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Presentation transcript:

FET (Field effect transistor) Two main groups JFET (junction FET) MOSFET (metal-oxide-semiconductor FET) Advantage extremely large input impedance Disadvantages Smaller gain (gm) than bipolar transistor More difficult to analyze

JFET n-channel JFET just a slab of n-type semiconductor !! like transistor, the drain current is controlled by VGS Gate Source Drain I FET Bipolar Gate = base Source = emitter Drain = collector

JFET n-channel JFET PN junction reversed biased

JFET operation VGS=0 Max conducting channel, max drain current ID VT <VGS < 0 pn junction is reverse biased reduce the conducting channel reduce the drain current VGS < VT (Pinch-off voltage) Further reduce VGS until the depletion layer grows so wide that the channel is completely blocked ID=0 VD VS=0 P ID N VT <VG<0 VD VS=0 VG< VT VD VS=0

JFET as a voltage-controlled resistor If VDS is small VGS controls the channel width, and therefore the resistance JFET is a voltage-controlled resistor VG VD VS

JFET as a voltage-controlled current source If VDS is large the drain end is more reversed biased ! The channel is warped Increase VDS => increase depletion => reduce ID But increase VDS => increase ID Net result ID remains constant even VDS is increased A voltage-controlled current source VG= -2V VS=0 VD = 5V P N-channel

Small VDS - linear region (voltage controlled resistor) Saturation region Small VDS - linear region (voltage controlled resistor) Large VDS – saturation region (constant ID, voltage controlled current source) Linear region Small VDS JFET is like a resistor

ID vs VGS (saturation region) IDSS maximum current at VGS=0 (widest channel width, smallest resistance) different FET has different IDSS IDSS VP

ID vs VGS The slope of ID vs VGS (gm) is less steep (not an exponential) smaller gm, not as good as bipolar transistor FET is difficult to analyze Bipolar is easier to analyze because VBE ~ 0.6V VGS can vary over a wide range, usually analyze by graphical method (load-line) The most important advantage Input is connected to an reversed biased pn junction Extremely high input impedance (IG~0)

FET versus bipolar FET is similar to bipolar transistor Voltage-controlled current source bipolar circuits can be used by FET

A simple current source VDS What is VGS? What is ID? The simplest current source ! But we cannot choose the current, as IDSS may vary from transistor to transistor

An adjustable current source Add a resistor RS so as to adjust ID Find by load-line (graphical) method VSG= IDRS VGS= -IDRS

gm of FET Curve approx by a parabola VT

Transconductance gm

k can be found by measuring gm at two points At VGS=0, measure gm (gm is maximum) Find VT (corresponds to gm=0)

Typical value of gm at ID=1mA JFET ~ 2m A/V (from data book) bipolar ~ 40m A/V (by calculation gm=IC /25mV) Gain of bipolar is much higher than FET ! Why use FET? extremely high input impedance almost zero input current good for picking up signal from source that has high source impedance e.g. microphones, input stage of oscilloscope

Source Follower Same as emitter follower Output voltage (VS) follows input (VG) DvG , DiD , DiDRS , DvS

Source Follower AC signal analysis if RSgm >> 1, then DVG ~ DVS => good follower To have large RS, use current source (active load)

Output impedance Fixed gate voltage, what is the output impedance model the gate-source section by a resistor DvOUT / DiD = rS = 1/gm (because DvOUT ~ DVIN) Typical value gm ~ 2m A/V, therefore rS ~ 500W The output impedance of source follower (500W) is much higher than emitter follower (25W)

Matched FET follower The follower is made of matched FET Q2 is a current source at VGS=0 and ID2=IDSS Q1 and Q2 are matched, Since ID1 = ID2 , therefore VGS1= VGS2 = 0V (!) zero DC offset

FET amplifier DvG , DiD , DvOUT = -RDDiD input and output are 180o out of phase, just like bipolar amplifier gain DiD = gmDvGS DvD = -RDDiD = -gmRDDvGS voltage gain = -gmRD same as bipolar amp except gm is smaller

use load-line to find the best R for VGS and ID FET amplifier DC bias VGS = -ID R use load-line to find the best R for VGS and ID R

Hybrid op amp - best of both worlds The tail, large impedance gives high CMRR Push-pull class B amp Mirror as active load. High gain amplifier Follower as buffer

Voltage Regulators Input: unregulated power supply (voltage is quite constant but still has some ripple) Output: regulated (constant) voltage

Voltage Regulator Regulator = Voltage reference + follower unregulated input provides the power zener diode (Vref) provides the voltage reference follower provides the output power and current

Dropout voltage Dropout voltage difference between input and output voltage

Dropout voltage For 723 supply voltage of 9.5V (min) produces 5V output Large 4.5V dropout voltage (not good), waste power also requires too many external components Modern regulators dropout voltage ~ 2-3V Specialized low-dropout regulators dropout voltage ~ a few tenths of a volt

723

78xx family A modern regulator that you would use only need to provide a couple smoothing capacitors

