Vertical Alignment CE 2710 Spring 2009 Chris McCahill www.Exchange3D.com.

Slides:



Advertisements
Similar presentations
Ch3: Vertical alignment, p
Advertisements

Geometric Design. Homework Ch 3 # 1,3,7,8,9 Geometric Design Roadway is designed using v, R, e – Need to know the required Stopping Sight Distance for.
Example #4: Designing Superelevation Design the superelevation transitions for a curve with the following parameters: 4-lane divided urban principal arterial.
Sight Distance Sight distance is defined as the length of carriage way that is visible to the driver. The minimum sight distance should be sufficiently.
Wisconsin DOT Facilities Development Manual (FDM)
Geometric Design CEE 320 Anne Goodchild.
Introduction to Transportation Engineering
HORIZONTAL ALIGNMENT Spring 2015.
Road Design Basic Road Design
Geometric Design Session Matakuliah: S0753 – Teknik Jalan Raya Tahun: 2009.
Vertical Alignment CE 5720 Spring 2011 Originally Created by Chris McCahill.
Vertical Alignment See: (Chapter 5 from FHWA’s Flexibility in Highway Design)
Geometric Design & Vertical Alignment
Lec 22, Ch.16, pp : Vertical alignment (objectives) You learned how to lay out a vertical curve, given grades, PVC, PVI, and PVT in CE113 Surveying.
Vertical Alignment CTC 440. Objectives Understand the basics of profiles Understand the basics of vertical curves.
Geometric Design CEE 320 Steve Muench.
Vertical Alignment CE 453 Lecture 20
ECGD4107 Pavement Engineering Summer 2008 Sat. 15:30-18:30 PM K004
Design of Highway Vertical Alignment Chapter 16
SPECIAL TRANSPORTATION STRUCTURES(Notes for Guidance ) Highway Design Procedures/Route Geometric Design/Vertical Alignment/The route in Longitudinal Profile/The.
VERTICAL ALIGNMENT Spring 2015.
CE 515 Railroad Engineering Hump Yard Design Source: Lecture Notes – CE 353 by Reg Souleyrette “Transportation exists to conquer space and time -”
Re-Design Of Nablus-Deir Sharaf Road Prepared by Enas Saleh Haneen Hetti Supervisor Prof.Sameer Abu-Eisheh.
EXAM 2 REVIEW. 1. Drainage problem (25 pts) Below you see a cross-section of a ditch. It runs parallel to a 200-acre field consisting of permanent pasture.
3. 5 Combinations of Horizontal and Vertical Alignment (p ~ p
Exercise 1: Basic Design Criteria 1) Route 17 is a minor arterial and it has a design ADT of Assume rolling terrain. Determine the following information:
CE 578 Highway Traffic Operations Lecture 2 and 3: Vertical Alignment and Sight Distance.
You are designing the vertical alignment of an east-west portion of SR 528 through Marysville. An equal tangent crest vertical curve must go over an.
CEE320 Midterm Exam 10 True/false (20% of points) 4 Short answer (20% of points) 3 Calculations (60% of points) –Homework –In class examples.
Geometric Design of Highways
Course Introduction and Two- Lane Highway Horizontal Alignment Lecture 1: CE 578 Highway Traffic Operations.
Austin, TX N.W. Garrick April 2008 CE 254 Highway Design Project Spring 2008.
Lec 23, Ch.16, pp : Horizontal alignment (objectives)
Applications of Parabolas: Highway Overpasses using Type 1 Vertical Curves John Catlett Mathematics Teacher North Star High School.
Highway Engineering Code No. (CM 304) Lec. 7& 8. Horizontal Alignment.
Geometric design.
Vertical Alignment CE 2710 Spring 2014 Lecture 18 Originally Created by Chris McCahill.
Sight Distances Distance a driver can see ahead at any specific time
Horizontal Alignment See: (Chapter 5 from FHWA’s Flexibility in Highway Design)
Horizontal Alignment.
Section 4 ELEMENTS OF DESIGN Sight Distance and Vertical Alignment
1 Chapter 3: Elements of Design Sight Distances (p.3-1 to 3-18 ) Be able to define and use the stopping sight distance equation Be able to explain the.
Horizontal Alignment CE 453 Lecture 16.
A curve inserted between two lengths of a road or railway which are at different slopes. Vertical curve vertical curve A smooth parabolic curve in the.
Sight Distance CTC 440. Objectives Understand the meanings of “sight distance”and “stopping sight distance” Understand how to determine minimum SSD’s.
Stopping Sight Distance
MD : ATIKUL ISLAM JUNIOR INSTRACTOR DEPT. OF. CIVIL SUB: SURVEYING3 SUB CODE : 6452 MOB:
Introduction to Transportation Engineering Alignment Design Vertical Alignment Instructor Dr. Norman Garrick Hamed Ahangari May 2014.
Geometric Design (I). Learning Objectives To understand the considerations and quantifiable aspects of geometric design.
CE 453 Highway Design Iowa State University Highway Design Criteria Overview April 24, 2006 David R. Dougherty, P.E.
3.4.6 Vertical Curves, p ~ p You learned how to lay out a vertical curve, PVC, PVI, and PVT for given grades in CE113 Surveying and reviewed.
GEOMETRIC DESIGN: HORIZONTAL ALIGNMENT
Geometric Design II CEE 320 Anne Goodchild.
How are Highway Designs Actually Represented in Surface Models for Automated Machine Guidance and How Should We Control Them? Alan Vonderohe Construction.
D=0 D= X D=0 4 Spiral Curve Spiral Curve is a transition curve is sometimes used in horizontal alignment design It is used to.
c.k.pithawalla college of engineering & technology
GEOMETRIC DESIGN: VERTICAL ALIGNMENT
Geometric Design (II).
Introduction to Transportation Engineering
Road Design Civil Engineering and Architecture
Geometric Design.
Importance of Geometric Design
Highway Geometric Design Combination of Vertical and Horizontal Alignment.
Vertical alignment controls how the road follows the existing terrain.
CTC 440 Vertical Alignment
CTC 440 Sight Distance.
Vertical Curves.
Lecture Sight distances.
Vertical Curves.
Vertical Alignment Geometric Design of Railway Track CE 435
Presentation transcript:

