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Presentation transcript:

Category 5 Category 4 Category 3 Category 2 Category

The number of grams in one mole of carbon… Answer

12 grams From Periodic Table

The number of moles in 24 grams of carbon… Answer!

2 moles of C 24 grams C x 1 mol C = 2 mol of C 12 g C

The volume in L of gas evolved from 2.0 moles of O2 at STP… AnswerAnswer!

44.8 L of O2 2 mol O2 x 22.4 L O2 = 44.8 L 1 mol O2

The number of atoms in 1.4 moles of carbon… AnswerAnswer!

8.43 x 10^(23) atoms 1.4 mol C x (6.02x10^(23) particles) = 8.43x10^(23) 1 mol C

The volume in L of gas evolved from 20 g of O2 at STP… AnswerAnswer!

14 L of O2 20 g O2 x 1 mol O2 x 22.4 L O2 = 14 L 32 g O2 1 mol O2

The number of grams in one mole of sodium… AnswerAnswer!

22.99 grams From Periodic Table

The number of moles in 99 grams of sodium… AnswerAnswer!

4.32 moles Na 99 grams Na x 1 mol = 4.32 mol of Na g

The number of moles in 48 grams of oxygen gas… AnswerAnswer!

1.5 moles O2 48 grams O2 x 1 mol = 1.5 mol of O2 32 g O2

The volume in L of gas evolved from 98 grams of H2O… AnswerAnswer!

L H2O 98 g H2O x 1 mol H2O x 22.4 L H2O = L 18 g H2O 1 mol H2O

The volume in L of gas evolved from 61 grams of CO2… AnswerAnswer!

31.05 L of CO2 61 g CO2 x 1 mol x 22.4 L = L 44 g 1 mol

The number of grams in one mole of calcium… AnswerAnswer!

40.08 grams Ca From Periodic Table!

The volume in L of gas evolved from 2.21 moles of CCl4… AnswerAnswer!

49.5 L of CCl mol CCl4 x 22.4 L = 49.5 L CCl4 1 mol

The number of atoms in moles of calcium… AnswerAnswer!

1.81x10^(21) atoms of Ca mol Ca x (6.02x10^(23) particles) = 1.81 x 10^(21) 1 mol Ca

The volume in L of gas evolved from 2.21 grams of CCl4… AnswerAnswer!

0.322 L of CCl g CCl4 x 1 mol CCl4 x 22.4 L CCl4 = L g 1 mol

The number of atoms found in 24.2 grams of calcium AnswerAnswer!

3.6x10^(23) atoms of Ca 24.2 g Ca x 1 mol Ca x (6.02x10^(23) particles = 3.6 x 10^(23) atoms g Ca 1 mol Ca

The number of grams in one mole of hydrogen gas… AnswerAnswer!

1.008 grams 1 mol H2 x g H2 = g 1 mol H2

The number of moles in 922 grams of bromine gas… AnswerAnswer!

5.76 moles Br2 922 grams Br2 x 1 mol Br2 = 5.76 mol Br g Br2

The volume in L of gas evolved from 0.12 moles of hydrogen gas at STP… AnswerAnswer!

2.688 L H mol H2 x 22.4 L H2 = L 1 mol H2

The volume in L of gas evolved from 66 grams of H2 at STP… AnswerAnswer!

733.3 L H2 66 g H2 x 1 mol H2 x 22.4 L H2 = L g H2 1 mol H2

The number of atoms found in grams of bromine gas… AnswerAnswer!

1.67x10^(21) atoms of Br g Br2 x 1 mol Br2 x (6.02x10^(23) particles = 1.67 x 10^(21) atoms g Br2 1 mol Br2

The number of grams in one mole of lead… AnswerAnswer!

207.2 grams 1 mol Pb x g Pb = g Pb 1 mol Pb

The number of moles in 35 grams of lead… AnswerAnswer!

0.169 mol Pb 35 grams Pb x 1 mol Pb = mol of Pb g Pb

The number of atoms in 9.9x10^(-23) moles of lead… AnswerAnswer!

59.59 atoms of Pb 9.9x10^(-23) mol Pb x (6.02x10^(23) particles) = atoms of Pb 1 mol Pb

The volume in L of gas evolved from 8522 grams of Rn at STP… AnswerAnswer!

859.8 L Rn 8522 g Rn x 1 mol Rn x 22.4 L Rn = L Rn 222 g Rn 1 mol Rn

The number of atoms found in 1.3x10^(-21) grams of lead… AnswerAnswer!

3.78 atoms of Pb 1.3x10^(-21) g x 1 mol x (6.02x10^(23) particles = 3.78 atoms Pb g 1 mol Pb