Równia pochyła 2 Sylwester Aleksander Kalinowski II LO Elbląg, 2005.

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Równia pochyła 2 Sylwester Aleksander Kalinowski II LO Elbląg, 2005

2. Na równi o kącie nachylenia =30 o położono ciało. Z jakim przyspieszeniem zsuwa się ono wzdłuż tej równi, jeśli współczynnik tarcia tego ciała o podłoże jest =0,15? m v

Q m IUO v 2. Dane: =30 o, =0,15. Szukane: a=?

Q N m IUO v 2. Dane: =30 o, =0,15. Szukane: a=?

Q R N m IUO v 2. Dane: =30 o, =0,15. Szukane: a=?

Q R N F m IUO v 2. Dane: =30 o, =0,15. Szukane: a=?

Q R N F m IUO v 2. Dane: =30 o, =0,15. Szukane: a=?

Q R N F m IUO v 2. Dane: =30 o, =0,15. Szukane: a=?

v Q R N F m IUO 2. Dane: =30 o, =0,15. Szukane: a=?

v Q R N F m IUO 2. Dane: =30 o, =0,15. Szukane: a=?

v Q R N F m IUO 2. Dane: =30 o, =0,15. Szukane: a=?

v Q R N F m IUO T 2. Dane: =30 o, =0,15. Szukane: a=?

v Q R N F m IUO T ma=F-T 2. Dane: =30 o, =0,15. Szukane: a=?

v Q R N F m IUO T ma=F-T F=Qsin =mgsin 2. Dane: =30 o, =0,15. Szukane: a=?

v Q R N F m IUO T ma=F-T F=Qsin =mgsin T= N= R 2. Dane: =30 o, =0,15. Szukane: a=?

v Q R N F m IUO T ma=F-T F=Qsin =mgsin T= N= R R=Qcos mgcos 2. Dane: =30 o, =0,15. Szukane: a=?

v Q R N F m IUO T ma=F-T F=Qsin =mgsin T= N= R R=Qcos mgcos T= mgcos 2. Dane: =30 o, =0,15. Szukane: a=?

v Q R N F m IUO T 2. Dane: =30 o, =0,15. Szukane: a=? ma=F-T F=Qsin =mgsin T= N= R R=Qcos mgcos T= mgcos a=g(sin - cos )