Vertical Alignment CE 2710 Spring 2009 Chris McCahill

Components of Highway Design Horizontal Alignment Vertical Alignment Plan View Profile View

Vertical Alignment & Topography Texas DOT

Today’s Class Properties of vertical curves (parabolic) Design of vertical curves

Crest Curve Sag Curve G1G1 G2G2 G3G3 Vertical Alignment - Overview

Parabolic Curves RadiusParabola Horizontal Curve Vertical Curve

Properties of Vertical Curves BVC EVC L G2G2 G1G1 Change in grade: A = G 2 - G 1 where G is expressed as % (positive /, negative \) For a crest curve, A is negative. For a sag curve, A is positive. L/2 PI

Properties of Vertical Curves BVC EVC L G2G2 G1G1 Characterizing the curve: Rate of change of curvature: K = L / |A| Which is a gentler curve - small K or large K? L/2 PI

Properties of Vertical Curves BVC EVC L G2G2 G1G1 L/2 Characterizing the curve: Rate of change of grade: r = (g 2 - g 1 ) / L where, g is expressed as a ratio (positive /, negative \) L is expressed in feet or meters PI

Properties of Vertical Curves BVC EVC PI L G2G2 G1G1 Point elevation (meters or feet): y = y 0 + g 1 x + 1/2 rx 2 where, y 0 = elevation at the BVC (meters or feet) g = grade expressed as a ratio (positive /, negative \) x = horizontal distance from BVC (meters or feet) r = rate of change of grade expressed as ratio (+ sag, - crest) Point T Elevation = y

Properties of Vertical Curves Distance to turning point (high/low point) (x t ): Given y = y 0 + g 1 x + 1/2 rx 2 Slope: dy/dx = g 1 + rx At turning point, dy/dx = 0 0 = g 1 + rx t x t = -(g 1 /r) where, r is negative for crest, positive for sag

Properties of Vertical Curves BVC EVC PI G2G2 G1G1 Example: G 1 = -1% G 2 = +2% Elevation of PI = m Station of EVC = Station of PI = Length of curve? L/2 = 2500 m m = 100 m Sta. BVC = Sta. PI - L/2 Sta. BVC = [24+00] m Sta. BVC = L = 200 m

Properties of Vertical Curves BVC EVC PI G2G2 G1G1 Example: G 1 = -1% G 2 = +2% Elevation of PI = m Station of EVC = Station of PI = r - value? r = (g 2 - g 1 )/L r = ( [-0.01])/200 m r = / meter

Properties of Vertical Curves BVC EVC PI G2G2 G1G1 Example: G 1 = -1% G 2 = +2% Elevation of PI = m Station of EVC = Station of PI = Station of low point? x = -(g 1 /r) x = -([-0.01] / [ /m]) x = m Station = [23+00] m Station 23+67

Properties of Vertical Curves BVC EVC PI G2G2 G1G1 Example: G 1 = -1% G 2 = +2% Elevation of PI = m Station of EVC = Station of PI = Elevation at low point? y = y 0 + g 1 x + 1/2 rx 2 y 0 = Elev. BVC Elev. BVC = Elev. PI - g 1 L/2 Elev. BVC = 125 m - [-0.01][100 m] Elev. BVC = 126 m

Properties of Vertical Curves BVC EVC PI G2G2 G1G1 Example: G 1 = -1% G 2 = +2% Elevation of PI = m Station of EVC = Station of PI = Elevation at low point? y = y 0 + g 1 x + 1/2 rx 2 y = 126 m + [-0.01][66.67 m] + 1/2 [ /m][66.67 m] 2 y = m

Properties of Vertical Curves BVC EVC PI G2G2 G1G1 Example: G 1 = -1% G 2 = +2% Elevation of PI = m Station of EVC = Station of PI = Elevation at station 23+50? y = 126 m + [-0.01][50 m] + 1/2 [ /m][50 m] 2 y = m Elevation at station 24+50? y = 126 m + [-0.01][150 m] + 1/2 [ /m][150 m] 2 y = m

Design of Vertical Curves

Determine the minimum length (or minimum K) for a given design speed. –Sufficient sight distance –Driver comfort –Appearance

Design of Vertical Curves Crest Vertical Curve If sight distance requirements are satisfied then safety, comfort, and appearance will not be a problem. h 1 = height of driver’s eyes, in fth 2 = height of object, in ft

Design of Vertical Curves Crest Vertical Curve Sample Equation: From AASHTO: h 1 ≈ 3.5 ft h 2 ≈ 0.5 ft (stopping sight distance) h 3 ≈ 4.25 ft (passing sight distance)

Design of Vertical Curves Sag Vertical Curve Stopping sight distance not an issue. What are the criteria? –Headlight sight distance –Rider comfort –Drainage –Appearance

Sag Vertical Curve Check also: Comfort –Change in grade, A –Design Speed Appearance –Change in grade, A Design of Vertical Curves

Maximum Grade Context –Rural –Urban Design Speed Terrain –Level –Rolling –Mountainous 0.5% to 3.0%

Maximum Grade Harlech, Gwynedd, UK (G = 34%)

Maximum Grade

Maximum Grade Dee747 at picasaweb.google.com