High current output Use parallel transistors to give high output current

Thermal runaway Consider the bipolar transistors different discrete transistor has different IC vs VBE curve if one transistor conducts more current than the other the transistor gets hotter conduct more current !! which makes the transistor hotter still, develops a local hot spot, may eventually break down

Thermal runaway The use of the resistor R in the emitter follower Negative feedback If a transistor gets hot and conducts more current VE is increased, providing a feedback voltage so that VBE is reduced, which reduces the current FET does not have the problem of thermal runaway Because FET has –ve temperature coefficient Increase in temperature reduces output current Really large power amplifiers can be built using MOSFET as the output stage

Switching regulators Regulators powered by microprocessors run at 75%-90% efficiency, more efficient than traditional regulators transformer-less (so that the size is small) but more noisy (high frequency noise) Work by dumping charges into a capacitor via a switch charges stored in the capacitor give a constant voltage

Switching regulators Dump charge to cap

MOSFET (Metal Oxide Semiconductor FET) Any current in the circuit below? No current one end must be reversed biased n n p

MOSFET Basic principle - capacitive effect metal +++++++++++++ - - - - - - - - - - - - - charge

Enhancement MOSFET Add a metal gate Capacitive effect builds up a –ve charge channel that allows electrons to flow metal insulator gate n n - - - - - - source drain p body -ve charge, conducting channel

NMOS (n-channel MOS) when gate voltage is zero, no drain current drain current increases as gate voltage increased

Enhancement mode and depletion mode Enhancement mode operation No gate voltage, no conduction Increase gate voltage increases the conduction JFET Depletion mode no gate voltage, conduction is at its maximum

Enhancement MOSFET - - - - - - - - - if VDS is small VGS controls channel width IDS VDS behaves as a variable resistor Large VDS VDS increase, drain becomes more positive conducting channel becomes less -ve charged to the point that it will almost be vanished Channel is warped Saturation increase in VDS also increase drain current but offset by the reduction in channel Constant ID over a range of VDS 3V 5V - - - - - - - - - 0V warped

With PMOS (p-channel MOS) Works in opposite polarity

MOSFET symbol

Digital circuits Logic gates the fundamental building block of digital electronics AND, OR, NAND, NOR, INVERTER with these gates, one can build adder, shifter, multiplier, logical unit, memory, and microprocessors

NMOS (n-channel MOSFET) inverters Inverter gate NMOS (n-channel MOSFET) inverters Output impedance at OFF state VOUT ON. Channel is conducting, drain is shorted to ground, VOUT = 0 OFF. Channel is non-conducting, ID=0, VOUT = VDD

Drawback of NMOS ON state draw current though R, large static power dissipation OFF state Large output impedance = R Large R gives small output current, which slows the switching speed of the circuit

Problems of NMOS Large RD -> takes longer to charge up Cstray

CMOS inverter (Complementary MOSFET) PMOS + NMOS Input = 0V, Output = 5V for NMOS (bottom one) VGS=0V, OFF (open circuit) for PMOS VG= 0V, VS= 5V VGS= -5V, ON (Short circuit) (5V) VGS = -5V VGS = 0V

CMOS inverter (Complementary MOSFET) PMOS + NMOS Input = 5V, Output = 0V for NMOS (bottom one) VGS=5V, ON (short circuit) for PMOS VGS= 0V, OFF (open circuit) (5V) VGS = 0V VGS = 5V

CMOS Output impedance Either the PMOS or the NMOS is short Zero W , tiny RC, fast switching Static power consumption output = 5V NMOS (bottom) is open circuit, draw no current PMOS is short, draw no voltage Power = VI = 0 output = 0V (same, power=0) ideal for low power applications e.g. mobile phone, notebook PC

Dynamic power dissipation Power consumes when there is a change of state 0 -> 1 or vice versa CMOS draws power when the MOSFET is changing state Both MOSFETs are partially conducting Charging up the stray capacitor of next stage consumes energy

Both MOSFETs are conducting

CMOS - capacitive charging current

Dynamic power dissipation Let the total stray capacitance = C Energy needs to charge up C = Energy needs to discharge C = Total energy needs per cycle = Total energy dissipation per second = High clock rate => hotter and need larger heat sink To reduce power Reduce power supply voltage V Reduce frequency (e.g. asychronous IC)

Why digital circuits use CMOS Extremely small output impedance Zero static power dissipation No change of state, don’t consume power can go all the way to 0V bipolar can only go as low as 0.2V (min VCE) Simpler processing => higher yields, lower costs Smaller size => smaller capacitance => higher speed The main problem is dynamic power dissipation

CMOS NAND gate NAND gate can be used to build all other gates

Non-volatile memory for NMOS and CMOS Add a floating gate Flash memory Non-volatile memory for NMOS and CMOS Add a floating gate A layer of oxide sandwiched between insulators floating gate (layer of oxide) Control gate insulator n n - - - - - - source drain p body

Operation To store logic 1 The oxide layer contains no charge positive voltage at the control gate will turn ON the MOSFET To store logic 0 Apply a high voltage (20V) across the floating gate Breakdown the insulator, electrons trapped in the oxide layer The electrons stored act as a screen, positive voltage at the control gate cannot turn ON the MOSFET (MOSFET is OFF)