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A block of mass m resting on a horizontal

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1 A block of mass m resting on a horizontal
Question 1 03 - C Force and Motion 20023 m m A block of mass m resting on a horizontal frictionless surface is connected to a second block of mass m by a light string which passes over a mass less pulley as shown in the diagram. When released the second block moves downward with a constant acceleration. The acceleration of the second block is A block of mass m resting on a horizontal frictionless surface is connected to a second block of mass m by a light string which passes over a mass less pulley as shown in the diagram. When released the second block moves downward with a constant acceleration. The acceleration of the second block is Solution m T mg

2 Solution... The acceleration of the block m mg m mg 03 - C
Force and Motion 20023 Solution... m A block of mass m resting on a horizontal frictionless surface is connected to a second block of mass m by a light string which passes over a mass less pulley as shown in the diagram. When released the second block moves downward with a constant acceleration. The acceleration of the second block is m mg mg m Solution m T mg

3 Slope of a velocity-time graph represents acceleration (Ex. 011)
Question 2 03 - C Force and Motion 20026 v (m/s) 0.2 0.4 0.6 0.8 1.0 1 2 3 t (s) 3.0 kg v (m/s) 0.2 0.4 0.6 0.8 1.0 1 2 3 t (s) 3.0 kg A block resting on a horizontal surface is connected to a second block by a light string which passes over a mass less pulley as shown in the diagram. The graph represents the speed of the blocks as a function of time when released from rest. The tension in the string during the acceleration is about A block resting on a horizontal surface is connected to a second block by a light string which passes over a mass less pulley as shown in the diagram. The graph represents the speed of the blocks as a function of time when released from rest. The tension in the string during the acceleration is about Solution v (m/s) 0.2 0.4 0.6 0.8 1.0 1 2 3 t (s) 3.0 kg Slope of a velocity-time graph represents acceleration (Ex. 011) mg T

4 Solution... The tension in the string T mg
03 - C Force and Motion 20026 Solution... v (m/s) 0.2 0.4 0.6 0.8 1.0 1 2 3 t (s) 3.0 kg v (m/s) 0.2 0.4 0.6 0.8 1.0 1 2 3 t (s) T 3.0 kg A block resting on a horizontal surface is connected to a second block by a light string which passes over a mass less pulley as shown in the diagram. The graph represents the speed of the blocks as a function of time when released from rest. The tension in the string during the acceleration is about mg Slope of a velocity-time graph represents acceleration Solution v (m/s) 0.2 0.4 0.6 0.8 1.0 1 2 3 t (s) 3.0 kg T mg Slope of a velocity-time graph represents acceleration (Ex. 011)

5 with constant acceleration Block (3m) moves downward
Question 3 03 - C Force and Motion 20031 m 3m m 3m Two blocks are attached to a light string which passes over a frictionless pulley as shown in the diagram. When released the blocks move with accelerations which are equal in magnitude. The tension in the string during the acceleration is Two blocks are attached to a light string which passes over a frictionless pulley as shown in the diagram. When released the blocks move with accelerations which are equal in magnitude. The tension in the string during the acceleration is Solution m 3m mg T Block (m) moves upward with constant acceleration Block (3m) moves downward

6 Solution... The tension in the string 3mg mg m 3m T 3mg mg 3m m 03 - C
Force and Motion 20031 Solution... 3mg mg m 3m m 3m Two blocks are attached to a light string which passes over a frictionless pulley as shown in the diagram. When released the blocks move with accelerations which are equal in magnitude. The tension in the string during the acceleration is m 3m T 3mg mg Solution T T Block (m) moves upward with constant acceleration 3m Block (3m) moves downward with constant acceleration m mg mg

7 Solution... The tension in the string Block (3m) moves downward with T
Force and Motion 20031 Solution... m 3m m 3m Two blocks are attached to a light string which passes over a frictionless pulley as shown in the diagram. When released the blocks move with accelerations which are equal in magnitude. The tension in the string during the acceleration is Block (3m) moves downward with constant acceleration 3mg T Block (m) moves upward with constant acceleration mg T Solution T T Block (m) moves upward with constant acceleration 3m Block (3m) moves downward with constant acceleration m mg mg

8 with constant acceleration Block (2m) moves downward
Question 4 03 - C Force and Motion 20033 m 2m h Two blocks of mass m and 2m are attached to a light string which passes over a frictionless pulley. Mass m is initially resting on the floor as shown in the diagram.When released the blocks move with accelerations which are equal in magnitude. The speed of the blocks when they pass each other is Two blocks of mass m and 2m are attached to a light string which passes over a frictionless pulley. Mass m is initially resting on the floor as shown in the diagram.When released the blocks move with accelerations which are equal in magnitude. The speed of the blocks when they pass each other is m 2m h Solution Block (m) moves upward with constant acceleration m 2m h mg 2mg T Block (2m) moves downward Equate Eq.1 and Eq. 2 The two block pass after block (2m) has fallen a distance of h/2. vo = 0

9 Solution... The speed of the blocks as they pass The two block
Force and Motion 20033 Solution... The two block pass after block (2m) has fallen a distance of h/2. 2mg mg Two blocks of mass m and 2m are attached to a light string which passes over a frictionless pulley. Mass m is initially resting on the floor as shown in the diagram.When released the blocks move with accelerations which are equal in magnitude. The speed of the blocks when they pass each other is m 2m h m 2m 2m h 2mg m mg Solution Block (m) moves upward with constant acceleration m 2m h mg 2mg T The two block pass after block (2m) has fallen a distance of h/2. vo = 0 Block (2m) moves downward with constant acceleration Equate Eq.1 and Eq. 2


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