University Physics: Mechanics

Slides:



Advertisements
Similar presentations
Chapter 4 The Laws of Motion Force Newton’s Laws Applications Friction.
Advertisements

University Physics: Mechanics
Physics Subject Area Test
Chapter 5 – Force and Motion I
1 Chapter Four Newton's Laws. 2  In this chapter we will consider Newton's three laws of motion.  There is one consistent word in these three laws and.
Dr. Steve Peterson Physics 1025F Mechanics NEWTON’S LAWS Dr. Steve Peterson
Newton’s Second Law The net force on a body is equal to the product of the body’s mass and its acceleration.
Multiple Masses. Tension in Ropes and Cables When a crane exerts a force on one end of a cable, each particle in the cable, exerts an equal force on the.
Ropes and Pulleys.
When a car accelerates forward on a level roadway, which force is responsible for this acceleration? State clearly which.
Newton’s Laws of Motion (Applications)
Chapter 5 Force and Motion (I) Kinematics vs Dynamics.
Physics 101: Lecture 9, Pg 1 Physics 101: Application of Newton's Laws l Review of the different types of forces discussed in Chapter 4: Gravitational,
ELEVATOR PHYSICS.
Newton’s Laws of Motion Problems MC Questions
An Introduction to Statics Unit 3, Presentation 4.
Newton’s Laws Problems
Physics 203 – College Physics I Department of Physics – The Citadel Physics 203 College Physics I Fall 2012 S. A. Yost Chapter 4 Newton’s Laws – Part 3.
AP Physics B Summer Course 年AP物理B暑假班
Newton’s Laws (cont…) Blocks, ramps, pulleys and other problems
I.Newton’s first law. II.Newton’s second law. III.Particular forces: - Gravitational - Gravitational - Weight - Weight - Normal - Normal - Tension - Tension.
Forces & Newton’s Laws of Motion
SECOND LAW OF MOTION If there is a net force acting on an object, the object will have an acceleration and the object’s velocity will change. Newton's.
Foundation year General Physics PHYS 101 Lecture 5 Instructor : Sujood Alazzam 2015/
Applications of Newton’s Laws of Motion
University Physics: Mechanics
PHYS16 – Lecture 10 & 11 Force and Newton’s Laws September 29 and October 1, 2010
Happy Monday Today: Equilibrium Examples HW: POTW #5 (Due Friday in class), WebAssign (Due Friday at Midnight) Tomorrow: Practice w/ Equilibrium Problems.
University Physics: Mechanics Ch6. Friction Lecture 8 Dr.-Ing. Erwin Sitompul
Force Systems accelerate together Combination Systems – connected masses Horizontal Pulley Atwood’s Machine.
1 Some application & Forces of Friction. 2 Example: When two objects of unequal mass are hung vertically over a frictionless pulley of negligible mass,
Newton 2nd Law problems - Atwood Machines -Incline Planes -Tension Problems -Other Object Connected problems.
Physics 111: Mechanics Lecture 4
Force Systems Combination Systems – connected masses Horizontal Pulley
Applications & Examples of Newton’s Laws. Forces are VECTORS!! Newton’s 2 nd Law: ∑F = ma ∑F = VECTOR SUM of all forces on mass m  Need VECTOR addition.
Chapter 5 THE LAWS OF MOTION. Force, net force : Force as that which causes an object to accelerate. The net force acting on an object is defined as.
Aim: More Atwood Machines Answer Key HW 6 Do Now: Draw a free-body diagram for the following frictionless inclined plane: m2m2 m1m1 M θ Mg m2m2 m1m1 M.
Physics 111 Practice Problem Statements 04 Force and Motion I: The Laws of Motion SJ 8th Ed.: Ch. 5.1 – 5.7 Contents: 5-2E, 5-7P, 5-9E, 5-29P*, 5-31P*,
Lecture 9 Serway and Jewett : 5.7, 5.8
University Physics: Mechanics
University Physics: Mechanics Ch5. Newton’s Law of Motion Lecture 7 Dr.-Ing. Erwin Sitompul
Lecture 7 Newton’s Laws and Forces (Cont….)
University Physics: Mechanics Ch5. Newton’s Law of Motion Lecture 7 Dr.-Ing. Erwin Sitompul
Applications & Examples of Newton’s Laws. Forces are VECTORS!! Newton’s 2 nd Law: ∑F = ma ∑F = VECTOR SUM of all forces on mass m  Need VECTOR addition.
University Physics: Mechanics Ch5. Newton’s Laws of Motion Lecture 8 Dr.-Ing. Erwin Sitompul
University Physics: Mechanics
Force is a vector quantity with magnitude & direction. e.g. a ball moves because you exerted a force by. If an object changes velocity, then a acted upon.
An 7.3-kg object rests on the floor of an elevator which is accelerating downward at a rate of 1.0 m/s 2. What is the magnitude of the force the object.
Newton’s Third Law If two objects interact, the force exerted by object 1 on object 2 is equal in magnitude and opposite in direction to the force.
Inclined Plane Problems. Axes for Inclined Planes X axis is parallel to the inclined plane Y axis is perpendicular to the inclined plane Friction force.
PHY 151: Lecture Forces of Friction 5.9 Newton’s Second Law.
University Physics: Mechanics Ch6. Friction, Drag, and Centripetal Force Lecture 9 Dr.-Ing. Erwin Sitompul
Force Problems. A car is traveling at constant velocity with a frictional force of 2000 N acting opposite the motion of the car. The force acting on the.
Solving problems when  F = ma
Force and Motion–I Chapter 5. Newton's First and Second Laws A force: o Is a “push or pull” acting on an object o Causes acceleration We will focus on.
University Physics: Mechanics
University Physics: Mechanics
University Physics: Mechanics
University Physics: Mechanics
Phys 270 Newton’s Laws.
Chapter 5 Force and Motion.
Newton’s Laws: Practice Problems
Last Time: Dynamics: Forces
Frictional Forces.
Chapter 4 Connected Objects.
Newton’s Laws: Practice Problems
University Physics: Mechanics
Chapter 5 – Force and Motion I
A block of mass m resting on a horizontal
Presentation transcript:

