuit voltage and short-circuit current due to each independent source

Thevenin’s and Norton’s Theorems Effects of dependent source must be considered simultaneously

Maximum Power Transfer Theorem Delivered to a load when the load impedance is the complex conjugate of the Thévenin or Norton impedance

Maximum Power Transfer Theorem ZTh = 3 + j4 ZL = ZTh* = 3 - j4 ZTh = 10 30° ZL = ZTh* = 10 -30°

Maximum Power Transfer Theorem If the ZL is the complex conjugate of ZTh or ZN

Relative Maximum Power If it is not possible to adjust reactance part of a load A relative maximum power will be delivered Load resistance has a value determined by