University Physics: Mechanics Lecture 7 Ch5. Newton’s Law of Motion University Physics: Mechanics Dr.-Ing. Erwin Sitompul http://zitompul.wordpress.com

Homework 5: Two Boxes and A Pulley A block of mass m1 = 3.7 kg on a frictionless plane inclined at angle θ = 30° is connected by a cord over a massless, frictionless pulley to a second block of mass m2 = 2.3 kg. What are: (a) the magnitude of the acceleration of each block, (b) the direction of the acceleration of the hanging block, and (c) the tension in the cord?

Solution of Homework 5 FN T T a a m1gsinθ m1gcosθ m2g m1g Forces on m1 along the x axis: Forces on m2 along the y axis: What is the meaning of negative sign?

Solution of Homework 5 (a) The magnitude of the acceleration of each block (b) The direction of the acceleration of the hanging block Assumption : The acceleration points upward Result : Negative value Conclusion : The true acceleration points downward Down (c) The tension in the cord

Applying Newton’s Law: Problem 3 A passenger of mass 71.43 kg stands on a platform scale in an elevator cab. We are concerned with the scale reading when the cab is stationary and when it is moving up or down. (a) Find a general solution for the scale reading, whatever the vertical motion of the cab. (b) What does the scale read if the cab is stationary or moving upward at a constant 0.5 m/s? (c) What does the scale read if the cab acceleration upward 3.2 m/s2 and downward at 3.2 m/s2?

Applying Newton’s Law: Problem 3 (a) Find a general solution for the scale reading, whatever the vertical motion of the cab. → The scale reading is equal to FN, which is the force exerted by the surface of the scale towards the passenger (b) What does the scale read if the cab is stationary or moving upward at a constant 0.5 m/s? In stationary condition or when moving upward with a constant velocity, the acceleration of passenger is zero

Applying Newton’s Law: Problem 3 (c) What does the scale read if the cab acceleration upward 3.2 m/s2 and downward at 3.2 m/s2? If the cab accelerates upward, the magnitude of acceleration is positive It the cab accelerates downward, the magnitude of acceleration is negative

Applying Newton’s Law: Problem 3 What does the scale read if, in case accident happens, the cab falls vertically downward?

Applying Newton’s Law: Problem 4 The figure below shows two blocks connected by a cord (of negligible mass) that passes over a frictionless pulley (also of negligible mass). One block has mass m1 = 2.8 kg; the other has mass m2 = 1.3 kg. Determine: (a) the magnitude of the blocks’ acceleration. (b) the tension in the cord. Atwood Machine

Applying Newton’s Law: Problem 4 Mass m1 Mass m2 The acceleration of m1 and m2 have the same magnitude a, oppose in direction. We take the acceleration of m1 as negative (downward) and of m2 as positive (upward). T a T a m1g m2g

Applying Newton’s Law: Problem 4 (a) The magnitude of the blocks’ acceleration What happen if m2 > m1? (b) The tension in the cord

Example: Particle Movement A 2 kg particle moves along an x axis, being propelled by a variable force directed along that axis. Its position is given by x = 3 m + (4 m/s)t + ct2 – (2 m/s3)t3, with x in meters and t in seconds. The factor c is a constant. At t = 3 s, the force on the particle has a magnitude of 36 N and is in the negative direction of the axis. What is c?

Homework 6: The Traffic Light A traffic light weighing 122 N hangs from a cable tied to two other cables fastened to a support, as in the figure below. The upper cables make angles of 37° and 53° with the horizontal. These upper cables are not as strong as the vertical cable and will break if the tension in them exceeds 100N. Will the traffic light remain hanging in this situation, or will one of the cables break?

Homework 6 New 1. What is the net force acting on the ring in the next figure? 2. Joe’s Advertising wishes to hang a sign weighing 750.0 N so that cable A, attached to the store makes a 30.0° angle, as shown in the figure. Cable B is horizontal and attached to and adjoining building. What is the tension in cable B?